370MVA/535kV main transformer power plant

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Loading Port:: Tianjin

Payment Terms:: TT OR LC

Min Order Qty:: 1 pc

Supply Capability:: 1 pc/month

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Quick Details

Place of Origin:	HeBei	Brand Name:	CNBM	Model Number:
Usage:	Power	Phase:	one	Coil Structure:	Toroidal
Coil Number:	2 Winding	Capacity:		Rated Voltage:	370MVA/535kV
Connection Symbol:	YNd11 Dyn11 YNyn0d11	Tank:	Cover type or Bell type	OLTC:	MR or ABB or SMS

Packaging & Delivery

Packaging Detail:	Mainbody --naked Disassembled parts -- crate
Delivery Detail:	3 months

Specifications

1. CESI certificate
2. High short-circuit withstand
3. Low loss, PD and noise
4. CTQC certificate
5. No leakage

Description

The application of the 370MVA/535kV main transformer power plant.can significantly improve the economy of the OLTC substation, and matches well with the transmission capacity of OLTC lines, which has wide prospect of application. Because of its large capacity and large volume, the whole transportation weight with nitrogen is about 470-490 tons, and due to the restricted transport conditions, the transportation becomes the critical issue for the 370MVA/535kV main transformer power plant. In order to make the products applicable to any OLTC substation in our country, the state grid of corporation of China set the "A study of easy-transport large capacity OLTC Transformer” as a key scientific research projects, and entrusted BTW to carry out the research.

During the process of research and development, BTW adopted the advanced design technology and modular design, the transformer can be transported disassembly and with advantages of compact core and winding body, less transportation weight and low transportation cost, effectively solves the need of OLTC construction in the transportation restricted areas. By using the most advanced 3D magnetic field calculation software, BTW performed detailed analysis and calculation for the magnetic flux leakage and eddy current loss of the transformer coil, iron core and oil tank steel structures. Besides, by using of the advanced electric field calculation software, BTW performed detailed analysis and calculation of main longitudinal insulation, and mastered the arrangement of the main longitudinal insulation of large capacity OLTCtransformer and the control of distribution of winding magnetic flux leakage. All of which make the products with low loss, low noise, small volume, strong anti short circuit ability, no local overheating and other significant advantages, and guarantee the long-term safe and stable operation.

The world's first on-site assembled large capacity OLTC Transformer’s right at the first time once again filled the gap in the field of OLTC transformer research after Chinese transformer industry overcame the difficulty of integral transport of the 370MVA/535kV main transformer power plant, which marks BTW has fully occupied the world transformer industry technical peak. The successful development of the product filled the gaps in the domestic technology and met the urgent need of OLTCconstruction application in our country, greatly improved the technical level and manufacturing ability of BTW in terms of OLTC Transformer products.

Q:2500KVA transformer bearing current how much calculation: Did not give the voltage data to transformer primary and secondary side rated voltage 10KV / 0.4KV as an example: Primary side rated current: I = P / 1.732 / U = 2500 / 1.732 / 10 ≈ 144 (A) Secondary side rated current: I = P / 1.732 / U = 2500 / 1.732 / 0.4 ≈ 3609 (A)

Q:Transformer Wiring and Principle: Three-phase transformer works: the basic working principle of the transformer is the principle of electromagnetic induction. When the AC voltage is applied to the primary winding, the AC current flows into the winding to generate the excitation effect, and the alternating magnetic flux is generated in the iron core. The alternating magnetic flux passes through the primary winding and passes through the secondary winding , Which induces the induced electromotive force in the two windings, respectively. At this time if the secondary side and the external circuit load connected, there will be AC ??current out, so the output power.

Q:A small transformer used in a foundry has 550 primary turns and 20 secondary turns. Initially, the switch on the secondary side of the transformer is open, so there is no connection between the two ends of secondary coil.(a) What is the voltage difference between the two ends of the secondary coil, Vs, if a direct current potential of Vp 120 V is placed across the primary coil? (That is, the frequency of oscillation on the primary is zero.) (b) What is the voltage difference between the two ends of the secondary coil, Vs if Vp is 120 V and the frequency of oscillation on the primary is 60Hz? (c) Now equipment powered by the transformer is put into use and the switch is closed. A resistance of 14 Ω is placed between the two ends of the secondary coils. What is the current through the secondary coil? (d) What is the current through the primary side of the coil with the switch closed? Thanks so much!!: A. Zero, since dc current does not have a varying magnetis field. B. 550/120 20/ X 4.3636volts Ne /E p Ns / E s C.4.3636v / 14 .311 a. Es / R t A s D. .011 amp if the transformer is 100% efficient

Q:1. What does a transformer actually trasnform?2.What does a step-ip transformer step up?3. In a transformer, how does the power input to the primary coil compare with the power output of the secondary coil?: It transforms voltage and current from the values that exist at the primary to the values that exist at the secondary. 2. It steps up voltage. 3. Ideally, the input and output power would be the same, that is the product of voltage and current would be the same even though the voltages and currents are different. I practical transformers there is resistance in the wire and energy loss in the core so that the output power is slightly less than the input power. The difference appears as heat in the transformer.

