• Syt Aluminum Sheet/Coil - Fin Stock Aluminum Foil with Competitive Price System 1
  • Syt Aluminum Sheet/Coil - Fin Stock Aluminum Foil with Competitive Price System 2
  • Syt Aluminum Sheet/Coil - Fin Stock Aluminum Foil with Competitive Price System 3
Syt Aluminum Sheet/Coil - Fin Stock Aluminum Foil with Competitive Price

Syt Aluminum Sheet/Coil - Fin Stock Aluminum Foil with Competitive Price

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Loading Port:
Shanghai
Payment Terms:
TT OR LC
Min Order Qty:
5 m.t.
Supply Capability:
10000 m.t./month

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Specification

Grade:
1000 Series,3000 Series,4000 Series,5000 Series,6000 Series,7000 Series,2000 Series
Surface Treatment:
Coated,Mill Finish
Shape:
Round,Flat
Temper:
T3-T8,O-H112,T351-T651,T351-T851,Soft,Half Hard,Hard
Application:
Liner & Wad,Decorations,Door & Window,Heat Sink,Transportation Tools,Glass Wall,Food,Kitchen Use,Pharmaceutical,Seal & Closure,Insulation Material,Label & Tag

 

1.Structure of  Fin Stock Aluminum Foil Description

1000 series are essentially pure aluminium with a minimum 99% aluminium content by weight and can be work hardened.  Widely applied in chemical industry, scientific experiments, ect.. Products commonly used in signs, billboards, building exterior decoration, bus body, high factory wall decoration, kitchen sink, lamp, fan, electronic components, chemical apparatus, sheet processing, deep drawing or spinning hollow ware, welding parts, heat exchangers, Bell surface and plate, plates, kitchen utensils, accessories, safety equipment and other.

 

 

2.Main Features of  Fin Stock Aluminum Foil

>Aluminum foil for fin stock;Heat exchange&condensator for A/C
>Alloy:1100/3003/8011-H22
>Thickness:  0.09~0.2mm
>Width:100mm~1000mm

 

 

3.  Fin Stock Aluminum Foil Images:

Fin Stock Aluminum Foil with Competitive Price

Fin Stock Aluminum Foil with Competitive Price

Fin Stock Aluminum Foil with Competitive Price


 

 

 

4.  Fin Stock Aluminum Foil Specification:

 

ProductAlloyTemperThickness
mm
Width
mm
Core  I.D
mm
Pipe OD
mm
 
Aluminium
 
Foil
 
1235H18 26
H24  O
0.007~0.290~152075 150 500200~1700
8011H18 H26
H24  O
0.007~0.290~152075 150 500200~1700
8006H18 H26
H24  O
0.007~0.290~152075 150 500200~1700
1060H18 H26
H24  O
0.007~0.290~152075 150 500200~700




5.FAQ

Q1.How long have you been in this product?
A1:More than 10 years.
 
Q2. What's the minium quantity(MOQ)?
A2. 5 Metric tons
 
Q3. How long is shipping time?
A3. 7 (ready-made products)-25 days(OEM)
 
Q4. How do you guarantee the quality?
A4. 1. Cooperating and Exchaning experience with sevral quoted aluminum companies
    2. Japanese and Swiss production line and skilled works (regular training and testing)
    3. more than 10 years production experience.
 
Q5. Do you have after sale service?
A5. Yes. Any quality problem occurs within one year, pls take photoes,we will be responsible.

