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We merge these roles because: Reducing “skills silos” results in fewer communications gaps, more efficiency, and better outcomes for clients.
it's an attitude found in some organizations that occurs when several departments or groups do not want to share information or knowledge with other individuals.
ensure their supply of drugs.
ok fine...but let's not give the peeps who control the nuke silos halucinogens
Does anyone living in lake-county- lake bluff area knowIf the SILO is a COUGAR area.?Some told me that place was popular for PIZZA. and older womenLooking for younger guys.I would love to find me an older women.625 Rockland Road Lake Bluff, IL 60044Does anyone know if it is true, or just a cruel joke.?
Kevin Pang a writer for the Chicago Tribune recently wrote an article about the restaurant. I am sure if you go to the Chicago Tribune web site you could read the article. I am sure that the article did not mention specifically if it was a cougar area but I am sure you might get some hints from the article.
Every time I go to the location it is never their. walkthroughs say that it should remain on the silo in the middle of the lake bed until the regular wraith is destroyed.
No, it's until the AA Wraith is destroyed. IT IS THE AA WRAITH THAT SHOULD NOT BE DESTROYED. Destroy the normal one, but do not forget to keep the AA one alive.
Why won't the zoning board let me build a watchtower on my property?
Because they probably know your neighbors might object? Adventurous kids and teens might trespass on your property, climb your tower, fall out of it and then sue you. Normally I think zoning boards screw up and I do think you should be allowed to build a tower if the world were more normal. But this is a crazy world and I think the zoning board is protecting you.
The silo shown in the skecth is an air- and water-tight tower. It consists of a lower cylinder surmounted by a frustum of a cone whose lower base is the upper base of the cylinder. The Frustum in turn is surmounted by a cupola consisting a smaller cylinder whose lower base is the upper base of the frustum. This smaller cylinder is topped by a conical roof. The inside radii of the smaller and larger cylinders are 6ft. and 12ft., respectively. The altitudes of the frustum and larger cylinder are 6ft. and 21ft., respectively. If ensilage can be stored up to the cupola, find the storage capacity of the silo.
There's no diagram provided, but it seems the storage capacity of the silo is equal to the volume of the lower cylinder, plus the volume of the frustum. (Since the upper cylinder is part of the cupola, we won't count it as part of the silo's storage capacity.) Let C = the volume of the lower cylinder, and Let F = the volume of the frustum. Now, C = πr^2 h We're given that r = 12, and h = 21. So, C = π(12^2)(21) = 3,024π ft^3 The frustum is like a cone with its top part sliced off. The base-radius of the cone is 12 ft. The top part, sliced off, is a similar, smaller cone with base-radius 6 ft. If we let y = the height of the sliced-off cone, and consider the triangular cross-section of both cones, then, by similar triangles, (y + 6) / 12 = y / 6 => 2y = y + 6 => y = 6 So, the height of the larger cone is 6 + y = 12, and the height of the sliced-off cone is y = 6. (Recall again we're given that the base-radius of the larger cone is 12, and the base radius of the sliced-off cone is 6.) Then, the volume of the frustum is the volume of the larger cone, minus the volume of the sliced-off cone: F = (1/3)π(12^2)(12) - (1/3)π(6^2)(6) = 504π ft^3 Our total volume V is: V = C + F = 3,024π + 504π = 3,528π ft^3
this question is in the book quot;calculus early transcendentalsquot; by james stewart.
s = radius of the silo. The rope must have a length of πs because it reaches around half the silo. Let θ=0 be the point at which the cow has walked around the silo and is at distance 0 from the silo. If the cow walks around keeping the rope taut then when θ = π the rope is fully extended; if the cow keep walking around the silo, it will eventually be back to 0 extended rope. We can think of this angle is two ways: either sin(θ/2) from 0 to 2π...or...[1 - cos(θ)] which will let us avoid half-angle forms. So, the length of the rope at angle θ is πs[1 - cos(θ)]. Now we are ready to set up our polar coordinate equation and integrate. If r is actually a function of θ, as is the case here, then area = (1/2) I[r^2 dθ]. area = (1/2) I{[πs(1 - cos(θ)]}^2 dθ from 0 to π. We will double our area to account for the full range of motion of the cow. I[1 - cos(θ)]^2 = (3/2)θ - 2sin(θ) + (1/4)sin(2θ), evaulated from 0 to π = 3π/2 --> the area where the cow can walk is (πs)^2*3π/2...*but*...the cow cannot walk inside the silo, so subtract πs^2. Grazing area is thus (πs)^2*3π/2 - πs^2 = πs^2[(3/2)π^2 - 1]. The only unknown is the radius of the silo. update: by the way, the shape of the area where the cow can graze is a cardioid.
Rough or Sensual...
Rough on the weekends. Sensual during the week. I love the new picture...:)