Aluminum Sheet, Aluminum Coil for Ceiling or Doors

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Loading Port:
Shanghai
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TT OR LC
Min Order Qty:
5 m.t.
Supply Capability:
10000 m.t./month

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1.Structure of Aluminum Sheet, Aluminum Coil for Ceiling or Doors:

Aluminum sheet, coil for ceiling or doors has big strength of extension and yield. Mill finished or preprinted aluminum sheet or coil  is hard and ever lasting under the blazing sun. You can choose the alloys as your habitation and we will do our best to meet your requests.

2.Main Features of the Aluminum Sheet, Aluminum Coil for Ceiling or Doors:

• Smooth surface

• High manufacturing accuracy

• High strength of extension and yield

• High color accuracy

• Well packaged

3.

Aluminum Sheet, Aluminum Coil for Ceiling or Doors:

Aluminum Sheet, Aluminum Coil for Ceiling or Doors

Aluminum Sheet, Aluminum Coil for Ceiling or Doors

Aluminum Sheet, Aluminum Coil for Ceiling or Doors


4.Aluminum Sheet, Aluminum Coil for Ceiling or Doors:

 

             Aluminum Sheet, Aluminum Coil for Ceiling or Doors

 

    

Aluminum Sheet, Aluminum Coil for Ceiling or Doors

Aluminum Sheet, Aluminum Coil for Ceiling or Doors

Aluminum Sheet, Aluminum Coil for Ceiling or Doors

Aluminum Sheet, Aluminum Coil for Ceiling or Doors

Aluminum Sheet, Aluminum Coil for Ceiling or Doors

Aluminum Sheet, Aluminum Coil for Ceiling or Doors


5.FAQ

We have organized several common questions for our clients,may help you sincerely:

① How about your company

A world class manufacturer & supplier of aluminum coil and alloy blanks. Aluminum production base is comprised of 18 aluminum annealers, 10 coil and foil mills, 4 continuous production lines, 2 hot rolling production line and 3 prepainted lines.

Export  5000 tons per month to Asia, America and Middle East. Always do the best for our clients.

②Can you guarantee the quality of the products?

We are responsible for the quality of materials to get a long-term cooperation with clients in a reasonable period of time and we are glad to arrange and coordinate any third party inspection for you.

    ③What is the delivery time after purchase?

35 day after receiving client’s deposit or correct LC

 

