Class 10KV S11 series transformer

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Shanghai
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TT OR LC
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Supply Capability:
1000sets set/month

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Product Description:

Type description

Technical characteristic
1.It accords to the GB1207-1997<voltage transformer> ,IEC186 and IEC60044.
2.This product has the character of limited tightness.All the tightness compartment do not be put into ultraviolet radiation so that we solve the problem of chap of tightness rubber and aging,these product is more reliable and has longer life,we ensure that it can run 20 years without leakage.
3.The porcelain is equipped with irragateing flange.the surface of flange use hot zincification to enhance the wholly mechnism of product and has beautiful outlook.
4.This product is equiped with bellow and is tightnesds completely.
5.With higher accuracy to 0.2,we can reach the requirment of customer with seperatly measuring secondary winding and protection winding.
6.With epoxy secondary terminal board,the product is enhanced secondary insulation and tightness.
7.All the standard comparthent are plated Dakelo.We ensure that the product don't rust for 20 years.
8.The inner structure of this product has changed largly and we solve the problem of old 35KV PT with unreasoned inner structure for the unpassed dielectric loss,This product has low partial discharge and litter dielectric loss with advanced workcraft.
9.The excitaton density of this product is equal or less than 0.7T and has the ability of avoiding ferro-resonance.

Technical Data

TypeJDXF-35
Rated voltagePrimary winding35/
Measuring winding0.1/
Protection winding0.1/
Residual voltage winding0.1
Frequency50HZ
secondary accuracy and reated outputMeasuring winding80VA 0.2 class
Protection winding150VA 0.5class 250VA 3P class
Residual voltage winding100VA 6P class
Rated limit output2000
Rated insulation level4.05/95/200
Creepage distance810,1050,1250
Flash distance410-500
Total weight/Oil weight40/190
Pack size580×600×1300

JDXF-35 Voltage Transformer Outline Drawing



Srructure drawing


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Q:What is the rated current of the 80KVA transformer?
Rated current calculation of transformer Primary side approximation 0.058 * KVA (transformer capacity, size 10kV / 0.4kV) Secondary side approximation 1.44 * KVA (transformer capacity, size 10kV / 0.4kV) Known transformer capacity, and its voltage level side rated current Formula a: Capacity divided by the voltage value, the business by six divided by ten. Description: Applies to any voltage level. Unit KV 80KVA transformer low voltage rated current is: 80 * 1.44 = 115.2A
Q:can i plug in a power strip to a transformer?
Hi, The 1000 transformer the is mentioned is not too clear. However, since transformers are rated in power like watts in small designs and volt/amps as they are larger, I will tend to feel that the transformer you are using is a 1000 watt unit. If it is so, then that 1000 watts is the total power it can transform. A thousand watts is not a large quantity when it comes to televisions and other modern electronic equipment. Depending on the size of the television, that alone can use up the power of the transformer. The transformer would have been protected with a suitable fuse or breaker to prevent overloading by the users. Hence the breaker will trip on overload to protect the transformer. Check the power consumption of the appliances that you want to use.
Q:whats the new transformers movie about?
its about transformers.
Q:How the transformer is transformer
The role of the core is to strengthen the magnetic coupling between the two coils. In order to reduce the iron in the eddy current and hysteresis loss, the core from the painted silicon steel sheet laminated; between the two coils there is no electrical connection, the coil by the insulated copper wire (or aluminum) A coil connected to the AC power supply is called the primary coil (or the original coil), and the other coil is called the secondary coil (or secondary coil). The actual transformer is very complicated, inevitably there is copper loss (coil resistance heating), iron loss (core fever) and magnetic flux leakage (by air closed magnetic induction line), etc., in order to simplify the discussion here only describes the ideal transformer. The ideal transformer is set up under the condition that the leakage flux is ignored and the resistance of the original and secondary coils is ignored. The loss of the core is ignored and the no-load current is ignored (the current in the secondary coil turns the original coil). For example, when the power transformer is running at full load (the secondary coil output rated power) is close to the ideal transformer situation.
Q:Rated capacity of three-phase transformer S = √3 * U * I
S is the total capacity of the three phases, is the apparent power, the unit is KVA. The sum of the three phases is equal to the sum of the three single-phase capacities, ie S = 3UI where U is the phase voltage and I is the phase current. If the line voltage line current, then S = √3UI This is because when the winding is triangular connected, the line voltage is equal to the phase voltage, the phase current is equal to 1 / √3 times the line current, 3 / √3 = Similarly, when the star is connected, the phase current is equal to the line current, the phase voltage is equal to 1 / √3 times the line voltage, the same 3 / √3 =
Q:Why is Transformers Fall of Cybertron full of kids?
Kids like to play games about robots maybe? If this is bugging you then stop playing for a bit then try again another time to see if its not just kids anymore, I mean they grow up right? :)
Q:If the secondary coil contains more loops than the primary coil ( Ns Np) we have a sep-up transformer?
A transformer is a device that transfers electrical energy from one circuit to another through inductively coupled conductors—the transformer's coils. A varying current in the first or primary winding creates a varying magnetic flux in the transformer's core and thus a varying magnetic field through the secondary winding. This varying magnetic field induces a varying electromotive force (EMF) or voltage in the secondary winding. This effect is called mutual induction. If a load is connected to the secondary, an electric current will flow in the secondary winding and electrical energy will be transferred from the primary circuit through the transformer to the load. In an ideal transformer, the induced voltage in the secondary winding (Vs) is in proportion to the primary voltage (Vp), and is given by the ratio of the number of turns in the secondary (Ns) to the number of turns in the primary (Np) as follows:- Ns/Np Vs/Vp ---------------------(i) By appropriate selection of the ratio of turns, a transformer thus allows an alternating current (AC) voltage to be stepped up by making Ns greater than Np, or stepped down by making Ns less than Np.
Q:buck-boost transformer question?
I already answered this. First, what is satisfactory performance? Is the 102 volts the lowest the voltage reaches? I asked you this last time, and I still don't see an answer. If 102 is the lowest, than adding 10 volts is all you need, as that gets you 112 volts, and any 120 volt appliance will operate fine at 110 volts. A 120 to 12 volt transformer is easy to find, and with 102 volts input you will get 10 volts output, and added to 102 that gives you 112 volts, plenty to operate the AC. Parts of this question read like a homework problem, but parts don't such as the undefined term satisfactory performance, so which is it?
Q:How Sick Was Transformers?
I was pissed It ended way to soon!?!?!? I realize it was a rather long movie but after 20 years I needed another few hours. I desperatly await a number two, And they better make it.
Q:gas furnace transformer?
There are two step down transformers either 208 to 24V or 120V to 24V. The transformer is marked what voltage its rated for and also can be verified with a volt meter. You need to check inside the furnace for voltage by removing the furnace panel. Try this turn the fan to ON on the thermostat. If the blower comes on your getting signal. And have 24V. Now if you have batteries in the thermostats then either the contacts are dirty or the batteries are dead. So check that as well. Also, if for some off reason you took the furnace cover off and did not put it back on right. There is a door switch. If the switch is not making good contact the unit wont do anything. Lastly if you have an older furnace that uses a fan combination switch that may be bad. Try running the unit with the fan set to ON and then turn the heat on. If the heat comes on then the fan combination switch is at fault and your on barrowed time till the high limit device fails.

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