Galvanized Steel Plank with perforated design for Scaffold CNBM

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20 m.t.
Supply Capability:
3000 m.t./month

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1.Quick Details

  • Model Number: RS-SP

  • Type: Scaffolding Parts, With hook for round tube or U profile

  • Scaffolding Part Type: Scaffolding Planks

  • Material: Steel

  • Surface: Paint/galvanized or to be ordered

  • Loading Capacity: 500kg

  • Standard: EN 12811

Galvanized Steel Plank with perforated design for Scaffold CNBM

2.Packaging & Delivery

Packaging Details:pallet

3.Product Description

Model No: FAS-AP

Model Name: Scaffolding System-Aluminium Platform

1) Dimensions (Lx W ): 2570x610mm, 3070x610mm,
2) Made of Aluminum channel and sheet
3) Used in facade scaffold systems
4) Surface: Aluminum oxygenation

5) With hook for tube and u-profile


Ring   Lock System Scaffold Steel Plank (9.5" wide)






Ring Lock Steel Plank 3050mm (10')




Ring Lock Steel Plank 2440mm (8')




Ring Lock Steel Plank 2130mm (7')




Ring Lock Steel Plank 1830mm (6')




Ring Lock Steel Plank 1520mm (5')




Ring Lock Steel Plank 1220mm (4')




Ring Lock Steel Plank 1150mm (3'10")

6.What is considerations of Scaffolding installation?

There must be a fire protection measures and specialist care, safety personnel patrol inspection when electricity, gas welding work on the scaffold,

(1) scaffold frontage hurtful to prevent falling objects protection is required.

(2) During take down the scaffolding, fencing and warning signs should be set up on the ground, prohibit others person besides the operator

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Q:How to calculate the amount of steel pipe Pay attention to meters as a unit, or tons of units! Thank you
With the number of specifications after each, in accordance with the principle of 260M for a ton See how much the specific need to be able to You said ten layers, not all ten layers of all structures, you can build three layers of three 3m high So you need to use more than 25 high steel pipe, because there are up and down positions Hope to help you, if you still do not understand, you can go to China Building Materials Leasing Network wwwzzzlllcom inquiries
Q:In the scarlet letter why is hester taken to the scaffold in the market-place?
This is where she is punished. People taunt her while she is standing up there. It is to make her feel shame.
Q:Seeking the Responsibility System of Safety Responsibility of Each Function Department
The responsibility system, policies, laws and regulations for the safe production of the production safety departments, and the actual development of the company's safety production, civilized construction and environmental management in line with the actual implementation of the company's safety production responsibility system
Q:How to do a good job in typhoon prevention work in rural areas?
Close the doors and windows, so as not to be strong wind blowing, check and tightly easy to be the wind to the objects, such as windows
Q:significance to Hester viewing the crowd from atop the scaffold in the beginning (ch. 2) of the scarlet letter
maybe because her partner in crime was in the crowd and she didnt give- that takes some big balls
Q:what do you call a place of great significance? such as the scaffold in the Scarlet Letter?
Historical a place with alot of history attached to it Landmarks
Q:What rights do I have as a tenant in regards to the scaffolding outside my window?
explain to your land lord the problems you are facing because of the old windows. i hope he understands you otherwise vacate the house and search for a new one. some companies also insurance for renters.go for it. i hope my answer helps you. all the best!
Q:How to do a good job of typhoon during the mass transfer mobilization work
Such as: all kinds of dangerous housing, plant, shed, temporary buildings (such as walls, etc
Q:Sprinkling water on the construction helps to help reduce haze days
Sprinkling the construction site is an effective means to reduce the construction of dust, you can indirectly less haze days
Q:71.0-kg painter is on a uniform 22.0-kg scaffold supported from above by ropes. How close to the left can he approach safely?
At the threshold of danger, the tension on the far rope reaches zero. (a) Distance from left edge = x; then summing moments about the left rope gives ΣM = 0 = 71.0kg * g * (1m - x) - 22.0kg * g * 2.0m - 6.0kg * g * 1m The g term cancels, and the rest solves to x = 0.296 m ◄ (b) Distance from right edge is X; summing about the right rope, and knowing the g terms will cancel, ΣM = 0 = 22.0kg * 2m + 6.0kg * 3m - 71.0kg * (1m - X) leads to X = 0.127 m ◄ Hope this helps!

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