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Q:Can aluminum coil 3003H24 replace 3A21H14?
It is ok in some way as both of them are alumal. The hardness of 3003H24 is similar to that of 3A21H14 after hardening without annealing. Both have good corrosion resistance, plasticity and bad machinability. They cannot be used as load bearing parts even though small load is ok. They cannot be anodized.
Q:Why there is arc panel after aluminum coil straightening?
The aluminum coil can only become flat and straight after being planished on stretch bender.
Q:Automotive aluminum coil, using GB H22, what brand, what are the main ingredients?
In the corresponding foreign brands for AlMg3, 5754 different heat treatment is the automobile manufacturing industry (car door, mould, seals), main materials used for canning industry
Q:How much is a ton gate of Jiangxi aluminium roll?
The effective distance of B1 and B2 around the inside wall of the entrance to;D depth (openings between the garage garage wall distance);Note: effective distance means no obstructions. Such as B1 with water to water the effective distance refers to the distance. If the above the door with a beam or beam, the correct value of H should be the top of the door opening to the beam or beam height.
Q:What volume of oxygen measured at 25oC and 0.975 atm is required to completely oxidize 3.42 g of aluminum to a?
First write out the formula reaction: 4Al + 3O2 --- 2Al2O3 Next, find the number of moles of oxygen gas needed to oxidize 3.42 g of aluminium completely. From the cchemical equation above, 3 mol of oxygen is used to oxidize completely 4 mol of aluminium. Calculate the no. of moles of aluminium used: no. of moles of aluminium used = 3.42 g / molar mass of Al = 3.42 g / 26.98 g mol^-1 = 0.127 mol Use the mole ratio concept to find the no. of moles of oxygen required: no. of moles of oxygen required : no. of moles of aluminium used = 3 : 4 no. of moles of oxygen required / 0.127 = 3 / 4 no. of moles of oxygen required = (3 / 4)(0.127) = 0.095 mol Next, use the gas equation PV = nRT [P: Pressure of gas in Pa; V: Volume of gas in m^3; n: no. of moles; R, gas constant, 8.314 J mol^-1 K^-1; T, Temperature of gas in K] -Convert 0.975 atm to Pa: 0.975 atm = (0.975 x 101325) Pa = 98791.875 Pa -Convert 25 oC to K: 25 oC = (25 + 273) K = 298 K -Substitute into the equation PV = nRT and solve it: (98791.875)(V) = (0.095)(8.31)(298) (98791.875)(V) = 235.2561 V = 235.2561 / 98791.875 = 0.002381 m^3 = (0.002381 x 10^3) L = 2.381 L
Q:Aluminum (Element)?
Aluminum is from team 3 and there for has 3 electrons in its outer shell and desires 5 to fill it. it fairly is going to react with any aspects from team 5 that want aluminum's 3 electrons.
Q:Removing electrons from Aluminum?
One approach to this can use the density of aluminum to find the mass of the1 cm³ block. The density of aluminum is 2.70-g/cm³ so your cube has a mas of 2.70-g. The number of aluminum atoms in this block is: 2.7-g Al x (1 mol Al / 27.0-g Al) x (6.023 X 10²³ atoms Al / 1 mol Al) = 6.023 x 10²² atoms Al. Each Al, as you pointed out, contains 13 electrons so we have 6.023 x 10²² atoms Al x 13 electron/atom = 7.83 x 10²³ electrons. 1 x 10¹² pC = 1 C and 1 C = 6.24 x 10¹⁸ electrons=== 1.5 pC x (1C / 1 x 10¹² pC) x ( 6.24 x 10¹⁸ electrons / 1 C) = 9.36 x 10⁶ electrons a.) % removed = 9.36 x 10⁶ / 7.83 x 10²³ x 100% = 1.2 x 10⁻¹⁵ % b.) Each electron has a mass of 9.11 x 10⁻²⁸-g , so the total mass removed =9.11 x 10⁻²⁸-g/elec x 9.36 x 10⁶ electrons = 8.53 x 10⁻¹⁴-g. Thus the % decrease is (8.53 x 10⁻¹⁴-g/ 2.7-g) x 100% = 3.16 x 10⁻¹² %
Q:Four roller rolling mill roller bearing on the aluminum top how always have holes
Do not know your factory function division, should have special polishing work roll, support roller grinding workshop, this problem should be addressed to them, sticks are not qualified, how can dry out qualified products?
Q:Does anyone know anything about artistic painting on aluminum sheeting?
I've known a couple of people who do this, you might try a search on Floating Panel. You could try to search out things on an artist called Gary Hume, as I know that his earlier paintings, certainly the ones for which he's known, were executed on aluminium. From what I remember of people doing this (some one on my MA made paintings on aluminium) the trick is in the priming, it being a non-pours surface. You need to rough the ground considerably and prime quite thickly. You also need to baton on the back, this will allow you to attach to the wall without ruining the face of the support, and prevent the possibility of warping. What looks great is if you recess the batons from the edge of the support, so that when against the wall they cannot be seen, this gives the appearance of hovering, and shows the thinness of your support. Another reason you might not be getting too many hits on your searches is the spelling, while not incorrect you might find art suppliers using the English, rather than the American spelling; aluminium rather than aluminum. I know that sounds petty but it might make a difference. The only other thing I know, while finding it a great surface to work on, smooth, bright, the artist I know also found it very expensive.
Q:polishing aluminum help?!?
Use 1200 to 2000 grit. Your sandpaper is way too course! The paper probably got gummed up With aluminum particals. Use water or oil to wash away particals. In other words wet sand it. Then get this polish called Mothers Aluminum Polish. And two micro fiber cloths. Use the mothers and wipe off with first towel. Then use second towel. Trust me! I spend alot of time in my machine shop making custom aluminum parts. If you can trickle water over the surface of what your polishing it helps. The 1200 to 2000 grit can be purchased at Walmart in the auto section.

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