SBH15-M amorphous alloy oil immersed transformer
- Ref Price:
-
- Loading Port:
- Guangzhou
- Payment Terms:
- TT OR LC
- Min Order Qty:
- 1 pc
- Supply Capability:
- 1000 pc/month
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Item specifice
Model Number:
SBH15
Usage:
Power
Phase:
Three
Coil Structure:
Toroidal
Coil Number:
Autotransformer
Rated Capacity:
30-10000kva
Core:
Amorphous alloy
Insulation Level:
Class F/H
Rated Voltage:
6.3kV-35kV
Cooling Method:
Copper/ Aluminum coil
Frequency:
50Hz/ 60Hz
Cooling:
ONAN/ ONAF
Installation:
Indoor/ Outdoor
Product Introduction
With stable & reliable quality for strong low current supply; Have strong short-circuit resistant and good thermal stability.. Can drop the no-load losses substantially Save energy Low cost & High return investment
Voltage Available: 10kV, 11kV, 20kV,22kV,33kV,35kV..
In order to better meet people's high demand for saving energy and resources, our company develops a new product Amorphous Alloy Omniseal Distribution Transformer, which is an advanced transformer made with amorphous alloy magnetic iron core and will get lower consumption.
Amorphous Alloy is a new type energy saving material, which is not exist crystal structure, with small magnetizing power and low impedance can reduce eddy current losses. Uses this kind of material as core, can drop the no load losses substantially.
Product Parameter
| Item NO. | Group Voltage & Tap Range | Connection Symbol | No-load power(W) | Load Loss(W) | No-load Current(%) | Short Circuit Impedance(%) | Dimension | Gauge(mm) | Weight(kg) | ||
| L*W*H | |||||||||||
| High Voltage(KV) | Tapping Variation | Low Voltage(V) | (mm) | ||||||||
| S(B)H15-M-30/10 | 6 | ±5% | 0.4 | Dyn11 | 33 | 600 | 1.5 | 4 | 400 | 345 | |
| S(B)H15-M-50/10 | 6.3 | ±2*2.5% | 43 | 870 | 1.2 | 480 | |||||
| S(B)H15-M-63/10 | 10 | 50 | 1040 | 1.1 | 545 | ||||||
| S(B)H15-M-80/10 | 10.5 | 60 | 1250 | 1 | 625 | ||||||
| S(B)H15-M-100/10 | 11 | 75 | 1500 | 0.9 | 710 | ||||||
| S(B)H15-M-125/10 | 85 | 1800 | 0.8 | 550 | 850 | ||||||
| S(B)H15-M-160/10 | 100 | 2200 | 0.6 | 940 | |||||||
| S(B)H15-M-200/10 | 120 | 2600 | 0.6 | 1085 | |||||||
| S(B)H15-M-250/10 | 140 | 3050 | 0.6 | 1265 | |||||||
| S(B)H15-M-315/10 | 170 | 3650 | 0.5 | 1485 | |||||||
| S(B)H15-M-400/10 | 200 | 4300 | 0.5 | 660 | 1860 | ||||||
| S(B)H15-M-500/10 | 240 | 5150 | 0.5 | 2180 | |||||||
| S(B)H15-M-630/10 | 320 | 6200 | 0.3 | 4.5 | 2480 | ||||||
| S(B)H15-M-800/10 | 380 | 7500 | 0.3 | 820 | 3048 | ||||||
| S(B)H15-M-1000/10 | 450 | 10300 | 0.3 | 3420 | |||||||
| S(B)H15-M-1250/10 | 530 | 12000 | 0.2 | 4218 | |||||||
| S(B)H15-M-1600/10 | 630 | 14500 | 0.2 | 4922 | |||||||
| S(B)H15-M-2000/10 | 750 | 18300 | 0.2 | 5 | 6150 | ||||||
| S(B)H15-M-2500/10 | 900 | 21200 | 0.2 | ||||||||
Product Features
1. SH15 oil immersed transformer
2. Adopts Amorphous core
3. Only 1/3 losses of normal transformers
4. With good heat dispassion
Rating Capacity: From 100kVA ~2500kVA Available!
Voltage: 10kV~35kV Available!
Product Installation
1. Installation: outdoor
2. Altitude: <1000m< span="">
3. Highest air temperature: +45 °C
4. Lowest air temperature: -25°C
5. Sunshine intensity: 0.1w/cm2(wind 0.5m/s)
6. Rain proof level: Level 3
7. Earthquake resistance ability: The ground level acceleration of 0.2g
8.The inclination of the installation site: <3°< span="">
- Q:If it is powered by a DC source, will there be a Back EMF generated? Why/Why Not?Obviously, there will be a higher current flowing than that of a AC supplied transformer, but I don't know why.Thanks.
