High Quality Steel-Cored Aluminum Strand

High Quality Steel-Cored Aluminum Strand

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Loading Port:: China Main Port

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Quick Details

Place of Origin:	Henan China (Mainland)	Application:	Overhead	Model Number:	ACSR
Conductor Material:	Aluminum	Insulation Material:	NO	Jacket:	NO
Number of Conductors:	seven			steel core ACSR:	circle aerial conductors

Packaging & Delivery

Packaging Detail:	Wooden drum or Iiron wooden drum or according to customer's requirements Delivery Detail 7 days

Specifications

ACSR cable,
good quality and price
fast delivery
best seller

Nominal Area (mm2)	Stranding Wire No. and Dia. (No./mm)		Calculated Area (mm2)			Approx. Overall Dia.(mm)	Approx. Weight (kg/km)	Calculated Min. Resistance Load(KN)	Calculated DC Resistance at 20°C (Ω/km)	Code Name
Nominal Area (mm2)	Al.	St.	Al.	St.	Total.	Approx. Overall Dia.(mm)	Approx. Weight (kg/km)	Calculated Min. Resistance Load(KN)	Calculated DC Resistance at 20°C (Ω/km)	Code Name
20	6/2.11	1/2.11	20.98	3.50	24.48	6.33	84.85	7.90	1.368	Squirrel
25	6/2.36	1/2.36	26.24	4.37	30.62	7.08	106.10	9.61	1.0930	Gopher
30	6/2.59	1/2.59	31.61	5.27	36.88	7.77	127.80	11.45	0.9077	Weasel
40	6/3.00	1/3.00	42.41	7.07	49.48	9.00	171.50	15.20	0.6766	Ferret
50	6/3.35	1/3.35	52.88	8.81	61.07	10.05	213.80	18.35	0.5426	Rabbit
60	6/3.66	1/3.66	63.12	10.52	73.64	10.98	255.30	21.77	0.4546	Mink
60	12/2.59	7/2.59	63.23	36.88	100.10	12.95	463.60	52.94	0.4566	Skunk
70	12/2.79	7/2.79	73.37	42.80	116.20	13.95	538.10	61.20	0.3936	Horse
70	6/4.09	1/4.09	78.84	13.14	91.98	12.27	318.90	27.05	0.3639	Raccoon
100	6/4.72	7/1.57	105.00	113.55	118.50	14.15	394.30	32.70	0.2733	Dog
150	30/2.59	7/2.59	158.10	36.88	194.90	18.13	725.70	69.20	0.1828	Wolf
150	18/3.35	1/3.35	158.70	8.81	167.50	16.75	505.70	35.70	0.18158	Dingo
175	30/2.79	7/2.79	183.40	42.80	226.20	19.53	842.40	79.80	0.1576	Lynx
175	18/3.61	1/3.61	184.30	10.24	194.50	18.05	587.60	41.10	0.1563	Caracal
200	30/3.00	7/3.00	212.10	49.48	261.50	21.00	973.860	92.25	0.1363	Panther
200	18/3.86	1/3.86	210.60	11.70	222.30	19.30	671.40	46.55	0.1367	Jaguar
250	30/3.35	7/3.35	264.40	61.70	326.10	23.45	1214.00	111.40	0.1093	Bear
300	30/3.71	7/3.71	324.30	75.67	400.00	25.97	1489.00	135.70	0.08912	Goat
300	18/4.78	7/1.68	323.10	15.52	338.60	24.16	1012.00	69.64	0.08914	Batang
350	54/3.00	7/3.00	281.70	49.48	431.20	27.00	1443.00	120.70	0.07572	Bison
400	54/3.18	7/3.18	428.90	55.59	484.50	28.62	1022.00	131.90	0.06741	Zebra
450	30/4.05	7/4.50	447.00	111.30	588.30	31.50	2190.00	198.30	0.06057	Elk
450	54/3.35	7/3.35	476.00	61.70	537.30	30.15	1800.00	146.20	0.06074	Camel

Q: I've had my subs wired up for a while but want to see if there is a more efficient way to do it. Hardware: Sony Xplod 800w amp bridgeable amp - What's the best way to wire these up to get the most volume?: wire the voice coils to series on each sub and then wire the subs in parallel to the amp and voila.

