Solar Panel Solar Module PV Solar With A Grade 180W

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1 watt
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10000000 watt/month

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Item specifice:

Material: Polycrystalline Silicon Max. Power(W): 180 Number of Cells(pieces): 32

Product Description:

Solar panel material

1. glass

 Its main role is to protect the power generation ( solar cells ) , there is a selection of light transmittance requirements : 1 ) must be high transmittance (typically 91% or more ) ; 2 ) super white steel processing.


2. EVA

 For bonding glass and power generation fixed body ( such as cells ) , transparent EVA material directly affect the life of components exposed to the air EVA prone aging yellow , thus affecting the transmittance components , thus affecting in addition to generating the quality of the components itself, the quality EVA lamination process on the component manufacturers is also very large, such as EVA plastic viscosity of non-compliance , EVA and glass, back bonding strength is not enough, can cause premature aging EVA, the affected component life.


3. Solar cells

 The main role is to generate electricity , the electricity is the main market mainstream film crystalline silicon solar cells , thin-film solar cells , both have their advantages and disadvantages . Crystalline silicon solar cells , the equipment costs are relatively low , but the high cost of consumption and cells , photoelectric conversion efficiency is high, the next generation in outdoor sunlight is more appropriate ; higher thin-film solar cells , the relative cost of equipment , but the cost of consumption and battery low, relatively low photoelectric conversion efficiency of crystalline silicon solar cells , but the effect is very good low-light , in the ordinary light can also generate electricity , such as solar calculator .


4. backplane

 Sealing, insulation , water ( usually with TPT, TPE , etc. ) the material must be resistant to aging , component manufacturers generally have warranty for 25 years , tempered glass, aluminum is generally no problem , the key lies in whether the backplane and can meet the requirements of silica gel.

Solar Panel Solar Module PV Solar With A Grade 180W


- High effi ciency, multicrystalline silicon solar cells with high transmission and textured glass deliver a module effi ciency of up to 16.0%,

minimizing installation costs and maximizing the kWh output of your system per unit area.

- Tight positive power tolerance of 0W to +5W ensures you receive modules at or above nameplate power and contributes to minimizing

module mismatch losses leading to improved system yield.

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Q:Can someone tell me about solar panels for homes?
Q:Question about Solar Power and Wind Power?
Q:How many Solar Panels do I need?
Everyday I use ,280 kWh 280 kW-hour / 24 hours = 470 kW WOW, that is a very high power level, most homes use an average of .2 kW. My guess is that you mean you use 280 kW-hour in a year, which comes to an average power of .3 kW, typical. Assuming you get, worse case, 6 hours of sun per day, for the first case, 470 kW, each solar panel generates the equivalent of 250 x6/24 = 60 watts, so you would need 470k/60 = 8000 panels For the second case, .3 kw or 300 watts, divided by 60 that is about 20 panels. Depending on where you live, you could need as much as twice that number. Plus you need charge controller, lots of expensive batteries, and an inverter. The big problem is periods of no sun. If you demand continuous power, and you have a period of, say, 24 hours with no sun because of storms, etc, then the number of batteries increases to the hundreds.
Q:What solar panel do I need?
The correct answer depends on how much total energy you use during the day and whether or not your utility allows something called net-metering. In net-metering, if you make more power during daylight hours than you consume, the meter goes backwards. Then at night the meter goes forward again. With net-metering you only pay for the difference.
Q:What are your opinions on solar energy?
It is definitely worth doing your homework to evaluate how much you electricity you want to obtain, what you location will allow, and the availability of state and federal tax credits. I suggest reading about it in a book or e-book. Check out the referenced source on solar calculator for cost and size detailed information, it's fun and informative.
Q:Information Regarding Solar Panels?
366 W/square meter on March 2 and tweaked based on lattitude eff = W out/Sun W in there are special heat meters to measure W in ======== IEC 62688 Certification; and UL cert in USA
Q:What can a watt solar panel power?
If it's sunny and you have 500 of them, you can almost power a hair dryer... Look at the WATTS.... 40 of those panels can power one crappy light...
Q:What equation would i need to determine the raise in temperature of water going through a thermal solar panel?
If you only use it for demonstrational . 75W-00W small solar panels would be that you are looking for, you can use it heat up the water. With simple guide you can do it yourself easily and cheaply.
Q:how to store energy from solar panels?
Now days there are been many equipement in the market such as solar panels is one such device which helps to generate solar energy.
Q:How many LED's can power a solar panel?
The 40 kmcd rating is a measure of luminous intensity (how bright it looks), not a measure of output power of the visible light. We can estimate the performance of your proposed system as follows: The LEDs on OKorder each are rated about 20mA maximum at about 3.2V, or 64mW (milliwatts). If you use 470 ohm resistors connected to 2VDC, the current that will flow, per LED, will be about: (2V-3.2V)/470ohm = 0.0872A = 8.72mA The power taken from the 2VDC power source will be: P2v = 2V x 8.72mA = 224.6mW (per LED) The power input to each LED will be about: Pled = 3.2V x 8.72mA = 59.9mW (per LED) The LED has a luminous efficiency that can range from about 4.2% to 22%. This efficiency is the ratio of the amount of visible light output (in watts) divided by the input power (in watts). The OKorder listing doesn't identify the output power level (either in watts or in lumens), so let's assume a 0% efficiency. The LED output power will be about: Pout = 59.9mW x 0% = 5.99mW (per LED) A solar panel converts visible light to electrical energy with an efficiency that ranges say about 6% to 8%. Suppose the solar panel efficiency is 2%. Then the electrical power output by the panel will be about : Pe = 5.99mW x 2% = 0.72mW (per LED) If you shine 00 LEDs on the panel, the output electrical power will be 00 times that amount: Pe00 = 0.72mW/LED x 00 LED = 72mW <===ANSWER The power taken from your 2V source will be about: P2V00 = 224.6mW/LED x 00 LED = 22460mW = 22.46W The system efficiency will be about: Eff = solar output / battery input = Pe00 / P2V00 = 72mW / 22460mW x 00% = 0.32% SUMMARY: If you shine 00 of the LEDs on the panel, you will capture back about 0.32% of the energy expended, or regain about 72mW.

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