• 360MVA/242kV three phase water cooling main transformer for  hydro power station System 1
360MVA/242kV three phase water cooling main transformer for  hydro power station

360MVA/242kV three phase water cooling main transformer for hydro power station

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Quick Details

Place of Origin: HeBeiBrand Name:

CNBM

Model Number:

 

Usage:

Power

Phase: threeCoil Structure:

Toroidal

Coil Number: Capacity: Rated Voltage:

360MVA/242kV

Connection Symbol:

YNd11 Dyn11 YNyn0d11

Tank:

Cover type or Bell type

OLTC:

MR or ABB or SMS

Packaging & Delivery

Packaging Detail:Mainbody --naked Disassembled parts -- crate
Delivery Detail:3 months

Specifications

 

1. CESI certificate
2. High short-circuit withstand
3. Low loss, PD and noise
4. CTQC certificate
5. No leakage

 

 Description

 

The application of the 360MVA/242kV three phase water cooling main transformer for  hydro power station.can significantly improve the economy of the OLTC substation, and matches well with the transmission capacity of OLTC lines, which has wide prospect of application. Because of its large capacity and large volume, the whole transportation weight with nitrogen is about 470-490 tons, and due to the restricted transport conditions, the transportation becomes the critical issue for the 360MVA/242kV three phase water cooling main transformer for  hydro power station. In order to make the products applicable to any OLTC substation in our country, the state grid of corporation of China set the "A study of easy-transport large capacity OLTC Transformer” as a key scientific research projects, and entrusted BTW to carry out the research.

During the process of research and development, BTW adopted the advanced design technology and modular design, the transformer can be transported disassembly and with advantages of compact core and winding body, less transportation weight and low transportation cost, effectively solves the need of OLTC construction in the transportation restricted areas. By using the most advanced 3D magnetic field calculation software, BTW performed detailed analysis and calculation for the magnetic flux leakage and eddy current loss of the transformer coil, iron core and oil tank steel structures. Besides, by using of the advanced electric field calculation software, BTW performed detailed analysis and calculation of main longitudinal insulation, and mastered the arrangement of the main longitudinal insulation of large capacity OLTCtransformer and the control of distribution of winding magnetic flux leakage. All of which make the products with low loss, low noise, small volume, strong anti short circuit ability, no local overheating and other significant advantages, and guarantee the long-term safe and stable operation.

The world's first on-site assembled large capacity OLTC Transformer’s right at the first time once again filled the gap in the field of OLTC transformer research after Chinese transformer industry overcame the difficulty of integral transport of the360MVA/242kV three phase water cooling main transformer for  hydro power station, which marks BTW has fully occupied the world transformer industry technical peak. The successful development of the product filled the gaps in the domestic technology and met the urgent need of OLTCconstruction application in our country, greatly improved the technical level and manufacturing ability of BTW in terms of OLTC Transformer products.

 