- A transformer uses magnetic flux changes in the primary coil for induce a voltage in the secondary coil, the relation between the voltages is given by: Vsec N2(dΨ1/dt) (Faraday's law of induction) Ψ1 k*N1*I1 Then Vsec N2(k*N1*dI1/dt) where: N1: number of turns in primary coil N2: number of turns in secondary coil Vsec: Voltage in secondary coil Ψ1: magnetic flux in primary coil I1: current in primary coil k: constant involving Reluctance and others parameters If the current in the primary coil is DC (a constant) then his derivative must be zero, then Vsec 0
- Q:Briefly explain how an alternating current transformer works and why they are so important to the world’s electrical power infrastructure.
- Okay. You take a magnet and run it past a coil and you get electricity. You can also simply switch the direction of current (or pulse it) in order to create induction current in a coil. So. if you make a basic AC electromagnet with say. 100 loops of thick copper wiring, and put it next to another coil with say. 10,000 thinner wraps. The coil that gets the juice, will induce a current in the coil next to it. Conveniently, more wraps higher voltage lower amperage, and fewer wraps higher amperage lower voltage. So in the above scenario, under ideal circumstances, we would take a primary voltage off 100 volts 100 amps and turn it in to a stepped-up voltage of 10,000 volts at one amp. The reason this is important is that high voltage travels well over great distances. It is much easier to push the same juice much farther away from its source with very high VOLTAGE and low amps than it is to do it the other way. Amps cause heat, heat causes loss and damage to the carrier wire. Voltage just rides along on the surface of the wire with very little loss. So we step up for transport and back down for use when we are close enough to end-use that the losses are negligible.
- Q:SGB10 transformer and SC (B) 10 transformer What is the difference between the two series where the difference, specifically to the 10 type and where the hope that the knowledge of a detailed explanation Thank you
- Both transformers are dry transformers. 1, SG (B) 10 is an open dry change, he used the United States DUPONT company's NOMEX insulation paper insulation (high voltage coil, you can see is white, if it is darker that is covered with glass wire The former is American technology, the latter is German technology.) The low voltage coil is a copper foil (there is a B in the model that is made of copper foil). The same is true of B in the SC (B). High and low coils are insulated with VPI (vacuum pressure dipping). The surface of a layer of epoxy resin insulation paint wrapped up. 2, SC (B) 10 model means that the epoxy resin pouring dry change (low pressure is copper foil). The high voltage coil is sealed with an epoxy resin, but the low pressure coil epoxy is hard to pour in, but at the end of the coil is sealed with an epoxy resin. 3,10 is the design serial number, representing the loss standard value. 4, there is a dry change, model SCR (B) 10, he is non-epoxy resin casting package. All with NOMEX paper plus silicone encapsulation is the French technology. This product yield less, better quality. Maybe the price will be higher. You can also look at it. 5, is currently in the country is the three kinds of technology transformers. Epoxy resin pouring products are mostly "F" class insulation level, a few also have "H". SG (B) 10 majority is "H" level. , A few are "C" level. SCR (B) 10 is "H" level. If you still want to know what, you can give me a message.
- Q:the use of autotransformers is strictly prohibited.
- Autotransformer A set of coils, which have a tap, can not achieve isolation. Or two sets of coils are attached.
- Q:I have a 34kv/380/500KVA transformer and it loads a pump of 450HP/2200V. Starting current reaches up to 1700 amps for around 3-4 seconds using a soft starter. The rated capacity of the transformer is 700amps and the pump running current is 689 amps.Any calculations to prove that the transformer is enough to provide the application would be a help.thanks.
- 500 kVA ÷ 0.380 kV ÷ √3 760 amps The nameplate rating (kVA) of a transformer is designed for 50% insulation life after being loaded to nameplate kVA and running with a top oil temperature of 110 °C for 20.55 years. (180,000 hours) Since your ambient temperature is not constant, and the equipment does not run continuously, the transformer's insulation will last far longer. In most real world applications, if a transformer is not loaded to nameplate, it will theoretically last for more than 100 years. Many electric utilities load their transformers beyond nameplate to take advantage of this overly long life. Motor Inrush: As for the motor starting inrush, the missing factor is how often the motor starts. If it is only seeing an inrush once an hour, the transformer can handle an inrush of 4x nameplate. Your motor's inrush of 1700 amps is 1700 ÷ 760 2.2 times nameplate. According to a transformer manufacturer's table, a transformer can handle an inrush of 2.2 times nameplate more than twenty times an hour. I highly doubt this 450 HP motor is starting and stopping every three minutes. You are good to go with the 500 kVA transformer.
