Q:Will the equipment based on the beam column and other structures, can not be poured once completed, should be set up civil construction or fixed?

The following model for your reference, the project budget is to determine the project cost and work, material consumption of the document, is the basis for assessing the economic investment

Q:Construction technology measures fee is directly into the sub - project costs

Construction technology measures fee is not directly into the sub-project costs, because the construction technology measures fees are measures fees rather than sub-project costs, measures fees, refers to the completion of the project construction, occurred in the construction and construction The cost of non-engineering entity projects during the process consists of construction technical measures and construction organization measures

Q:What is the vertical transport of construction and the high increase in fees

The vertical transportation fee is a special item in the construction industry

Q:What is the exterior scaffolding erection specification? What do you need to pay attention to?

Presumably everyone on the external scaffolding erected norms of the word feel strange, do not know what it is about what is it? Now look at: what is the external walls of scaffolding erection specification: There are several to note: in their daily lives which are needed

Q:A man of mass 60.3 kg stands on a scaffold supported by a vertical rope at each end. The scaffold has a mass of 21.5 kg and is 2.3 m long. Suppose the man stands to the right from the middle of the scaffold that is a distance one sixth of the length of the scaffold. What is the tension in the right rope? Left Rope?Can someone please explain HOW you do this question!? Thanks!

this is a 2d concern. The moments approximately any component interior the gadget could desire to stability, in any different case the gadget (scaffold) might rotate. additionally, the vertical forces could desire to stability, or the gadget (scaffold) might translate. it style of feels to me that to the spectacular from the middle of the scaffold this is a distance one 6th of the dimensions of the scaffold is the comparable as announcing 2-thirds from the left-edge of the scaffold. The moments could be summed approximately any component. i will evaluate the left edge of the scaffold, the place the 2d produced by utilising the left rope is 0. finished M = 0 = scaffold M + guy M + spectacular rope M 0 = 23.7kg*9.8m/s^2*(3.1m/2) + 60.1kg*9.8m/s^2*(2*3.1m/3) - F*3.1m wherein: the scaffold is assumed to be a component mass placed at its middle the tension F acts opposite to the load of the guy and the scaffolding, and subsequently has -ve sign sparkling up for F. To get the tension in the different rope, you may basically evaluate the vertical forces interior the gadget. besides the fact that, you're able to desire to sum the moments approximately another component (say, the spectacular rope). desire this enables.

Q:There is a 6.0-kg pail of paint to one side.How close to the left end can he approach safely? How close to the right end can he approach safely? Can someone help me with this problem, I keep working and reworking it and coming to the same answer. I must be consistently making the same mistake. If someone can help me work through it I would really appreciate it. The answers I got were:Left: dmin, left = .54mRight: dmin, right = .77m

At the threshold of danger, the tension on the far rope reaches zero. (a) Distance from left edge = x; then summing moments about the left rope gives ΣM = 0 = 71.0kg * g * (1m - x) - 22.0kg * g * 2.0m - 6.0kg * g * 1m The g term cancels, and the rest solves to x = 0.296 m ? (b) Distance from right edge is X; summing about the right rope, and knowing the g terms will cancel, ΣM = 0 = 22.0kg * 2m + 6.0kg * 3m - 71.0kg * (1m - X) leads to X = 0.127 m ? Hope this helps!

Q:A 531 N window washer is standing on a scaffold supported by a vertical rope at each end.The sca?old weighs 332 N and is 3.5 m long.Assume the window washer stands 1.36 mfrom the left end.What is the tension in the rope on the right?Answer in units of NWhat is the tension in the rope on the left?Answer in units of N

(332 N)×(3.5 m)/2 + (531 N)×(1.36 m) = (3.5 m)×R R = 372.3 N < - - - - - - - - -tension in the right rope (531 N) + (332 N) = (372.3 N) + L L = 490.7 N < - - - - - - - - - tension in the left rope

Q:Im pretty sure that the 3 characters are Reverend Mr. Wilson, Governer Bellingham, and Mistress Hibbins. The hard part is finding what they represent.

First I would like to acknowledge that this question is from the book: The Scarlet Letter by Nathaniel Hawthorne

Q:Two painters are standing on a 5.0 mg long scaffold. Each painter weighs 833 N. 1 painter is standing 2.0 mg from the left end and 1 is standing .50 mg from the right end. The scaffold weighs 285 N. What is the tension in the 2 cables supporting the scaffold?

Summing torques at the left cable T2*5-833*2-285*2.5-833*4.5=0 T2=1225 N Summing torques at the right cable T1*5-833*3-285*2.5-833*.5=0 T1=726 N Check 833*2+285-(1225+726)=0 It checks j

Q:Also if its possible part B wants to know A ball thrown vertically upward is caught bythe thrower after 2 s.Find the initial velocity of the ball. Theacceleration of gravity is 9.8 m/s2Answer in units of m/sFind the maximum height it reaches.Answer in units of m

Use, Vf = Vo + g * t With Vo = 0 , Vf = g * t = 9.8 m/s^2 * 3.39 s = 33.222 m/s. part B, use the same equation, but take into consideration to watch for direction and adopt a convention. As before we have considered +ve for downward direction. Now Vf = 0 0 = Vo + g * t. Vo = - 9.8 m/s^2 * 2 s = -19.6 m/s . Negative means upward direction according to the adopted convention.