Hot Dip Galvanized Iron Wires

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Diatmeters:0.15mm-6mm

Application	Weaving, braiding, fencing, cable armoring, knitting, tie wire, for redrawn, for binding or forming etc.
Material	low carbon steel wire
Diameter	0.15mm~6.00mm
Tensile strength	350-500MPA, or higher
Zinc coating	Min 12g/m2, min 25g/m2, min 200g/m2,min 300g/m2,610g/m2
Surface treatment	Hot dipped or electro galvanized
Packing	On spools In small coils of 25-50kg/coil, 10kg/coil In rosette coil of 100-800kg/coil
Standard	ASTM 641, EN10257-1& EN10244-2

All can be produced according to customers’ requirements.

Q: How can I repair an enamel coated headphone wire? In other words, how can an enamel coated wire be reconnected; i.e. how is the enamel coating stripped off, and what can I use to recoat it so that it won't short?: Strip off the coating to expose bare metal where you would to slice (reconnect) new wires. Twist them or soldier them together. The wires will not short unless they come in contact with electricity-conducting materials, including human flesh. Hardware stores sells paint just for wires, but you don't have to go such extremes. Just put some tape it or cover it with any other non-conductive materials.

Q: 2 long striaght wires (20m each) ,each having a 1.0A current going up.The distance between the two wires is 1.0m(a) what is the magnetic field (magnitude and direction) at a point o.50m left of the wire 1?(b)what is the magnetic field (magnitude and direction) at a point 0.6m right of Wire 1?: Assuming Wire 2 is to the right of Wire 1: a) Bwire1 = (u*I)/(2*pi*r) = ((4*pi*10^-7)*1A)/(2*pi*0.5) = 0.000004 Bwire2 = 0.000000424 Btotal = 0.000004424 (away from wire 1) b) Bwire1 = 0.000003333 Bwire2 = 0.000005 Btotal = -0.0000017 (toward Wire 1)

Q: I bought these speakers and I was wondering what kind of wiring do I need to get to wire them to the amp?: Wire okorder /Product/Product.as...

Q: What's the thickness, or measurement for the last or thickest wire?: they change your wire according to how much your teeth have shifted around, so it just depends. the ortho needs to adjust the size of the wire due to your teeth straightening out and making sure the wire(s) are at a correct length. its really not that thick of a wire, so don't worry about it. :D

Q: What exactly is 6 AWG stranded grounding wire usually used for?: In a nutshell: a) Verify that your service drop has the capacity for the additional load - verify this with your utility. b) If you are planning to install a 200A service in the barn, and you are planning to bury the wire, you will need to use 3-0 wire in a conduit. Use separate conductors. Check with your local electrical inspector, but I do not believe you will need to run a separate ground within the conduit for this application. The code may have changed, however. c) You will need to install a 200A fused safety-switch at the pole, and a new 200A panel in the barn. d) The barn panel will also have a 200A main disconnect breaker in it. e) You will need to install an additional ground-rod (or rods) at the barn panel. 1. DO NOT use old/used wire. 2. Consider running triplex wire overhead as it will be less expensive and equally effective. 3. Get the work inspected by an underwriter - your fire insurance will be voided if you do not. Lastly, it is not rocket science, but the codes and standards that apply are there for a reason - follow them carefully and fully and you will be fine.

Q: I am trying to run a wire from a breaker box to a new plug. To get to the new plug, I have to run the wire over a garage with a finished ceiling, around, through, or over 2 half staircases ( bi level) to get to the unfinished wall to run to the new plug. What would be the proper way to run this wire.: YOU CAN USE 100 AMP WIRE ONLY IF IT HAS A BREAKER AT THE POLE BOX FOR 100 AMPS

