Q:a fully charged capacitor is connected to an inductor and a resistor. what is the value of tfe charge on the capacitor when time becomes large?

Depends on what the total circuit looks like. If both ends of the capacitor are connected to each other thought the resistor, and maybe the inductor, then the large-time charge will be zero.

Q:A constant voltage of 12.00 V has been observed over a certain time interval across a 2.60 H inductor. The current through the inductor, measured as 3.00 A at the beginning of the time interval, was observed to increase at a constant rate to a value of 7.00 A at the end of the time interval. How long was this time interval?

Given v12.00V, L2.60H, Δi4.00A The voltage across an inductor is given by: v L*di/dt v L*Δi/Δt Δt (L/v)Δi 0.87s

Q:A 10 ohm resistor and 10 henry inductor are attached in series to a 10 volt DC supply. If the current i(0)2.5 amperes, what is the current after 1 second? Round in the tenths place.I got 1.55 but that isn't right.

Question doesn't make sense. Current after a long time would be 10/10 1 amp, where just the resistance would be relevant. Current when the supply is first turned on will be less, not more than 1 amp.

Q:A certain circuit consists of an inductor of 55 mH in series with a resistor of 90 Ω. At a moment when the current in the circuit is 21 A, a switch in the circuit is opened. How long will it take for the current to fall to 7.14 A? Answer in units of s.Okay, easy smeasy I thought. i made an expression 7.1421(1-e^(-90t/55*10^-3))Simply algebra, so I got t2.53926x10^-4. This is wrong! please show me the errors of my ways. Do the entire problem. Show work. I need to get this down to I can tackle the tougher problems.And I based my expression off of the equation i(Io)(1-e^(rt/L)). Thanks! will choose best answer!

This is easy. You used the wrong formula. The formula is for current INCREASING from zero and asymptoting to Io. But it isn't accurate even for that. The actual formula is i Io (e ^- t/(rL)) Note the features. The larger the value of r the less that is lost (or gained ) per second. The larger the value of L the less that is lost (or gained) per second so these must be in the denominator. The larger the time the more that is lost so it must be in the numerator. The negative sign in e ^ - x means that as x becomes larger ( more time taken) the answer becomes smaller. If we had 1 - e^ -x then it would asymptote to 1 not to zero. This would be the case for increasing the current to a maximum.

Q:I need help answering this question i have no idea how to do the steps if you could lead me through the steps or tell me what to do that'd be fantastic.An inductor is fabricated with 500 turn of wire, a diameter of 1 centimeter and a length of 2 centimeters, and an air core with a permeability of 1.25X10^-6 H/m. A DC current of 500 mA is made to flow through the inductor.Find:A) The inductanceB) The energy stored in the field:C) The energy stored in the field if a steel core, with apermittivity of 4000 is inserted into the coil.

A)From physics, you know that: B μNI / h where μ is the permeability h is the height of the loop B is the magnetic flux N number of loops B 0.03125 wb An the inductance L is equal to L B/I L 0.0625 H B) Energy stored 1/2 LI^2 0.007813

Q:At a given instant the current through an inductor is 50.0mA and is increasing at the rate of 115 mA/s. What is the initial energy stored in the inductor it the inductance is known to be 60.0mH, and how long does it take for the energy to increase by a factor of 10 from the initial value?

Energy in an inductor 0.5 L I^2 0.5 (60 x10^-3)(50 x10^-3)^2 7.5 x10^-5 J 7.5 x10^-4 J 0.5 (60 x10^-3) I^2 I SQRT [ 7.5 x10^-4 J / 0.5 (60 x10^-3) ] 1.58 x10^-1 Amps 158mA increase needed 158mA - 50mA 108mA time 108mA /115mA/s .939 sec

Q:i cant connect the resistor and inductor and the voltmeter check this

If you learn to spell and punctuate someone may help you. Yes, it does matter. I would never hire someone who sent me a message like yours.

Q:How can I make inductors ?

You can make inductors my winding an insulated wire around a suitable core. The core is usually air or carbon. Use appropriate formula to calculate how many turns you need. Make sure that the wire is insulated. Hope this was helpful.

Q:A) What is the initial energy stored in the inductor if the inductance is known to be 66.5 mH ?B)How long does it take for the energy to increase by a factor of 9 from the initial value?Please give me final answer too :x thank you so much!

Energy stored in the inductor 1/2 Li? 1/2 x 66.5x10?? x (15.5x10??)? 7988.3125 x 10?? J 7.988 x 10?? J W ∝ i? Hence for energy to become 9 times, the current flowing through the inductor should increase by √9 3 times. That is current should be 3 x 15.5 46.5mA Time taken (46.5 - 15.5) / 270 0.1148s

Q:An L ? C circuit contains a single inductor in parallel with a single capacitor. The inductor has an inductance of 0.55 mH and the circuit has a resonant frequency of 250 kHz. What is the capacitance of the capacitor? I keep getting 2.9e-8, but the correct answer is 7.4e-10, and I have no idea why.

Inductors are also similar to resistors and add in series. There are two components in inductors, the resistance and inductance. The resistance is negligible compared to inductance. But inductance comes into play only when an alternating current flows. Inductance L x2 pi x f where L inductance, pi 3.14 and f frequency