Aluminum Magnesium Alloy Wire AL-MG Alloy Wire

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Loading Port:
China main port
Payment Terms:
TT OR LC
Min Order Qty:
10 m.t.
Supply Capability:
1000 m.t./month

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Product Description:

1.Product Introduction:

The high quality oxygen-free copper wire produced by our company adopts imported CATH-1 series of electrolytic copper in high purity, whose copper content is higher than 99.996%. We apply the upward-pulling technology in the protection of inert gas, and ensure the oxygen content of copper bar is lower than 8ppm. Through the hot-working process in vacuum, the oxygen-free copper bar becomes more uniform and dense in structure, and better in its inner quality. Through continuous pulling and pushing process to the 3mm copper bar by equal diameter wheel, the flexibility and circle performance are ganranteed, which enables us to supply high quality ingots for the next-process customers.


2.Product Characteristic:

1). Adopting Φ8mm high-quality oxygen-free copper wire ingots as raw material.

2). Using equal diameter wheel to pulling and pushing to ganrantee low loss of the wire material.

3). Adopting the micrometer slide pulling process, and the outgoing-line block is spinning block, which improves the circle performance of copper wire.

4). The take-up tension can be automatically regulated, and the Annealing voltage follow the line-pulling speed automatically which lead uniform annealing.

5). Good surface finish of wire material, good flexibility and ductility, and the elongation is greater than 35%.

6). Convenience in transportation, easy line-setting process, used for the high speed production of double-zero lacquer covered flat wire.


3.Image of Aluminum Magnesium Alloy Wire AL-MG Alloy Wire: 

Aluminum Magnesium Alloy Wire AL-MG Alloy Wire


4.Technical parameters: of Aluminum Magnesium Alloy Wire for Braiding: 

parameter performance name

Tensile strength

(Mpa)

Mainstream resistivity

(Ωmm2 / m)

Elongation

(%)

Density

(g/mm3)

Heat

(AJ/Kg°C)

Copper

205-270

≤0.018

15~20

8.90

0.39 * 103

aluminum

100-125

≤0.0285

8-15%

2.70

0.88 * 103

CCA

120-140

≤0.0268

15-25%

3.63

0.79 * 103

CCAM

160-350

≤0.0245

10-20%

2.85



5.FAQ

We have organized several common questions for our clients,may help you sincerely: 

①How about your Warranty?

 Warranty: 1-Year for the whole light. Warranty is based on correct storage, installation, using and maintenanc

②How to guarantee the quality of the products?

We have established the international advanced quality management system,every link from raw material to final product we have strict quality test;We resolutely put an end to unqualified products flowing into the market. At   the same time, we will provide necessary follow-up service assurance.

③How long can we receive the product after purchase?

In the purchase of product within three working days, We will arrange the factory delivery as soon as possible. The pecific time of receiving is related to the state and position of customers.Commonly 7 to 10 working days can be served.



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Q:Mass hung by two wires?
To solve this, you have to find 2 equations, because there are 2 unknowns. Assume, Tension in wire 1 = T1 Vertical component of T1 = T1 sin42.2 Horizontal component of T1 = T1 cos42.2 Tension in wire 2 = T2 Vertical component of T2 = T2 sin58.8 Horizontal component of T2 = T2 cos58.8 Since the sign board is in equilibrium, the forces must balance each other. Horizontally, the horizontal components of both forces are balancing each other. Therefore, T2 cos58.8 = T1 cos42.2 T2 = (T1 cos42.2) / (cos58.8) -------------------(1) For the vertical components of the wire, both are balancing the weight of the sign. T1 sin42.2 + T2 sin58.8 = (41.7)(9.8) T1 sin42.2 + T2 sin58.8 = 408.66N ----------------(2) Combine (1) into (2), T1 sin42.2 + (T1 cos42.2)(sin58.8) / (cos58.8) = 408.66 T1 ( sin 42.2 + cos 42.2 tan 58.8) = 408.66 T1 = 215.66N Subst T1 = 215.66N into (1), T2 = (T1 cos42.2) / (cos58.8) = 308.4N Hope it is correct ^^

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