Top Quality AWS A5.20 Competitive Price E71T-1Welding Mig Wire 0.8Mm

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Loading Port:
Tianjin
Payment Terms:
TT OR LC
Min Order Qty:
20 m.t.
Supply Capability:
30000 m.t./month

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Product Description:

 

Quick Details

  • Place of Origin: Jiangsu, China (Mainland)

  • Model Number: Welding Mig Wire 0.8Mm

  • Material: steel

  • Diameter: 0.8mm-1.6mm

  • Melting Point: 100

  • Weight: 1KG,5KG,15kg,18KG per spool

  • Application: welding various steel structure

  • Flux Content: CO2 or CO2+Ar

  • Item: Welding Mig Wire 0.8Mm

  • Brand Name: DA YUNHE

  • Place of Origin: Jiangsu, China (Mainland)

  • certification: CCS,TUV,LR,CPR,DB,ABS,GL,KR,NK, CWB,BV,RS

  • Dimensions: 0,8mm-1,6mm

  • Material: welding steel

  • Application: welding wire

  • Chemical Composition: C,Mn, Si,P,S

  • Shape: line

  • ISO certificates: ISO14001,ISO9001

Packaging & Delivery

Packaging Details:spool packing, precision layer wire on the black plastic spool, covered with the wax paper, each spool in ploy bag with silicon gel in the carton, then put on non-wooden pallets.
Delivery Detail:within 15 days after confirming the orders

 

Trade Items Of Product

PaymentL/C,T/T,
MOQ500 Kilograms
OEMAccept
PortShanghai 
Deliverywithin 20 days after confirmed the purchase order
Supplier Capacity 40000 Metric Ton/Year
PackingMAG/MIG wire:1kg 5kg 15kg per spool, every spool in one carton,then put on the wooden pallets
TIG wire:5kg or 10 kg per tube

 

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Q:Subwoofer wiring, help please?
Well, okorder.com/...
Q:Wired or Wireless connection?
Wired is much better, because it works faster, it's secure, far more reliable. The only downside of a wired connection is a necessity to mess around with cables. On the other hand, you do it only once. I'm using a wired connection.
Q:what size wire do i need?
If he does not know he had better leave it to a pro or you will get fried or burn the place down! GEEZ!
Q:how to wire a new plug on a wire?
If you're talking about a ''polarized'' plug the hot wire (usually all black) will attach to the narrow side. And the neutral (usually with a white stripe) will attach to the fat side.
Q:circuit wire resistance problem?
The resistance of the new wire is (in terms of its length, area resistivity); R2 = pL2/A2 And the resistance of the original wire is; R1 = pL1/A1 The ratio is;(resistivity will cancel because its the same for both situations) R2/R1 = L2A1/L1A2 given L2 = 3L1 R2/R1 = 3A1/A2 To find the new cross-sectional area ,require the volumes to be equal; L2A2 = L1A1 3L1A2 = L1A1 A2 = (1/3)A1 Sub this into the R2/R1 equation to get; R2/R1 = 9 R2 = 9R1 = (9)(21) = 189 ohms
Q:Red Black and White speaker wire?
I'n not sure I understand the problem. In my view if you have 3 wires -- ending in, let's say, three plugs -- and want an extension it doesn't matter what colour the wires are as long as you end up connecting the original wires to the same plugs. So if you have white, green and bare on the original cable, when you cut the cable you have white, green and bare on both halves. Use the white, black, red extension cable to connect the two halves. I'd suggest white white, green red, and bare to black at one end and the same at the other ... but it doesn't really matter. Hope that helps.
Q:Resistivity of a Wire?
R = ( rho x l)/A Where: R is the resistance, rho the resistivity, l the length and A the area Resiatance of wire = (3.76 x 10^-8 x 18)/6.52 x 10^-6 R = 0.1038 Ohms Voltage across wire = current through wire x resistance of wire V = I x R V = 1.44 x 0.1038 V = 0.14947 V = 0.15 Volts
Q:What are finishing wires?
Finishing wires are for the final stage of braces. They are pretty strong wires that snap tightly into your brackets so the orthodontist can finely control the teeth and line everything up nicely. I can't say how long until you get your braces off...that's kind of a case by case basis. Typically the wire retainers are better than the clear ones from a hygiene perspective. They can also be adjusted unlike the plastic ones.
Q:Mass hung by two wires?
To solve this, you have to find 2 equations, because there are 2 unknowns. Assume, Tension in wire 1 = T1 Vertical component of T1 = T1 sin42.2 Horizontal component of T1 = T1 cos42.2 Tension in wire 2 = T2 Vertical component of T2 = T2 sin58.8 Horizontal component of T2 = T2 cos58.8 Since the sign board is in equilibrium, the forces must balance each other. Horizontally, the horizontal components of both forces are balancing each other. Therefore, T2 cos58.8 = T1 cos42.2 T2 = (T1 cos42.2) / (cos58.8) -------------------(1) For the vertical components of the wire, both are balancing the weight of the sign. T1 sin42.2 + T2 sin58.8 = (41.7)(9.8) T1 sin42.2 + T2 sin58.8 = 408.66N ----------------(2) Combine (1) into (2), T1 sin42.2 + (T1 cos42.2)(sin58.8) / (cos58.8) = 408.66 T1 ( sin 42.2 + cos 42.2 tan 58.8) = 408.66 T1 = 215.66N Subst T1 = 215.66N into (1), T2 = (T1 cos42.2) / (cos58.8) = 308.4N Hope it is correct ^^
Q:what if you touch electric wires?
better use a tester to fin out where is the leakage of current,or else touch u r self,and feel,if its more that 220V AC then u r gone,

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