PVC Lined Fire Hose C/nature rubber lining fire hose

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China main port
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Min Order Qty:
1000 m
Supply Capability:
3000000 m/month
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Product Description:

PVC lined fire hose: 

1. The fire hose jacket is made of polyester staple and filaments or 100% polyester filaments.
2.  The lining can be made of natural rubber, synthetic rubber, pvc or pu . The jacket can be color
polyurethane coated jacket or dyed colored jacket (colors can be orange, yellow,blue and red). The hose resists abrasion. It has bright color, which makesit easy to distinguish. It is mainly used in fire-fighting and shipyards.

 Fire Hose Detailed Product Description


1) Advantage:PVC  lining fire hose which is thinner and softer, lighter, much convienient to use.

2) Sizes: 1.2" (32mm), 1.5" (40mm), 2" (50mm), 2.5" (65mm),

    3" (80mm), 4" (100mm)

3) Printing and color of inner PVC/PU/SY rubber: according to your requirements

Jacket Material:       

High tenacity filament polyester or nylon filament .

Working Pressure:  



Abrasion resistance, resistance to high pressure, water fast, cold resistance, corrosion resistance

Main Usage: Used in cold environment or more upscale places

inner dia


working pressure


test pressure


burst pressure




1"              25

1.0 / 10 / 150


1.3 / 13 / 190


1.6 / 16 / 240


2.0 / 20 / 300

1.5 / 15 / 220


2.0 / 20 / 300


2.4 / 24 / 360


3.0 / 30 / 450

3.0 / 30 / 450


3.9 / 39 / 580


4.8 / 48 / 720


6.0 / 60 / 900

15 / 50


20 / 66


25 / 82


30 / 100

1.5"           38

2.5"           64

3"              76

4"             100

PVC Lined Fire Hose C/nature rubber lining fire hose 



1.Do you have QC teams?
 Yeah, sure, our QC team is very important, they will keep the quality control for our products.
2. What's your normal delivery time?
Our delivery time about 10-20days for standard sizes, if you have other requirements like hardness  and width ,it is about 20-40days. But don't worry ,we also try our best for the delivery time ,because time longer and our cost is higher.


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It's a bit much to give answers for all that! I'll give some help for no. 1. 1) Work out the cross- sectional areas of the hose and nozzle (pi x r^2). Radius is 1/2 diameter. Multiply the hose x- sectional area by the flow rate per second, then divide the result by the x- sectional area of the nozzle. The result is the velocity of water from nozzle. The slightly quicker way is just to square the radii, and forget pi, which is common to both. ((R hose^2) x velocity)) /R nozzle^2 exit velocity. Try putting 1 question at a time up, but just ask for formulas/ help.
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? horizontal speed uw*cosp, where p35°, w25m/s; ? initial vertical speed vw*sinp, time to reach vertex is tv/g; distance from hose to building is xu*tw*cosp*(w*sinp/g) 0.5w^2*sin(2p)/g 30.0 m;
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use drop to get time d Vi t + 1/2 g t^2 Vi is 0 because horizontal at start -0.20 m 0 + 1/2 (-9.81) t^2 t^2 0.040775 t 0.202 s then if we ignore air resistance (customarily done) and the horizontal is the only component of V as water leaves hose horizontally Vx X/t 20 m / 0.202 s 99 m/s if you take g as -10 m/s/s then the answer comes out to 100 m/s

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