- Q:I need to know the details of TRANSFORMER OUTEGE, if possible an equations related ,or any sources for getting idea on this .Pls help.THank u.
- Means that someones going without any electicity tonight. A Transformer changes voltage. As in, The Thermostat in most homes workes off 24 volts. A Transformer will take 120 volts and drop it down to 24.
- Q:I am learning about transformers and one of the items to calculate is the impedance. I need to calculate regular 60 Hz Core and Coil Shell Type Transformers Al wire in secundary, Cu Wire primary and use Epoxy paper for insulation.
- It's pretty difficult to calculate the impedances (there's more than one) entirely from the transformer's design data. It's easier and more usual to decide on an equivalent circuit (there are plenty available depending on how well you want to model the transformer) and then to determine the parameters by a mix of calculation and measurement. A pretty basic equivalent circuit which refers all impedances to the primary side, has the primary terminals connected first by Xm and Rc in parallel (the magnetising reactance and core loss resistance) and then by a third parallel branch containg a series connection of leakage reactance Xl, winding resistance Rw and an ideal transformer of turns ratio Np/Ns. Xm is best obtained from an open circuit test but could be calculated as the inductance of the primary winding. For the latter you'd need to know core dimensions, number of winding turns and the magnetising characteristic of the core iron. If you have conductor sizes and conductivities you can calculate the winding resistance Rw, referring the secondary part to the primary by multiplying it by (Np/Ns)?. You can deduce Rc from the losses measured on open circuit at nominal voltage and Rw from dc resistance measurements on the windings. If you know the specific hysteresis and eddy current losses of the core material, you can also have a good stab at calculating Rc. The leakage reactance is quite difficult to calculate from first principles - even designers usually resort to some empirical factors. Basically it's determined from the short circiut test which is at nominal secondary current. The ratio of primary volts to secondary surrent (referred of course) on secondary short circuit will get you close to Xl - you can adjust for Rw which can be determined from the losses on short circuit (core losses are absent here!) or by the two methods indicated above. It's normally Xl that's referred to as the transformer reactance and together with Rc and Rw, the impedance.
- Q:A I have a 230V/12V, 3A step-down transformer. What will happen at primary side of transformer if I attach a 12V/5A device at secondary side? Will primary side attributes (such as voltage or current) change?
- the transformer converts Watts if it is rated at 12V 3A it means 36 Watts if you load-it more than that it will overheat and eventually burn the primary current is proportional to the secondary current however with an overload of 5 A as oppose to a load of 3 A it may last for several hours before becoming too hot the answer is yes you can run your load for a while provided that you monitor the temperature and watch the situation however do not load over 3 times the rating (8~9A) for any length of time more than 1 second A
- Q:1.Why does transformer action can't take place in a dc circuit?2.on transformer coil what 5% tap means?
- A 5% tap means that on the secondary coil there is a tap (a connection that leads out) 5% of the way up (or down) the coil.
- Q:I have a DC current transformer and it is a 2500:1. I do not know what this means but I have a rectifier hooked up to it and am measuring the output DC voltage. I have hooked up resistors in values of 20Ω, 2kΩ, 10kΩ, and 20kΩ. I do not know how to convert to amperes though the resulting DC volts. How can this be done?
- Your current transformer at 2500:1 means, 2500 amp flowing through bar primary, (Which passes through the centre of the coil) will produce 1 amp in the coil, but it will not be DC. The CT will have a VA rating. You would have to put 2500 amps through bar primary to achieve 1 amp on secondary winding. This is in the power generation/distribution sector. It's what is says on the tin, A current transformer. The voltage output would be minimal. To find this, you would need to measure the AC voltage at 2500 amp through bar primary, or find the number of turns on the coil and/or the voltage drop on the primary bar as it passes through the coil. Primary volts per turn Sec volts per turn.
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SBH15-M amorphous alloy oil immersed transformer
- Ref Price:
-
- Loading Port:
- Guangzhou
- Payment Terms:
- TT OR LC
- Min Order Qty:
- 1 pc
- Supply Capability:
- 1000 pc/month
OKorder Service Pledge
Quality Product, Order Online Tracking, Timely Delivery
OKorder Financial Service
Credit Rating, Credit Services, Credit Purchasing
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