• Petant Design Malt Strage Silo with Factory Direct Price System 1
  • Petant Design Malt Strage Silo with Factory Direct Price System 2
  • Petant Design Malt Strage Silo with Factory Direct Price System 3
Petant Design Malt Strage Silo with Factory Direct Price

Petant Design Malt Strage Silo with Factory Direct Price

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Loading Port:
Tianjin
Payment Terms:
TT OR LC
Min Order Qty:
1 set
Supply Capability:
100 set/month

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Petant Design Malt Strage Silo with Factory Direct Price


Main Features for Malt Storage Silo

Details

Materials

Quality Standard

Features

 

 

Body Plate

By Hot Dip Galvanized Steel Plate,

275-600g/m2 Galvanization

China National Standard with Quality Report

Corrugated

Our Corrugated Steel Plate Production Line is IMPORTED

 

Bolts and Screws

 

Hot Dip Galvanized, Taiwan Imported, Strengthened, Max Sealing

Quality Strength Report

Imported from Taiwan

 

 

 

 

Enforcement Rib Stiffeners

 

Sidewall stiffeners are manufactured from min. 350 N/mm² tensile high strength steel with zinc coating of 275 g/m². This type of stiffeners easily transit the vertical loads during loading or unloading, environment loads of the silo.

China National Standard with Quality Report

Can be inside or outside rib

Rigorous calculation to meet full silo strength safety

 

 

 

 

Wind Ring

 

Hot Dip Galvanized

For additional support for higher wind areas, the wind ring is attached directly to the stiffeners. The rings strengthen the silo providing reinforcement against damaging wind.

China National Standard with Quality Report

Rigorous calculation to meet the anti-wind needs for sea port area or windy area

 

 

 

Manhole

 

A standard manhole door is located in the second ring of the silo. Double size door with strong frame and block system

China National Standard with Quality Report

Easy for the ascendant to inspect and maintenance, ensure the safety of the silo.

 

 

 

 

Stairs

 

SRON offers both ladders and stairs as outside climbing options. Stairs offer a shallow 8” step that decreases the incline angle for an easier, safer, and more comfortable climb.

China National Standard with Quality Report

Can be installed inside and outside of the silo, Easy for the ascendant to inspect and maintenance, ensure the safety of the silo.

 

Inside Ladder

 

Ladder inside silo, simple vertical or cage type ladder are available for your choice

China National Standard with Quality Report



Detail Asseccory for Malt Storage Silo

 


Structure for Malt Storage Silo

  • Galvanized Coating: 275-600g/m2

  • Bottom Type: Flat or Hopper Type

  • Gas-tightness: Perfect Gas-tightness

  • Auxillary System:Drying,Cleaning,Dedusting,Lifting and Conveying

  • Monitoring System: Temperature and Moisture Supervision SIMENS PLC

  • Silo Life: 25-40 Years

  • Installation and Debugging: Engineers Sevice Overseas for Transportable Silo


Picture:

Petant Design Malt Strage Silo with Factory Direct Price

Petant Design Malt Strage Silo with Factory Direct Price

Petant Design Malt Strage Silo with Factory Direct Price


Q:I live in South Dakota and in 1994 (on July 4th to be exact) the 68th Strategic Missile Squadron was deactivated meaning that the Kilo, Lima, Mike, November, and Oscar Launch Control Facilities were deactivated (along with the 50 missile silos that they were responsible for).
You may also want to visit the museum at Ellsworth AFB near Rapid City: www.ellsworth.af.mil/museum.asp They may be able to give you more information on any other sites that are available for wandering around at without getting into trouble. :) Have fun!
Q:A two-dimmensional, silo-shapped figure is formed by placing a semicircle of diameter 1 on top of a unit square, with the diameter coinciding with the top square. What is the radius of the smallest circle that contains this figure?
Draw a unit square (each side is 1 unit). Then draw a semicircle of diameter 1 on top of this, if you do this right the centerpoint of the circle will be at the midpoint of the top line of the square. Now draw a circle that goes thru the two lowest corners of the square the top of your silo, this is the smallest circle that contains it. Remember this doesn't have to be perfect to follow my explaination. Starting at the very top of the circle, draw a line straight down thru the top line of the square, but stop at the bottom line of the square. Label the top point of this line E, the mid point of this line F the bottom of the line G. If you've done everything right, the length of EF is 1/2 (the radius of the semicircle) and the length of FG is 1 (same length as the sides of the square). Pick a point on this line that looks like it's at the center of the circle (this should be between F G) draw a line out to one of the lower corners of the square. Label the end of this line at the center of the circle C the other end at the corner of the square H. Now we are done drawing. Since C is the center of the circle, we can see that CE is the radius of the circle. And CH is also the radius of the circle. So CE = CH. We can write an equation for each set them equal to each other. Lets say the distance from C to G is x, write an x next to it. Since FG = 1, FC is 1 - x, write that next to FG. So the length of EC = EF + FC = 1/2 + 1 - x = 3/2 - x. Now find the length of CH. Using the pythagorean theorum, we know square root of HG squared + CG squared = CH or CH = (HG^2 + CG^2)^1/2 = (1/2^2 + x^2)^1/2 = (1/4 + x^2)^1/2 EC = CG, so 3/2 - x = (1/4 + x^2)^1/2 Square both sides to get (3/2 - x)^2 = 1/4 + x^2 or 3/2^2 - 3/2x - 3/2x + x^2 = 1/4 + x^2 or 9/4 -3x + x^2 = 1/4 + x^2 or 9/4 - 1/4 = 3x or 2 = 3x, so x = 2/3 EC = 1/2 + 1 - x = 1/2 + 1 - 2/3 = 3/2 - 2/3 = 9/6 - 4/6 = 5/6. Your radius is 5/6 or 0.833333.
Q:Find the area available for grazing by the cow.
If the rope allows the cow to reach a spot on the opposite side of the silo, then the rope must be half of the circumference of the silo. If the radius of the silo is r, then the length of the rope is PI * r. The area that the cow can graze is the area of a circle with radius PI * r, or PI * (PI * R) * (PI * R) or PI ** 3 * r ** 2 (PI cubed times r squared) minus the area of the silo which is PI * R ** 2. The grazing area is then PI ** 3 * R ** 2 - PI * R ** 2 (PI cubed times r squared - PI times R squared). You can then factor to simplify the expression. HTH
Q:I am getting a golden retriever and I dont know what to name but I dont want to name it anything like Gikdie or something help!
Of all the names I would never have suggested, Gikdie probably tops the list.
Q:Coverage G of the farm policy for other farm structures would cover all of the following except?A.)SilosB.)AntennasC.)Portable buildingsD.) Pasture FencesIts tricky, my book never says anything about Pasture Fences...
It's been so long since I've read a farm policy, I had to get my book out, too. D. Pasture fences, are specifically NOT covered. It provides coverage for all fences EXCEPT field and pasture fences. You actually have to go read the policy form, rather than the book, to find the answer.
Q:A grain silo has a cylindrical shape. Its diameter is 16ft, and its height is 39ft. What is the volume of grain that can be stored in the silo?
Volume = pi * r^2 * h = 3.14* (16/2)^2*39
Q:Grain is pouring out of a silo at a constant rate of 4 m^3/min. As it falls, the grain forms a conical pile that has a radius twice its height. How fast is the radius increasing when the radius is 7 m?I am not getting the answer at the back of the book: the answer is 8/49pi m/min. Thanks
haha, you're lucky I was on this for another questions, so u get a quick reply. ok, so the radius is 7, so the height is 3.5. Calculate the volume of the cone. pi*r^2 *height. 49*pi*3.5. You get 171.5 pi is the volume. Divide 171.5 by 7 (the radius) and you get how many minutes it takes for the radius to grow one meter. (6.125 minutes). But you want how fast the radius is growing. So simple 1/6.125= 8/49m/min. I'll leave the transfering of the unit pi to you. Goodluck!
Q:for math i have to find the volume a silo, but i am not sure on how to start the question. After finding the volume i have to find how many pounds of hog fuel weighing at 44.4 lb/(ft^3) can fit inside it assuming that the silo is full. To find that, do i just take the volume and divide it by the mass of the hog fuel?
d = 12.8 m hci = 10.1 m hco = 10.3 m pi = 3.14 volume silo =pi(d^2/4)(hci + 1/3(hco)) mass = volume * density Edit: Dude, I gave you the formula and all of the values you need to plug in. Just plug in and solve. plug in and solve.
Q:what is the reason behind painting a flag on a silo?
It is a very old tradition. Originally it was done by homesteaders to claim the territory they occupied as part of the USA. Now it is a form of patriotism.
Q:A silo (base not included) is to be constructed in the form of a cylinder surmounted by a hemisphere. The cost of construction per square unit of surface area is twice as great for the hemisphere as it is for the cylindrical sidewall. Determine the dimensions to be used if the volume is fixed and the cost of construction is to be kept to a minimum. Neglect the thickness of the silo.I am having trouble getting a cost function in terms of a single variable.
let r be the radius of the hemisphere and the cylinder, h the height of the cylinder. the volume of silo V = pi*r^2*h + 2/3 * pi*r^3 so h = (V - 2/3 * pi*r^3)/(pi*r^2) (1) the surface area of the hemisphere A1 = 2*pi*r^2 the surface area of the cylindrical sidewall. A2 = 2*pi*r*h The cost C = k*(2*A1 + A2) where k is a constant. C = k*(2*2*pi*r^2 + 2*pi*r*h) (2) use eq.(1) to replace h in eq.(2) we get C is a function of a single variable r.

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