Q: I have two DVC subs and I know how to wire them down to 1 ohm with the wires coming out of one outlet on the box but I don't know how to wire them down to 1 ohm with wires coming out of both sides of the box. Anyone have a wiring diagram for this?: For okorder /... On the inside of the enclosure, connect both positives and both negatives to the enclosure inside terminal. That makes each side of the enclosure 2 ohms. Mount and screw in the subs. Now, on the outside: 1) Observing polarity, run short jumpers between the terminals (positive to positive, negative to negative) and then connect ONE set of terminals to the amp (again observing polarity) (positive to positive, negative to negative. 2) Run separate wires from each set of terminals to the amp, observing polarity. That makes the final impedance to the amp 1 ohm.

Q: So I need to tap a few wires, and cut 1 wire and join it with another wire..What would be the best way to approach this? Here are the full instructions so you guys have an idea on what I'm trying to do.quot;On the TAN plug there is 1 ALL PINK(E7) wire you need attach the WHITE wire from your relay to that but don't cut the PINK wire just tap the WHITE into it.Next go the the GREY BCM plug there are 3 WHITE wires.: The instructions seem pretty straight-forward. T-Taps and squeeze-connectors are basically the same thing; achieving the same results, which is to add a connection to an existing wire without interrupting the line. Just make sure you use the right size and type, meaning; don't use a low-voltage connector for a high-voltage application... You'd just fry it up. For the cut wires, I'd use crimp-connectors and some shrink-wrap. Again, using the correct connector. You can use wire-nuts, but the crimp-connectors are a more permanent fix. Good luck to ya.

Q: When was the hot-wire anemometer invented? and who was it?: Sir Charles Wheatstone in 1843 modern anemometer use ultrasound hot wire sensors are used as mass air flow but did not find original usage! Guru

Q: the plug only has room for black,red,ground wire.. what do i do with the white wire: If you have a dryer with a 3 prong cord you can combine the ground and white. Has been done for many decades if you use an older dryer.

Q: THERMOSTAT WIRING: What Sickwillie said.

Q: i just got guitar hero 3 and i want to buy another guitar contoller for the xbox 360 but my mom only wants to buy the wired one because it is cheaper is there anything wrong with the wired one and should i get it or not since i will be playing it with my brother. also how long will the wire be.: There's nothing wrong with the wired controller, but once you get used to the wireless one, the wired one feels a little bit weird. The wireless one has smooth fret buttons that feel nice, and the strum bar doesn't click as much. Also the body is thinner and smaller, making is more comfortable. The wire for the wired controller is 8 feet I believe.

Q: electrical wire prices: everything does to some degree cos of the oil used in production packaging and transportation, and because wire is used in massive quantities in industry the companys selling it would lose out if they didnt increase there costs immediatly.

Q: Why does a thin wire melt and a thick wire glow when put up to the terminals? Explain in terms of resistance and current. Thanks=]: the electrical restistance of a thin wire is greater that the tick wire. thus : Watt = current * current * resistance if the resistance of the thick wire is 10 times the resistcance of the thin wire , then ( with same voltage ) you have for small wire Watt = current * current * resistance for thick wire Watt = 10*current * 10*current * (resistance/10) = 10current current resistance. so the power generated in the thick wire is ten times more than the power in the thin wire ( if you keep the voltage the same ) so that is not why the smaller one melts. I dont know why it melts then, interesting

Q: Say you have a 5 cm current wire carrying 10 A going from left to right. Directly 1 c.m below the left end of this wire is a long wire that is perpendicular to the first wire and goes out of the page. What is the net force on the 5 cm wire?I've tried using F=ILB with the I of the first wire and the B of the second wire.: I didn't read the question so I was carefully working out the force. The wire is perpendicular to the first wire, so using the right hand rule you discover that the field it creates is PARALLEL to the first wire at this left end. The magnetic force is caused by the component which is PERPENDICULAR to the wire which is in fact zero. So there is no magnetic force at this point. As you move along the wire you get a diminishing amount of magnetism caused by the wire which is going out of the page but that field has a component which is DOWN the page. Therefore that part of the wire experiences a force which is into the page. ( take your right hand, put the thumb along the wire pointing to the right, the fingers point down the page, the palm points into the page which is then the direction of the force) I would be surprised if you were required to work out the magnitude of the force in this context. You can't use F= ILB because both the magnitude and the direction of the field varies at different points along the wire. If the perpendicular wire had been directly below the middle of the other wire there would have been no net force. If you were of a level where working out the force was appropriate you would need to set up the formula for B at various points along the wire, taking the vertical component only and integrate this over the range from 0 to 5 cm. Not a trivial mathematical task.

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