 

 

 

 

Q: Are aluminum coils compatible with different welding methods?
Yes, aluminum coils are compatible with different welding methods. Aluminum is a versatile metal that can be welded using various techniques such as gas tungsten arc welding (GTAW), also known as TIG welding, and gas metal arc welding (GMAW), also known as MIG welding. These methods are commonly used for welding aluminum coils due to their ability to produce high-quality welds with good strength and appearance. TIG welding is particularly suitable for aluminum as it allows for precise control of heat input and provides excellent weld quality. It uses a non-consumable tungsten electrode and an inert gas such as argon to shield the weld zone from atmospheric contamination. MIG welding, on the other hand, is a faster process that uses a consumable wire electrode and a shielding gas to protect the weld pool. It is widely used in industrial applications due to its efficiency and ease of use. In addition to TIG and MIG welding, other methods such as laser welding and friction stir welding can also be used for aluminum coils, depending on the specific requirements of the application. It is important to note that proper preparation, including cleaning and surface treatment of the aluminum coils, is crucial for achieving successful welds. This ensures the removal of any contaminants or oxide layers that may negatively affect the welding process. Overall, aluminum coils are compatible with different welding methods, and the choice of technique depends on factors such as the desired weld quality, production requirements, and the skills and equipment available.
Q: This question asks for a comparison between steel wires and other materials when used in coilings, highlighting the pros and cons of steel wires.
<p>The advantages of using steel wires for coilings include high tensile strength, durability, and resistance to corrosion. Steel wires are also cost-effective and widely available. They offer excellent fatigue resistance, making them suitable for applications requiring repeated coiling and uncoiling. Disadvantages include higher weight compared to some alternatives, which can be a concern in certain applications. Steel wires can also be prone to rust if not properly treated, and they may not be as flexible as some other materials, potentially leading to difficulties in handling or installation. Additionally, steel's magnetic properties can be a disadvantage in environments where non-magnetic materials are required.</p>
Q: How many atoms are there in a piece of aluminum foil, 7.3 inches in length and 12.0 inches in width, and 0.141 mm thick? According to this problem, aluminum foil is a flat-rolled product, rectangular in cross section, of thickness from 0.006(0.15mm) to 0.00025(0.006mm). The density of Al is 2.699 g/cm3.
What you want to do is determine the mass of the piece of aluminum foil and then convert that to number of atoms. I'll give some pointers and you can fill in the rest: 1. Calculate the mass of the foil: a. Convert the length and width of the foil into centimeters. b. Convert the thickness of the foil into centimeters. Use your 0.141 mm figure. c. Now multiply the length times width times the height to give you the volume in centimeters. d. Now multiply this volume calculated in step c times the density of aluminum. That will give you the mass of your piece of foil. 2. Convert this mass into number of atoms. a. From the periodic table you know that there are 26.982 grams per mole of Al b. There are 6.02 x 10^23 atoms in a mole. c. So, take the mass calculated in Part 1 and divide it by 26.982 grams per mole of Al. That will give you the number of moles of Al in your piece of foil. d. Now take this number of moles and multiply it by 6.02 x 10^23 atoms in a mole, and that will give you the number of atoms in your piece of foil.
Q: A nitrate is added with sodium hydroxide, then a piece of aluminum foil. After warming the mixture, ammonia gas is released.A source tells me that aluminum reduces nitrate ion into the ammonium ion. How is this done?
Aluminum is an active metal and wants to be ionized. Al -- Al(3+) + 3e(-) ?n basic media, tetrahydroxoaluminate complex will be formed: Al(3+) + 4OH(-) -- Al(OH)4(-) ======================================... Al + 4OH(-) -- Al(OH)4(-) + 3e(-) Nitrate is reduced to ammonia in basic media, ammonium in acidic media: N(5+) + 8e(-) -- N(3-) NO3(-) + 8e(-) + 10H(+) -- NH4(+) + 3H2O in basic media, we add base (OH-) to both sides: NO3(-) + 8e(-) + 11OH(-) + 10H(+) -- NH4(+) + 3H2O + 11OH(-) NO3(-) + 8e(-) + OH(-) + 10H2O --- NH3 + 4H2O + 10OH(-) ======================================... NO3(-) + 8e(-)+ 6H2O -- NH3 + 9OH(-) Now, to the balancing of these two redox half reactions: Al + 4OH(-) -- Al(OH)4(-) + 3e(-) NO3(-) + 8e(-)+ 6H2O -- NH3 + 9OH(-) ============================= 8Al + 32OH(-) -- 8Al(OH)4(-) + 24e(-) 3NO3(-) + 24e(-) + 18H2O -- 3NH3 + 27OH(-) ================================== 8Al + 3NO3(-) + 32OH(-) + 18H2O -- 8Al(OH)4(-) + 3NH3 + 27OH(-) //////////////////////////////////////... 8Al + 3NO3(-) + 5OH(-) + 18H2O -- 8Al(OH)4(-) + 3NH3 Hope this helps.
