• SMD Multilayer Ferrite Chip Bead System 1
SMD Multilayer Ferrite Chip Bead

SMD Multilayer Ferrite Chip Bead

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low frequency Inductor/filter

1.SMD multilayer ferrite chip bead

2.Low Crosstalk/DCR Features

3.competitive price

4.by customer's requests

 

Features:

1.Low crosstalk/DCR, high reliability

2.Low crosstalk between adjacent circuits

3.Single MZA series chip provides noise attenuation for four lines, ideal for various highly miniaturized I/D lines

4.Internal electrodes feature low DC resistance, minimizing wasteful power consumption

5.Electroplated terminal electrodes accommodate flow and reflow soldering

6.Monolithic structure ensures high reliability

7.Operating temperature range: from -25 to 85 degree Celsius

 

Applications:

1.High-frequency noise counter measured in computer

2.Printers

3.Portable telephones and other equipments

4.VCRs

5.Televisions

 

 

Q:A 4-mH inductor is connected to an ac voltage source of 151.0 V rms. If the rms circuit is .820 A, what is the frequency of the source?This is NON-Calculus based Physics! Please Help! Thx!
I V/XL XL V/I 151/0.820 184Ω Now XL 2π*f*L f XL/(2π*L) 184/(2π*4x10^-3) 7330Hz
Q:A 42.8-?F capacitor is connected across a 57.0-Hz generator. An inductor is then connected in parallel with the capacitor. What is the value of the inductance if the rms currents in the inductor and capacitor are equal?I have the equations Xc1/2(pi)fC for Capacitive reactance and I have XL2(pi)fL for Inductive reactance but I do not know how to relate the two equants for this problem.
To solve you need two additional equations, Vrms Irms*XL and Vrms Irms*Xc. (I being current) According to the question your currents are equal, so solve for Irms for the two provided equations using your values for Xc and Xl (L is the only value you do not have), then set them equal to each other. Vrms / (2 * pi * f * L) Vrms (2 * pi * f * c), solve for L which cancels your Vrms leaving you with L 1/ ((2 * pi * f)^2 * C)
Q:Hello! I am a college student who wants to get extra credit in my Electronics class (I need it desperately).I heard that in some circuits you can replace a capacitor with an inductor, so I wanted to do a experiement:-Build a standard common emmitter circuit with a capacitor-Build another common emmitter circuit with a equivalent inductor-Compare and contrast the responseI did a google search on how to replace a inductor with a capacitor in a circuit, but to no avail. I haven't found anything.Do any of you brilliant engineers know about this circuit technique? Can you direct me to more information on how to do this?Thanks!
I believe that the substitution is real, but not literal - for example in op amp filters a feedback inductor is the same as a feed in capacitor, and so on. Perhaps at a certain frequency a capacitor will look the same as an inductor in a circuit, but it seems impossible to for a capacitor to replace an inductor across all frequencies. Then again, I'm still an undergrad, and perhaps in something like a dc oscillator, it could be done.
Q:i cant connect the resistor and inductor and the voltmeter check this
If you learn to spell and punctuate someone may help you. Yes, it does matter. I would never hire someone who sent me a message like yours.
Q:An electric oscillator is made with a 0.10 uF capacitor and a 1.0 mH inductor. The capacitor is initially charged to 5.0 V.
This may be an overly long method and an incorrect interpretation of the question but assuming it is an inductor and capacitor in parallel: Impedance of inductor 2πfL and imp. of capacitor 1 / (2πfC) When the current resonates the impedances are equal and thus this equation is formed: 1 / (2π√(RC)) f, the resonant frequency. So you calculate the frequency and that allows you to get the impedance of the inductor or capacitor - which turns out to be 100 ohms. In parallel two 100 ohm components give an impedance of 50 ohms (1 / R 1 / R1 + 1 / R2). Therefore the maximum current should be 5V / 50? 0.1 A
Q:if the frequency is 60 Hz.
XL2*pi*f*L 2*pi*60*0.9getyouranswer and the substitute it in ohm's law. IV/XL. Inductors and capacitor offer a form of resistance to ac called Inductive reactance and capacitive reactance respectively whch is dependant of da frequency of the supply.
Q:How much DC current flows through a resistor-inductor series circuit after the inductor has fluxed (i.e., after the transient)?
At an 'infinite' time after applying a DC source, the current will settle to a value determined by the resistance of the inductor a la ohms law. But if its an ideal inductor, the current will simply continue to ramp up linearly for ever
Q:1. 12J2. 31J3. 16J4. 20JPlease explain further
The standard formula for energy stored in an inductor is: E ?LI? . . ? x 2 x 4? . . 16J
Q:A series circuit consisting of an inductor of negligible resistance and a pure resistor of 12Ω is connected to a 30V, 50Hz AC supply. If the current is 2A, calculate: (a) the PD across the resistor (b) the PD across the inductor (c) the inductance of the inductor (d) the phase angle between applied voltage and current. (e) the impedance of the circuit
(a) PD 2A X 12 Ohm 24 Volts (b) Z 30V/2A 15 Ohm Xl (15 Ohm) X sin(arc cos 12/15) 9 Ohm PD across inductor 2A x 9 Ohm 18 Volts (c) 9 Ohm (6.28) x (50) x inductance Inductance 9 / 314 28.7mH (d) Phase angle arc tan Xl/R arc tan 9/12 36.87 degrees (e) Impedance 30V/2A 15 Ohm
Q:All the current from the wire before it will go through the inductor because there is no resistance, right?
Almost. If it is made of very low ohmic value.
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1. Manufacturer Overview

Location Guangdong,China (Mainland)
Year Established 2010
Annual Output Value US$10 Million - US$50 Million
Main Markets North America; South America; Eastern Europe; Southeast Asia; Africa; Oceania; Mid East; Eastern Asia; Western Europe
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