Farm Grain Steel Silos For Algricultural Usage

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Tianjin
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TT or LC
Min Order Qty:
1 set
Supply Capability:
100 set/month

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Product Description:

Farm Grain Steel Silos For Algricultural Usage

 

Quick Information

 

Type

flat bottom / hopper bottom

Material

hot galvanized steel

Auxiliary system

-Loading and unloading system

-grain cleaning system

-ventilation system

-Temperature monitoring system

-Level indicating

-Lightening proctection system

Characteristics

-Turkey basis

-standardization componet

-full silo filling

-clear silo discharging

  1. excellent heat insulation technology

  2. Easy Maintenance

 

Specification

 

Full silo filling

By adopting new type grain arrangement device, to make corns, rice, soybean meal or other materials to fill the silo to the maximum extent while alleviating automatic grading. Crushing reducing device is also adopted to ensure the material quality.


Clear silo discharging

By adopting silo vibrating discharging equipments, to solve the discharging problem of large flat bottom silo. At the same time, our discharging solution solves arch, bridging problems of soybean meal, vegetable seed meal, rice husk and other materials, and discharging problems caused by soybean harden. The energy consumption of our discharging equipments is 50% lower than that of the sweep auger of the same output. The silo basic cost is 40% lower than that of the cone bottom silo of the same diameter.


 Characteristics

Excellent heat insulation effect

By adopting coldbridge-free heat insulation technology, the thermal conductive area of our 10,000-ton silo is only 0.18m2, which is 2% of that of the heat insulation silo of other enterprises.



 Pictures

Farm Grain Steel Silos For Algricultural Usage

Farm Grain Steel Silos For Algricultural Usage


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Q:Have you ever visited a missile silo?
Niet... I have never seen one.
Q:What could happen if a nuclear war start in the middle east?
If there was a nuclear war in the middle east, it would be a much better place. If a nuclear bomb exploded in USA, it'd kill our economy and the world would probably go into a recession. Also, the country which sent the bomb would not exist.
Q:A silo is a structure that is shaped like a right circular cylinder with a half sphere on top. The surface are?
just substitute 6.25 for h and 1.5 for r and calculate -=-
Q:surface area and volume of silo?
Surface area of silo = 108*pi^2=1065.92
Q:What id the word for something that is hidden and ready for deployment?
The word is maybe poised. Example : The rock was poised precariously on the edge of the cliff. Derived from the Middle French pois meaning 'weight' or 'balance'. In the 15th century a poiser was an official who weighs goods.
Q:Do you know the meaning of these Russian Village Names? Razdolna, Voznesenka, or Kachemack Selo? BQ?
Open Kiline PAPER MOST SHOULD BE ALL THERE :) IC XC NIKA ZENA
Q:What is the surface area?
cylinder V = πr²h A = 2πr² + 2πrh = 2πr(r+h) Don't know if you include the top or bottom or both or neither. .
Q:Calculus optimization problem?
First note that in this problem, the height h refers only to the height of the cylindrical portion of the silo, not including the domed part (which would add another r ft to the height). The formulas given for the volume surface area include both portions of the silo. Begin by finding an expression of h in terms of r. V = pi(r^2)(h) + (2/3)(pi)(r^3) 497(pi) = pi(r^2)h + (2/3)(pi)(r^3) 497(pi) - (2/3)(pi)(r^3) = pi(r^2)h [497(pi) - (2/3)(pi)(r^3)] / (pi)(r^2) = h 497/r^2 - (2/3)r = h Now, using the formula for the surface area and substituting for h in terms of r, the function f(r) that calculates the amount of material needed based on the radius of the silo is: f(r) = (pi)(3r^2 + 2rh) f(r) = (pi)[3r^2 + 2r(497/r^2 - (2/3)r)] f(r) = (pi)[3r^2 + 994/r - (4/3)r^2] f(r) = (pi)( (5/3)r^2 + 994/r ) Use the First Derivative Test to find the value of r where f(r) takes on its minimal value. f '(r) = (pi)( (10/3)r - 994/r^2 ) 0 = (pi)( (10/3)r - 994/r^2 ) 0 = (10/3)r - 994/r^2 994/r^2 = (10/3)r 994 = (10/3)r^3 2982/10 = r^3 cbrt(2982/10) = r 6.6809 = r h = 497/r^2 - (2/3)r h = 497/6.6809^2 - (2/3)6.6809 h = 497/44.6346 - 4.4539 h = 11.1349 - 4.4539 h = 6.6710 Actually, there's a lot of rounding error in that value of h. If you use a calculator and don't round off, you'll see that the height h is the same as the radius r (accurate to 9 decimal places). Regardless, when rounded to one decimal place your answers are: r = 6.7 ft h = 6.7 ft (again, not including the domed portion of the silo; 13.4 ft with the dome). Edited to add: Cidyah beat me to the punch... but unfortunately, Cidyah did not calculate h in terms of r correctly... the total volume of the silo is 497(pi) according to the question. Everything else he/she did in terms of methodology is spot on; but unfortunately his/her final answers end up being incorrect.
Q:A dairy farmer uses a storage silo that is in the shape of the right circular cylinder.?
Volume is pi * (d/2)^2 * h = 72 pi Compute
Q:Im in need of some help on this word problem.?
Here is correct response: Area of cylinder formula: π*r^2*h. 15^2*π*h = 11,700π - divide by 225*π h = 52

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