Q:Where the fuse for the fan motorblower located on my 96 bonneville because i bough a new blower motor and its still not working

Probably not the fuse, more like the fan switch or fan resistor. Fuse is with the others...under the dash...driver's side...

Q:I'm trying an experiment, I want to wire a AC or DC motor to a light fixture and manually rotate the shaft which extends from the motor to generate electricity to the light bulb 60W or bigger.Can it be done, If so, Which type motor is recommend? Ac or Dc

Ac motors are not generators unless connected to an existing ac line. Small permanent magnet dc motors as used for models or dynamo from bikes (effectively permanent magnet alternators) or a old car dynamo are the best. Alternators of new cars require dc excitation.

Q:I am planing to send some equipment overseas but I am not sure if there is going to be a problem or not. Here in the u.s., our cycle is 60hz, and where I am going it is 50hz. Please help.

Synchronous speed = 1500 (4-pole machine) i) Slip = (1500-1420)/1500 = 5? % ii) Rotor current frequency = 5? ? 50 /100 = 2? Hz iii) Strictly speaking, motors do not generate power. They supply mechanical power. If you mean that the output (mechanical) power = 1kW at 1420 rpm (=23? rps) then we may write: 1000 = 2.π.n.T or T (the torque) = 1000/(2.π.n) = 1000/(2 ? π ? 23?) = 6.725 Nm.

Q:How to use single-chip microcomputer to control AC motor 65KTYZ, what should be used to control the chip? Please give expert advice. It is better to give access to each interface.

With two relays (or IGBT what) do isolation, change any of the two lines after the state of the line on the line. For example, when the A-C-B is turned on, the A-B-C is switched on, and if it is reversed, the drive relay (or IGBT) becomes a reverse.

Q:Hey guys, my AC tries to start outside it seems, but then i hear a big BEENG sound for like 4 seconds (as if the AC tries to start). Then it stops. I have a digital thermostat and its showing all 8888. I tried to stop the circuit breaker and restart it to no avail. It's the unit outside that seems to be the problem.ANy clue what's going on here and how much it will take to fix it?

It appears like a situation with the burden on the motor to me. The Cap is barely for beginning,you ought to have a initiate winding going undesirable or something is preserving the motor back at startup, or centirfigal change that cuts out Cap is improper.

Q:What is it?

The resistors act as a load to absorb the power from an AC motor that is acting as a generator. Assume that the frequency of the power applied to an AC motor is reduced at a rate that requires the motor speed to decrease at a faster rate than it would slow down if power were to be removed. In order to force the load to turn at the slower speed demanded by the frequency reduction, the motor produces negative torque, torque that is applied as a braking force rather than a driving force. During braking, the load is driving the motor and the motor acts as a generator. The motor produces a voltage that exceeds the voltage produced by the AC drive. That voltage would tend to charge the capacitors in the drive to an excessive voltage. Circuitry in the drive detects the voltage increase and/or the current reversal and connects braking resistors to draw a compensating current and dissipate the energy produced by the motor.

Q:whats are elecrtric motors and where can they be used?? and how

AC motors which usually range from 110v to 4160 volts and higher are used for tones of jobs...from pumping..grinders..moving machinery..moving roller racks.. ducing electricity...etc..they also come in multiple speeds...also used for gear reducers....there are single phase....three phase...slip ring motors...variable speed motors...variable HP motors...repulsion induction motors..brake motors..and on and on DC..they are also used for varies purposes..as drive motors...shunt wound and compound wound...to drive locomotives..run various machines that require various speeds...they can also be used to produce DC electric..like generators..again i can go on and on i spent 35 yrs repairing and rewinding both AC and DC motors..i could wqrite you a small book on electric motors

Q:AC motor stator winding does not turn, why the back EMF?

The principle of an electric motor can be understood in junior high school. It is a device that transforms electrical energy into mechanical energy. The energized coil is subjected to a magnetic field to its ampere force in the magnetic field, causing the coil to rotate around the shaft. Ampere force is the power source of coil rotation. If we see only the power of the ampere force, the coil of the motor will continue to accelerate, which is obviously impossible because each motor has a maximum speed.

Q:I sucked at physics in undergrad and I suck at physics even more now. Thanks.

We'll need more information. Technically 50 kg is a mass and you're trying to overcome a force. If you put the object on a scale and the scale read 50 kg, the scale was converting the 50 kg mass into Newtons on the earth's surface and expressing the result (wrongly) in kg. Remember F = ma? F in Newtons = mass (in kg) x acceleration (in m/s?) on earth, a = 9.81 m/s?, so a 50 kg mass exerts a force of 9.81 x 50 = 490.5 Newtons Now we'll need to know how rapidly you want to lift this mass. The formula for motor horsepower is Power (in HP) = 0.7457 (Horsepower per Kilowatt) x Torque (in Newton-meters) x 2π x rotational speed (in rpm) / 60 (seconds per minute) / 1000 (watts / kilowatt) This gives you shaft power output. Because of the motor's ineffiecencies, you will need to apply between 25% and 33% more input power than you expect to extract. If you attach the cable directly to a 6 diameter drum and the cable is lifting a 50 kg mass, the torque on the shaft is 490N x 3 inches (the pully radius) x 0.0254 (meters per inch) = 37.33 Newton-meters The shaft output power for a typical 1760 rpm electric motor will be HP = 0.7457 x 37.33 x 2π x 1760 / 60,000 = 7.01 You'll need a motor rated at about 10 HP to do this job. You will also want to consider stepping down the speed, which will decrease the efficiency of the system considerably but will also reduce the speed the cable is wound onto the pully (in this example it's at 46 feet per second or about 30 miles per hour). If you use a step-down gear to reduce the take-up speed to 1 foot per second, the rotational speed drops to about 38 rpm and the shaft horsepower drops to 0.15 HP. Of course the gearing introduces a great deal more inefficiency and the resulting rated horsepower of the motor might have to be as much as 3 times the calculated output. You would be looking at a 1/2 or 3/4 HP motor.

Q:Im trying to make tattoo gun what would be a better motor 18volt ac or 18 volt dc?

DC because it's safer. If you don't know what you are doing you could kill someone with ac, even at 18 volts.