Q: A 41.7-kg sign is suspended by two wires, as the drawing shows. Wire 1 makes and angle of 42.2deg with the horizontal and wire 2 makes an angle of 58.8deg. Find the tension in wire 1 and wire 2.: To solve this, you have to find 2 equations, because there are 2 unknowns. Assume, Tension in wire 1 = T1 Vertical component of T1 = T1 sin42.2 Horizontal component of T1 = T1 cos42.2 Tension in wire 2 = T2 Vertical component of T2 = T2 sin58.8 Horizontal component of T2 = T2 cos58.8 Since the sign board is in equilibrium, the forces must balance each other. Horizontally, the horizontal components of both forces are balancing each other. Therefore, T2 cos58.8 = T1 cos42.2 T2 = (T1 cos42.2) / (cos58.8) -------------------(1) For the vertical components of the wire, both are balancing the weight of the sign. T1 sin42.2 + T2 sin58.8 = (41.7)(9.8) T1 sin42.2 + T2 sin58.8 = 408.66N ----------------(2) Combine (1) into (2), T1 sin42.2 + (T1 cos42.2)(sin58.8) / (cos58.8) = 408.66 T1 ( sin 42.2 + cos 42.2 tan 58.8) = 408.66 T1 = 215.66N Subst T1 = 215.66N into (1), T2 = (T1 cos42.2) / (cos58.8) = 308.4N Hope it is correct ^^

Q: I attempted to change a bathroom fan to a new one with the help of a friend. He disconnected all the wiring without paying attention to what he was doing and what was wired where. We have a set of wires coming from somewhere (I presume the fuse box) to the fan that is hot regardless of the switch being on or off. That has a black, white and naked wire in it. Then we have another wire that comes from the switch that has black, white and naked as well. The fan has black, white and green. Can someone please tell me how to connect these as we have tried everything and the only thing that works is wired to the constant hot which of course won't allow us to turn the fan off with the switch...: You need to pull your wall switch to see how it is wired. I suspect the original wiring used the black and white on the switch itself which would make the white actually black or hot instead of neutral. If on one side of the wall switch the black wire is wired and the other the white then you need to wire the black from the fuse panel to the black going to the switch. Then the white coming from the switch to the black on the fan. The white on the fuse panel wire would be wired to the white from the fan and all grounds(bare and green) wire together.

Q: i just got two new aiwa stereo speaker's they come with their own wiring in the back but i dont know which wire is whatthere is one black wireand there is another black with gray dashesim thinking the one with dashes is positive?the speaker works both ways: Chances are the marked wire is positive. For your purposes it doesn't matter a whole lot. The phasing (which DOES matter) will be correct as long as you are consistent with both speakers. If you can remove the front grill or otherwise see the speaker cone directly, you can check the polarity with a AA or other 1-1/2 volt battery. The cone will move forward when the positive wire is *briefly* touched to the positive terminal of the battery while the negative wire is held on the negative terminal. If you see it move back, you've connected the wires in reverse. Don

Q: This is the typical Physics problem with the wire and boom connected to a wall with a mass hanging on the end of the wire.Does the tension in the wire increase or decrease when the wire is connected higher on the wall (meaning the angle between the wire and the boom increases).: Assuming the boom is free to pivot at the wall, and a massless wire, the tension in the wire decreases as the attachment point is moved further up the wall away from the boom. There is a constant vertical force (the weight of the boom and the mass attached to its end) that is a constant component of the tension in the wire. The tension must increase to maintain this constant upward force as the wire approaches the pivot point, because the vertical component of tension is the tension multiplied by the sine of the angle between the wire and the boom. As the angle approaches zero, the tension required to support the boom approaches infinity. Conversely, as you move the end of the wire higher up on the wall, the tension decreases, approaching the combined weight of the boom and the suspended mass as the wire approaches being parallel with the wall. So imagine a sign attached to the side of a skyscraper at street level supported by a wire extending to the top of the building. There will be almost no horizontal component to the tension in the wire and the vertical component will just be the sum of the weight of the wire, the boom, and the attached mass.

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