• Q345 Ringlock Scaffolding Standard / Q345 Standard Scaffolding System 1
  • Q345 Ringlock Scaffolding Standard / Q345 Standard Scaffolding System 2
Q345 Ringlock Scaffolding Standard / Q345 Standard Scaffolding

Q345 Ringlock Scaffolding Standard / Q345 Standard Scaffolding

Ref Price:
get latest price
Loading Port:
China main port
Payment Terms:
TT OR LC
Min Order Qty:
50 pc
Supply Capability:
10000 pc/month

Add to My Favorites

Follow us:


OKorder Service Pledge

Quality Product, Order Online Tracking, Timely Delivery

OKorder Financial Service

Credit Rating, Credit Services, Credit Purchasing

Q345 Ringlock Scaffolding Standard / Q345 Standard Scaffolding


Product description:

1.suitable for buildings like bridges, tunnels, large-scale construction projects, water conservancy project ,ship buildings, and so on.

2.latest wedge lock system is easy assembly and time saving. Due to its high stability and bearing capacity ringlock scaffolding is popular in the world.

3.made by high-strength welded pipe (48X3.0-3.5mm),which is durable and ensures the workers' safety.


Surface finishing: 

Hot Dipped Galvanized ( HDG) or zinc plate


Application:

Exhibition setup

Interior refurbishing

All the towers can be connected together for multi-purpose


Specification:

LengthWeight(KG)Material
330mm2.29Q345

500mm

3.20Q345
1000mm5.70Q345
1500mm7.85Q345
2000mm10.11Q345
2500mm12.80
Q345
3000mm14.70Q345
4000mm19.33Q345


Others Accessories:

Ledger, Standard( Vertical), Base Collar,  Steel Plank, Screw Jack etc. (Click to quick view).


Q345 Ringlock Scaffolding Standard / Q345 Standard Scaffolding

Q345 Ringlock Scaffolding Standard / Q345 Standard Scaffolding

Q345 Ringlock Scaffolding Standard / Q345 Standard Scaffolding

Q345 Ringlock Scaffolding Standard / Q345 Standard Scaffolding

Q345 Ringlock Scaffolding Standard / Q345 Standard Scaffolding

Q345 Ringlock Scaffolding Standard / Q345 Standard Scaffolding

Q:A man of mass 74.4 kg stands on a scaffold supported by a vertical rope at each end. The scaffold has a mass of 21.9 kg and is 3.9 m long. Suppose the man stands to the right from the middle of the scaffold that is a distance one sixth of the length of the scaffold. What is the tension in the right rope? b) What is the tension in the left rope? thanks in advance.
this could be a 2d concern. The moments approximately any factor interior the gadget would desire to stability, in the different case the gadget (scaffold) would rotate. additionally, the vertical forces would desire to stability, or the gadget (scaffold) would translate. it form of feels to me that to the superb from the middle of the scaffold it somewhat is a distance one 6th of the dimensions of the scaffold is comparable to saying 2-thirds from the left-edge of the scaffold. The moments could be summed approximately any factor. i will evaluate the left facet of the scaffold, the place the 2d produced by the left rope is 0. comprehensive M = 0 = scaffold M + guy M + suited rope M 0 = 23.7kg*9.8m/s^2*(3.1m/2) + 60.1kg*9.8m/s^2*(2*3.1m/3) - F*3.1m wherein: the scaffold is considered a factor mass located at its center the strain F acts opposite to the load of the guy and the scaffolding, and subsequently has -ve sign remedy for F. To get the strain in the different rope, you are able to basically evaluate the vertical forces interior the gadget. on the different hand, you should sum the moments approximately another factor (say, the superb rope). wish this permits.
Q:There is a 6.0-kg pail of paint to one side.How close to the left end can he approach safely? How close to the right end can he approach safely? Can someone help me with this problem, I keep working and reworking it and coming to the same answer. I must be consistently making the same mistake. If someone can help me work through it I would really appreciate it. The answers I got were:Left: dmin, left = .54mRight: dmin, right = .77m
At the threshold of danger, the tension on the far rope reaches zero. (a) Distance from left edge = x; then summing moments about the left rope gives ΣM = 0 = 71.0kg * g * (1m - x) - 22.0kg * g * 2.0m - 6.0kg * g * 1m The g term cancels, and the rest solves to x = 0.296 m ? (b) Distance from right edge is X; summing about the right rope, and knowing the g terms will cancel, ΣM = 0 = 22.0kg * 2m + 6.0kg * 3m - 71.0kg * (1m - X) leads to X = 0.127 m ? Hope this helps!
Q:For many years did not renovate the old house, the original is the kind of cement outside the gray, remove the gray + with cement and sand tiles, no glue, this method a square hand fee how much money? The original wall is to take the line, how to deal with. The local master said the line and the socket lifted up temporary hanging, finished tiles to say, can be decorated to electricity, I always feel this method is not safe, there is no better way?
Hello, "farmers from the building, the most important is the quality and safety
Q:Please advise the construction industry experts: residential full scaffolding inside the frame how to calculate the number of steel pipe needs, pay attention, I asked how many meters! Or tell me how many meters per square meter of steel pipe? And then attached to the high requirements, thank you For example: now a layer of 1000 square meters area, a total of 10 standard layer of residential buildings, 3 meters high! How to calculate the amount of steel required to do a layer? The amount of steel pipe in meters, or tonnage units.
Look at how many holes are needed with a few meters of steel pipe
Q:Seeking the Responsibility System of Safety Responsibility of Each Function Department Garden company for safe production permit
System, and to monitor the implementation of the situation
Q:Two painters are standing on a 5.0 mg long scaffold. Each painter weighs 833 N. 1 painter is standing 2.0 mg from the left end and 1 is standing .50 mg from the right end. The scaffold weighs 285 N. What is the tension in the 2 cables supporting the scaffold?
Summing torques at the left cable T2*5-833*2-285*2.5-833*4.5=0 T2=1225 N Summing torques at the right cable T1*5-833*3-285*2.5-833*.5=0 T1=726 N Check 833*2+285-(1225+726)=0 It checks j
Q:What is the distance from the external walls of the scaffolding and scaffolding?
Scaffold (scaffold) refers to the construction site for workers to operate and solve the vertical and horizontal transport and erected various stents
Q:How to do a good job of typhoon during the mass transfer mobilization work
strong winds may blow down buildings, high-altitude facilities, easily lead to casualties
Q:What would you like to ask?At what height do scaffolds have to be engineered?
At all heights...they are engineered as a system.
Q:for 10 sq. meters = ? h/sq. m. and how many person need to do the job?
It depend upon availability sorting of ledger to be used.If prop ledger has been transported sorted then three person can do 10 sqm in maximum 3/4 hour .i.e.0.075 h/sqm

1. Manufacturer Overview

Location
Year Established
Annual Output Value
Main Markets
Company Certifications

2. Manufacturer Certificates

a) Certification Name  
Range  
Reference  
Validity Period  

3. Manufacturer Capability

a)Trade Capacity  
Nearest Port
Export Percentage
No.of Employees in Trade Department
Language Spoken:
b)Factory Information  
Factory Size:
No. of Production Lines
Contract Manufacturing
Product Price Range

Send your message to us

This is not what you are looking for? Post Buying Request

Similar products

New products

Hot products


Related keywords