Water Supply Equipment

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Product Description:

<1>Features

1)No need of water pool, saving both fund and energy

2)Simple installation and less used

3)Extensive purpose and strong suitable

4)Full functions and high degree in intelligence

5)Advance product and reliable quality

6)Personalized design, showing a distinctive style

<2>Applications

1)Water supply for city life

2)Fire-fighting system

3)Agricultural irrigation

4)Prinkling & musical foudation

<3>Technical Data

1)Ambient temperature 5~40&ordm; C

2)Relative humidity no higher than 85. C(20+/-5) &ordm; C

3)Liquid temperature 5~70&ordm; C

4)Service voltage 380V(+5%, -10%)

<4>Working Principle

When the equipment is put into movement, the water from the tap-water pipe-net flows into the flow stabilizing can. When the water supply capacity of the pipe-net can meet with the demand of use, the pressure of it is kept with the normal water supply range, the negative-pressure preventing module controlled electric valve is opened and the pump moves to carry out the pressure-overlapped water supply; While the said capacity can not meet with the demand, the pipe-net pressure is lower than that for normal water supply, the said module automatically adjusts the opening of the electric valve till its being closed, at this time water supply by the flow stabilizing can is automatically switched in. The vacuum eliminator on the said can is opened therewith, preventing a negative pressure from being produced inside of the can.

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Q:install recirculating hot water pump?
what your plumber is installing is a pump and temperature sensor under a sink , hopefully the furtherest from the water heater. what it does is sense when the hot water temp drops below a certain point, at which time it pumps the water into the cold line until the temp rises again.. the obvious advantage being , not having to wait a long time at the faucet for the water to get hot.. the also obvious disadvantage being electric consumption.. not only for the pump and controller , but also with the water heater clicking on a little more often.. not a lot of expense but a balance against convenience..
Q:My 1998 GMC Yukon is leaking water out of the tail pipe.?
Water is a normal byproduct of catalytic converter operation. If you are concerned about a possible coolant consumption issue, observe your exhaust for any signs of white smoke emitting. It's highly unlikely that coolant would be able to make it through your exhaust and to the end of the tailpipe, as exhaust temperatures run between the 500-900 degree range. If there are no signs of white smoke, then your vehicle is operating as it's supposed to.
Q:How does an electric motor pump water?
Pump And Motor Works
Q:Will a water pump work?
Be careful what you buy. Most aquarium pumps are AIR pumps. Why not just use a siphon? As long as the storage tank is higher than the generator it will work. Get a hose or plastic tubing of the size you need, put one end in the tank. Suck on the tubing to start flow. To stop flow just pinch off the pipe or raise the spout above the water level. you might even install a valve if the tubing is large enough.
Q:water pump leak headache?
Pay an automotive repair shop to do it. Then it is their problem. Even the best technicians need help once in a while. Yes it costs 3x as much, but no more headache for you.
Q:Is it possible for a water pump in a car to leak for awhile ( days; weeks???) or does?
Water pumps go when the seal around the bearing wears out. The leak starts out slow, but once it starts, there is nothing that can be done for it other than to replace it. The leak does start out slow, and get faster, but it can go from slow to fast in just a few days. Like you notice your car over-heats and needs water, and then a couple days later it needs more, and then you gotta fill it every day, and then like every hour, and then like every five minutes. Once it starts to leak, the water will leak a little slower if the engine is running and the radiator cap is loose, so that it cannot build pressure. But that trick is only good for getting you home, and then to the shop the next day. However, with the radiator cap loose, the water will leak faster if the engine is off. My wife's last car was ruined by severely over-heating, so it is not something you want to mess with. If your car severely over-heats, you will AT LEAST blow the head-gasket. So get it fixed as soon as possible, and in the meantime, carry jugs of water with you.
Q:Integral Problem: Water is pumped out of a holding tank at a rate of 4-4e^-.14t liters/minute?
Water is pumped out of a holding tank at a rate of 4-4e^(-.14t) liters/minute. Lets call that function w(t). So if we integrate w(t) over a time period that will give us the total water removed over that time period. So lets integrate it from t=0 (time when pump started) to t=60 (one hour later): ∫ w(t) from t=0 to t=60 ∫ w(t)=∫ 4-4e^(-.14t)=4t+(4/.14)e^(-.14t) evaluated from 0 to 60 ∫ w(t)=4(60)+(4/.14)e^(-.14*60)-4(0)-(4/.1... ∫ w(t)=211.435 liters removed If the holding tank began at 1000 liters and 211.435 were removed... Remaining water=1000-211.435 ***Remaining water=788.565 liters***
Q:how can i put in a water pump for a1994 bonniville sse?
Simple. Open the trunk. Put the water pump inside. Close the trunk. Drive the car (or have it towed) to your local mechanic and ask him to install it for you. ;^)
Q:Need a new water pump, should i get an electric?
Not sure where your shopping, but I could have sworn water pumps were more than that at least the ones I buy. And yes, I do not buy aftermarket parts since I do not like replacing the same part over over again every month!!!!!!! I would advise you if you do not want to replace the engine down the road for overheating, I would stick with factory water pump leave the electric pump idea alone!!!!! Last time I checked on those, they were more than $50.00 also.
Q:Three phase water pump rated power 4000W, is three-phase working water pump, the voltage is 380V, how to find the three-phase pump current, and calculation of public
Three phase water pump motor rated power 4000W is the output shaft power, divided by the motor efficiency (general 85%) is the input power, which is often mistaken. The electric power is =4000/0.85=4706WRated current = electric power /1.732x, rated voltage x, power factor =4706/1.732x380x0.8=8.94A (assuming power factor 0.8).The above three answers are all wrong.

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