Q: I'm having trouble with another chem problemAluminum sulfide reacts w/water to form aluminum hydroxide and hydrogen sulfide. Write the balanced chemical equation for this reaction and find how many grams of aluminum hydroxide are obtained from 14.2 g of aluminum sulfide.I already found the balanced equation but I need help on finding how many grams of aluminum hydroxide are obtained from 14.2 g of aluminum sulfide. Can someone please explain how it's done?
No way!! because of the fact inspite of the bat, the helmet and the shin guards the undergo is plenty larger than a human and is going to basically get mad from the bat and kill you. Nope $800,000 isn't something for that!
Q: Can aluminum coils be painted for custom designs?
It is indeed possible to paint aluminum coils to achieve personalized designs. The act of painting the coils opens up a world of limitless options for customization and aesthetic appeal. Various colors, patterns, and designs can be applied to the coils, catering to individual tastes and needs. To complete the painting process, the surface must first be cleaned, followed by the application of a primer and the desired paint or coating. Through this method, one can create distinctive and captivating custom designs suitable for a wide array of purposes, including architectural elements, signage, automotive components, and more. Moreover, the paint not only safeguards the aluminum from corrosion but also enhances its durability.
Q: Using principles of chemical bonding, explain why solid aluminum is a good conductor of electricity but solid aluminum chloride is not. NaCl has a boiling point of 1413 degrees celcius wheras BrCl has a boiling point of 5 degrees celcius. Account for this difference using chemical bonding and molecular structure.
Pure aluminium is a good conductor because it's atoms are metalically bonded. This means it's electrons are delocalised and can therefore produce a current. NaCl has a high boiling point because in order to evaporate it first needs to melt. And to melt it you need to break it's lattice structure. Na and Cl atoms are held by strong ionic bonds. BrCl on the other hand is covalently bonded. It's molecular structure does not need to be broken in order for it to melt or boil. All that has to be done is weak van der waal bonds need to be broken.
Q: Describe the various uses of aluminum coils in the manufacturing industry.
<p>Aluminum coils are widely used in manufacturing due to their lightweight, corrosion resistance, and strength. They are utilized in the production of various products such as automotive parts, aerospace components, and construction materials. Aluminum coils are also employed in the manufacturing of electrical wiring, heat exchangers, and packaging materials. Additionally, they are used in the production of cans and foils for food and beverage industries. Their versatility makes aluminum coils an essential material in many manufacturing processes.</p>
Q: Is it possible to customize the dimensions of aluminum coils?
Indeed, the dimensions of aluminum coils can be tailored to suit individual preferences. Customers are able to request and obtain aluminum coils that have been manufactured and trimmed to specific measurements in accordance with their particular requirements and specifications. This customization procedure entails the meticulous cutting and molding of the aluminum coil in order to achieve the desired dimensions. This capability offers versatility across a range of industries and applications, where precise coil sizes are indispensable. By customizing the dimensions of aluminum coils, they become perfectly compatible with various production procedures, machinery, or end-use applications.
Q: Is it possible to use a saw to cut aluminum coils?
<p>Yes, aluminum coils can be cut with a saw, but it's important to use the right type of saw. A hacksaw or a fine-toothed metal cutting saw is suitable for cutting aluminum. Lubrication is also crucial to reduce friction and prevent the saw blade from overheating. When cutting aluminum, it's advisable to use a cutting fluid or a light machine oil to keep the blade cool and ensure a clean, smooth cut. Always follow safety precautions and wear appropriate protective gear when cutting metal.</p>

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