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If you're in Hawaii, number one, be sure to get a solar water heater. Guaranteed fast payback. Now about those kits. Avoid the kind that says you can make your own panels for under $200. Those are scams. If you're in CC of Honolulu, you will not be allowed to connect that kind of panel to your house - it doesn't meet National Electrical Code because it doesn't have a safety rating like UL. There are kits for grid-tied solar that run from $6000 on up. That's the kind that can actually save you money. I don't know whether you are allowed to install it yourself, though. In California, you can, as long as you get the inspection, same as any other building project. In spite of being further south, Honolulu gets about the same amount of sun as we do in San Jose, California. That's because our area is dry, and you have more clouds and rain during an average year. If you're in one of the wet valleys like Manoa or Palolo, obviously the situation would only be worse. But your electric rates are high, so you have a good chance of making your money back. Very few sites are really good for wind turbines. You cannot just put it on your roof in the city - it needs to up high, where the wind is strong and steady. That's why you see turbine mounted on towers. Also, because it has moving parts, it's going to wear out. Finally, you know how cars rust out quickly there compared to the mainland? Same thing with a wind turbine.s
running six hours a day doesn't mean much. You need to look at the solar insulation charts for your school's geographical location to come up with a better factor. The easiest number for you to use is sun hours. For example, Washington DC averages 4.23 hours. Do a Yahoo search for sun hours and you should find lots of charts. Solar panels rated at 50W give this output at full sun near noon at full brightness (no clouds). The sun hour factor makes it easy to find the equivalent number of full brightness hours. So, using Washington DC as an example you have: 000 panels * 50W * 4.23 sunhours/day = 634kWh a day on average. You state your school uses 88240kWh/month which is 6274kWh a day. This would mean you need ten times more solar panels since there is no way to get more daylight. Be careful to put in all the units in your formula and cancel them out to make sure you don't end up with a nonsense result. The title of the question would be answered as followed: 50W/000 * 4.23 sunhours/day = 0.63kWh/day or 9kWh per month or 228kWh a year. These are annual averages. If you wanted a specific month, you would need the sun hours for that month. Hope this helps.s
Heating panels have aluminum for the frame, glass for the top, copper pipes running through them, and possibly some plastic parts. The raw materials are easily obtained. Copper is the most difficult to get probably, but it's not all that rare, since we used to make pennies out of it. A solar electric panel is similar, with the copper used for wires and interconnect instead of pipes. The actual solar cells commonly used are almost completely pure silicon, which is abundant worldwide. There are traces of other elements in the silicon like boron, arsenic or phosphorous - these are also inexpensive, and easy to get.s
Typically LED's run off low voltage and 20mA or so of power (it depends what kind of led you have). That being said if one of your solar panels only provides 22mA of power then your circuit would have to be a series circuit for you to connect more than one. In a series circuit the current supplied of 22mA will go through each LED whereas a parallel circuit the current would be divided for each subsequential led. So in your case i can see you getting away with 3 or so led's before the voltage drop across each led will cause the voltage to be insufficient enough to drive anymore. Keep in mind the LED's will turn on but the first one will be bright then next one not as bright and so on. If you opted out and bought a solar panel with 200mA and 4V you could wire the led's in parallel and get 0 led's to turn on with the same brightness or intensity. Hoped that helped!s
Likely there will be at least a small change in the no load volts. The short circuit current will be different and the watts output will be different. Connect an amp- meter to the panel with or without a to 00 ohm resistor in series with the amp-meter and you will see different amounts of current for different colors. You do however need to adjust for the amount of light falling on your solar panel. Possibly you can use a exposure meter or a bolo meter as reference. Neils