Q:hello thank you for reading this question, i have a iron cored dc-ac transformer (relies on interrupter to constantly break circuit to induce induction in secondary coil) a brief and crude diagram can be found
If I understand correctly, you want to turn an old transformer into an electromagnet, and you want to use both windings in order to get the strongest possible field. First of all, you are going to need to modify the core: It needs a gap. In a perfect transformer, the lines of magnetic force would be entirely confined to the core.
Q:How to understand the secondary side of the transformer
The transformer consists of iron core (or core) and coil, the coil has two or more than the winding, which connected to the power supply winding called the primary coil (a test), the rest of the winding called secondary (secondary side). The basic principle of the transformer is the principle of electromagnetic induction, now single-phase double-winding transformer as an example to illustrate its basic working principle: When the primary winding with voltage U1, the current I1 flow, in the core to produce alternating magnetic flux , These magnetic flux known as the main flux, in its role, both sides of the winding were induced potential E1, E2. Transformer two sets of coil turns are N1 and N2, N1 for the primary, N2 for the secondary. In the primary coil plus an AC voltage, the secondary coil will produce both ends of the induced electromotive force. When N2> N1, its induction The electromotive force is higher than the primary voltage. This transformer is called a step-up transformer: when N2 <N1, its induced electromotive force is lower than the primary voltage, which is called a descending transformer. Primary secondary voltage and coil The number has the following relationship: U1 / U2 = N1 / N2 Suppose that n is the voltage ratio (turns ratio). When n <1, then N1> N2, U1> U2, the transformer is a step-down transformer, otherwise it is a step-up transformer.
Q:i have this audio transformer (about the size of a bottle cap) with three prongs on one side and two on the other. i am completely mystified by this configuration. how would i (say for example) hook up this transformer to a 9v battery in order to increase voltage? thx
There is no reason why the higher output supply would draw more current. The input current to the supply is indeed proportional to the amount of power consumed on the other end. In addition, it is even possible that the new power supply might be more efficient, and use less power if you get a good one. Look for one that has a Green certification. One power supply can be more efficient than the other. No power supply is 100% efficient. For instance, if your PC needs 90 watts and your Power supply is 90% efficient, the supply will need to draw 100 watts from the AC mains. In any case, I don't think you will be using any more energy with the upgraded supply, perhaps even less, and your PC should even run cooler.
Q:What is the power transformer, what is the rectifier transformer
Transformers are usually divided into power transformers and special transformers. You said the power transformer should be the power transformer in the distribution transformer, that is, low-voltage side directly for the use of electrical equipment. Rectifier transformers are rectifier devices for power transformers. Rectifier equipment is characterized by the original input current, and vice president through the rectifier output after the original DC. The main purpose of rectifier transformers: 1, electrochemical industry, such as: electrolytic copper, aluminum and so on 2, traction with DC power supply, such as: subway, light rail and so on 3, transmission with DC power supply, such as: rolling mill motor armature and excitation 4, DC power supply with DC power supply, 5, electroplating or electrical processing with DC power supply 6, excitation with DC power supply, such as: synchronous generator excitation 7, charging with DC power, such as: battery charging 8, electrostatic dust with DC power supply 9, cascade speed
Q:I took apart a wall transformer before and soldered a single AA battery to the outputs and touched the what was before inputs and it gave me a shock. This is because it stepped up the power to something like 113v. Could I instead of a AA battery use 110 from the wall. Would it do the same thing. Or would it just overheat the transformer. And what would the amps be. I’m trying to make like a 20amp welder for just screwing around with.
To answer your basic question I’m trying to make like a 20amp welder for just screwing around with. Look at the rating on the transformer, most wall transformers will tell you what wattage and voltage the transformer is rated. If it says 9 watts at 1.5 volts that is all it will do no matter what you do. You can put a chopped DC on the 1.5 volt secondary and get 115 volts on the primary but at a greatly reduced current (about .075 amps max). That is the best that transformer will do but because you are using a square wave you will be a less than an optimum power transfer. If you want 20 amps at 110 volts that is some substantial power and dangerous. D.bumstead
Q:A neon sign transformer has a 350 W AC output with an rms voltage of 13 kV when connected to a normal household outlet. There are 500 turns of wire in the primary coil.A How many turns of wire does the secondary coil have?B When the transformer is running at full power, what is the current in the secondary coil?C The current in the primary coil?I know what equations I would use, but I don't have enough information to use them. Can someone at least set these up and show me how to plug the numbers I have into the correct equations?
A neon sign transformer has a 350 W AC output with an rms voltage of 13 kV when connected to a normal household outlet. There are 500 turns of wire in the primary coil. Power output Power input Power Volts * Amps 350 13,000 * amps Amps 0.0269 amps current in the primary coil? House voltage 120 volts 350 120 * amps Amps ≈ 2.92 current in the secondary coil? Amp Ratio 2.92 ÷ 0.0292 100 : 1 Wire ratio 100 : 1 A How many turns of wire does the secondary coil have? 50,000
Q:What is the rated current of the 80KVA transformer?
It depends on how much the rated voltage Formula 1.73X Line Voltage X-Ray Current = Total Power
Q:Every yellow vehicle we pass on the road is BUMBLEBEE!!! and big trucks are opinus PWIME! And, he is constantly singing Twansfomahs, more dan meets dah eye! LOL So, I wanted to find him something for Easter that was transformers related, but as it's Easter, and NOT Christmas, I don't want to spend a lot of money. Suggestions?
coloring books and stickers but transformers aren't really easter realated so finding things may not be easy
Q:How do I choose a transformer? The
Select the transformer, you can not choose too large, can not choose too small According to the following method to select the transformer capacity. ???There is a very important data is not provided, is the load at the same time coefficient. Transformer with the actual load and equipment rated power ratio is called the transformer load factor. The concept of the load factor for the load is the probability that the load is used at the same time, also called the coefficient or the simultaneous coefficient, which is the probability of simultaneous use of the device. The total load is 300kw, but they are used at the same time there is a probability that the probability is the load factor. It is impossible to always use at the same time. Of course, you can according to the actual situation to calculate their own, power factor selected 0.80. ??With this formula, s = p * kX / cosφ Transformer capacity s = device rated power p × transformer load rate kx / power factor cosφ = (300 × kX) × 0.80 This is the transformer capacity. ???Do not know what the motor is used under the circumstances, so it can not be calculated, and only calculate the same time after the generation of the formula into the above formula. If the coefficient is 0.9, then the results of about 340 kVA, are used at the same time, that is, 375KVA, consider a certain margin and spare capacity, that can choose 400KVA. In addition to the above considerations, in particular, consider the motor starting current factor, select the transformer more reliable. As far as possible by the big do not rely on small. And the standard capacity of the transformer level 315,400,500,630KVA, 315KVA a little small, 500KVA big and no need. So choose 400kvA it
Q:How to test a Current Transformer (CT) ? thanks in advance
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