Low Frequency Cheap Filter/Iductor
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- Q:an ideal current source is connected in series with an ideal inductor of 50 milliHenriesthe current source is not constant but a time varying sinusoid. the following formula describes the current in the units of Amperes : i(t) 10cos(500t)derive a formula for the voltage across the inductor, in the units of Volts, as a function of time.note that the units of Amperes per second time Henries yields Volts.I KNOW THIS IS A ODE PROBLEM, Im nor sure how to work the problem any help is welcome, thanks in advance.
- You use the definition of inductance (L) V L*di/dt where V is the induced voltage, and di/dt is the rate of change of current in the inductor. i(t) 10 cos(500*t) di/dt -500*10*sin(500*t) V -25*sin(500*t) note that the current function is not a sinusoid but is a cos function.
- Q:a detailed answer required. can inductors also be used or is there some drawback associated with them
- Op Amp Inductor
- Q:An electrical engineer needs an inductor capable of producing an emf amplitude of 140 mV. The current source available produces current of the form I I0 cos(ωt), with I0 0.65 A and ω 2.7 102 rad/s. What size inductor should be used?________mH
- Value of inductor (L) in mH is given by ωL 140/0.65 or (2.7*10?)*L 215 .38 or L 215.38/270 0.7977 or 0.8 mH
- Q:A 22 mH inductor, an 14.0 resistor, and a 6.0 V battery are connected in series. The switch is closed at t 0.Find the voltage drop across the resistor at the following times.(a) t 0V(b) after one time constant has passedVAlso, find the voltage drop across the inductor at the following times.(c) t 0V(d) after one time constant has elapsedV
- oubaas: Can you explain why for the inductor you don't use the 1-e^whatever and for the resistor you do? I'm just trying to understand the concepts before for my midterm. Thanks!
- Q:A 4 mH inductor is connected to an AC voltage source of 149 V rms. If the rms current in the circuit is 0.83 A, what is the frequency of the source?
- Use the equation X 2pi*f*L. You are given X indirectly, through V and I. Since I V/X, X V/I. Once you solve for X you can put this in the first equation and solve for f. X V/I 149/.83 179.52 X/(2pi*L) f 179.52/(2pi*.004) 7142.797 Hz
- Q:A series RLC circuit is connected across a 10kHz source. The 1.2 H inductor and 1000 ohm resistor are fixed and the capacitor is variable. At what capacitance will the current in the resistor be a maximum?
- At resonance the inductor and capacitor will be a short. C1/w^2 L where w2 pi f.
- Q:A 26.0 mH inductor has a reactance of 1.80 k. (a) What is the frequency of the ac current that passes through the inductor? ____Hz(b) What is the capacitance of a capacitor that has the same reactance at this frequency? ___ F(c) The frequency is tripled, so that the reactances of the inductor and capacitor are no longer equal. What is the new reactance of the inductor?____ k(d) What is the new reactance of the capacitor?___ k
- ok for the first one: reactance is 2pifL Xl reactance Solve for f which is frequency b. then u use 1/2pifC Xc for part b, and use this equation to get C c. Just do what it says for c and d. and use the above equations.
- Q:All the current from the wire before it will go through the inductor because there is no resistance, right?
- Almost. If it is made of very low ohmic value.
- Q:I am supposed to use a 10uH inductor but accidentally ordered a 100uh. How will this effect the circuit?
- 10uH ? A piece of wire with one turn has this inductance. You do not need to order it, make it yourself.
- Q:A 288.0 mH inductor is connected across the output terminals of an AC generator that is delivering an output voltage of 135.0 mV rms. What is the alternating current through the inductor if the frequency of the emf is 0.084 kHz? What is the alternating current if the frequency of the generator is changed to 1.09 kHz?
- X 2πf*L 2π*0.084*1000*0.288 152Ω I V/X 0.135/152 888?A ----- 888*1.09//0.084 11,525?A 11.5mA -----
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| Location | Shenzhen, Guangdong, China (Mainland) |
| Year Established | 2006 |
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| Nearest Port | Shekou,Yantian |
| Export Percentage | 51% - 60% |
| No.of Employees in Trade Department | 3-5 People |
| Language Spoken: | English, Chinese |
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| Factory Size: | 3,000-5,000 square meters |
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| Contract Manufacturing | OEM Service Offered Design Service Offered Buyer Label Offered |
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Low Frequency Cheap Filter/Iductor
- Ref Price:
-
- Loading Port:
- China Main Port
- Payment Terms:
- TT or LC
- Min Order Qty:
- 1000 Pieces pc
- Supply Capability:
- 10000 Pieces per Month pc/month
OKorder Service Pledge
Quality Product, Order Online Tracking, Timely Delivery
OKorder Financial Service
Credit Rating, Credit Services, Credit Purchasing
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