Q:hi , i got some electronics frm asia( like camera and hair dryer) , which can only be used in 220 volts. which converter or transformer sud i use which changes 110 volt to 220 volt ? and where can i get it ? i searched for it . but i found converters that change 220 v to 110 volt :(: Do okorder

Q:When the transformer voltage is a rated voltage, the secondary voltage in the end is how to change with the load, what is the basis for the theory of the way you ask you about the inrush: 2 excitation current characteristics When closing the circuit breaker to charge the transformer, sometimes you can see the transformer ammeter pointer put great, and then quickly return to the normal no-load current value, the impact current is usually called the inrush current, features are as follows: 1) The inrush current contains high-order harmonic components (mainly secondary and tertiary harmonics), so the variation of the inrush current is a steep wave. 2) The attenuation constant of the inrush current is related to the saturation of the core. The deeper the saturation, the smaller the reactance and the faster the attenuation. Therefore, at the beginning of the moment decay quickly, then gradually slow down, after 0.5 ~ 1s after its value does not exceed (0.25 ~ 0.5) In. 3) Under normal circumstances, the greater the capacity of the transformer, the longer the duration of attenuation, but the general trend is the inrush current decay rate is often slower than the short-circuit current attenuation. 4) The value of the inrush current is very large, the maximum rated current of 8 to 10 times. When setting up a circuit breaker to control a transformer, the quick break can be set according to the transformer excitation current.

Q:even though the output voltage of a transformer can be much larger than the input voltage, the power output is nearly the same as the power input.Determine the relationship between the input and output current and the number of turns in the input and output coils.help!!!!!!!!thank you: just read your text book. lets say we have a transformer with a turns ratio of 10:1 If we apply 20 V on the high voltage side, (the side with the higher turns ratio aka 10:1), on the other side it will have 2 V. This is because of the turns ratio. Lets say that the power input on the high V side is 100W. So the current on the high V side is 100W/20V5 A Assuming ideal transformer with no losses, power in is power out. So on the other side, you will also get 100W. So the current on the low V side is 100W/250 A Basically, going from one side to the other, the V increases and the I decreases to keep the same power on both sides, as according to the turns ratio. I hope that you can figure out how the turns ratio of 10:1 made sense here. I better get best answer for this, lol. But seriously, read the text book, see how the turns are wound see how the electric field makes a magnetic field, which makes the electric field, etc.

Q:What is the temperature of the dry-type transformer?: Dry-type transformers are generally 130 ° C alarm. Most dry-type transformers now use H-class insulation. Under normal circumstances, the normal operation of the transformer temperature control control settings: 80 ℃ automatic fan, 100 ℃ automatic fan, 130 ℃ high temperature alarm, 150 ℃ high temperature trip. National standard "dry-type transformers" GB6450-1986 on the dry-type transformer temperature limit to make the provisions. 1, the dry-type transformer coil: A. The use of A-class insulation material, the limit operating temperature at 105 ℃, the maximum temperature rise should be less than 60K; B. When using E-class insulation material, the maximum working temperature at 120 ℃, the maximum temperature rise should be less than 75K; C. When using B-class insulation material, the maximum working temperature at 130 ℃, the maximum temperature rise should be less than 80K; D. When using F-class insulation material, the maximum working temperature at 155 ℃, the maximum temperature rise should be less than 100K; E. When using H-class insulation material, the maximum working temperature at 180 ℃, the maximum temperature rise should be less than 125K; F. When using C-class insulation material, the maximum working temperature at 220 ℃, the maximum temperature rise should be less than 150K. 2, the core, metal parts and adjacent materials, in any case, shall not appear to make the core itself, other parts or adjacent materials damaged by the temperature. Now most of the dry-type transformers are used H-class insulation material, it is generally said that the dry-type transformer temperature should be below 180 ℃.

Q:i have the 240V AC to 12V AC step down transformerwhen i connecting directly to 240V line the output is higher at about 16Vi need only 12V for my circuithow to get the exact amount of output voltage?: This is typical of smaller transformers. They are not very efficient, and so the output voltage changes with changes in load. They are specified for voltage at the full load, so with a light load the voltage is higher. Of course the output voltage also depends on the input voltage with a transformer, and there can be measurement issues with non sinusoidal waveforms. Usually a DC supply in an appliance or device (if that is your purpose) is designed so it can accommodate the full expected range of input AC voltages. This often involves a DC regulator applied to the unregulated DC output. This leads to a DC supply with a specified range of AC input voltages. You will need to consider the range of voltages your appliance can use. This is not always specified, but it may be shown as a maximum and minimum AC voltage allowed. With more information about your circuit it should be possible to determine the maximum and minimum input voltages required. There are ways to change this to suit your transformer if the appliance circuit is known. Ways to reduce the AC voltage: Increase the load on the transformer, perhaps with a suitable lamp or heater. The total load (watts) must be less than the transformer power ratings. Near full load the voltage will be more like the specified voltage for the transformer. This assumes the normal load is much less than the transformer power rating, which is when the voltage is high. If the load varies, this method is not ideal and it wastes power. Use a second transformer or variac to adjust the AC input to the transformer. This only works if the transformer is used with a small load. This will work best with a fixed load current, and is bulky and expensive. Get a different transformer specified to supply the correct voltage at the current you are using. If the current varies widely this is not a suitable method.

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