• Portable Power Bank Power Charger System 1
Portable Power Bank Power Charger

Portable Power Bank Power Charger

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TT OR LC
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Product Description

Promo Power Bank, Mobile Power Model 5000-5600mAh ; Power Bank for mobile phone ; Back up charger

Charge your devices on the go using the compact and convenient Power. The 5600mAh power charger works as an external battery bank.

It has a USB output interface that allows you to charge your smartphone, MP3 player or any other device whilst you are out and about.

The Power Bank  is available in a wide range of colours including black, royal blue, red, sky blue and pink. It can also be customised with your company logo or brand name using our high quality pad printing service.

We require a minimum order quantity of 50 and provide a lead-time of 5-7 working days.

1. Compact size, meet ur portable power supply
2. Certifications: CE FCC RoHS
3. Intelligent protection circuit/control
4. Over current/Over voltage/discharge/Short circuit/Over charging protection
5. Suitable for iPhone, sumsung, Sony, GPS, iPad etc with USB port digital products

Input: 5V/1.0A
Output Voltage/Capacity: 5V/1.0A
Net: 135g
Warranty: 1 year
Capacity: 5000-5600mAh
Recycle life: More than 500 times

Main features and application:

Ultimate capacity, fast charging, excellent safety and convenient carry, fashionable design and appearance, meet the charging demand of communicate and digital devices such like mobile phone smart phone, PDA, MP3, MP4, GPS, PSP etc...

Our Advantages:

Directly printing your logo on Powerbank.

Provide different Connector: DC 3.5 USB Cable/Samsung D800/SonyEricsson K750/Nokia DC. 2.0/PSP/MINI USB/LG/Micron USB/iPhone 4/4s/5s

Packing design can be changed as per buyers' requested.

Package:
1.1PC/ polybag, Free of charge
2. Small white box
3. Blister Card or Giftboxes, Velvet Pouch packing
4. Tin box or Magnetic box

Terms:
EXW, FOB, CIF

Payment:
T/T in advance, West Union, Paypal

Shipping Way:
UPS; FedEx, DHL, TNT and so on.

Product Picture Showing

Portable Power Bank; Power Charger
Portable Power Bank; Power Charger
Portable Power Bank; Power Charger

Q:have somebody know how to make a power bank portable charger that usually use to charge our notebook battery or handphone?also with a high capacity. maybe someone can help me how to make a scheme of PCB, what's part that needed, and how to set it into PCB and get work.thanks *sorry, my english ability not good enough.
Why not use off-the-shelf components ? I.e. a 12V charger for the cellphone, sold to use in a car, and then a 12V battery bank with a solar charger, and something like the iGo 12V laptop power supply. Yes, it would be more efficient to do it in one go, but you'd have to make it adjustable for every separate device you want to charge, since many require different voltages
Q:Does anyone know what is the best ford year model to get, if I want to add 150hp on it? I heard about chips and after market parts, but I also heard you can still blow up the 6.0L engine or mess it up real bad, and the transmition will not last. Can anyone help me? What do you think is the best way to gain the extra power safely, where my engine and transmition will not fall apart in only two years. Also, I will not switch to any other truck maker.
Can you wait a month? You'll like the new 2008 with the 6.4. The twin turbo is a hoss and they've upgraded the interiors and have some new options with it like navigation and the rear step to get in the bed.
Q:i want to know how to measure practical the power out of generator i have generator and i lost the Manuelthere's no info on the generator except the voltage and Frequency
The only practical method of measuring generator output is with a frequency meter, power meter, or alternatively, a voltmeter and ammeter, and an adjustable load bank. If it is a portable, a.c. generator, you could connect known loads to the generator, such as portable space heaters and light bulbs. As you load the generator up, you will eventually see the frequency dip significantly, which will indicate that the generator has achieved its full load.
Q:I had an account with chase bank and the account ended up becoming over drafted about 1,000 dollars. i just received notice on what i will be receiving for my refund on my taxes and I'm wondering will they have the power to automatically deduct the debt from my state or federal tax return.?
Only if you have your refund sent to that account or another account at Chase. Otherwise the IRS does not collect on private debts.
Q:i was wondering if an example of concurrent power would be to charter banks?
The coalition in the UK and Germany.
Q:i need help with banking in canada. i want to know if i got a bank account and for some reason i cant sign any paper beccause of a injury or what ever. How would i be able to get money out of my bank could i assign certain people to help mi get money when i had a injury? can some one help mayb give me some links on the information. thix be great help
There are several things you can do. You can set up a power of attorney, so someone can do your banking for you. You can open a joint account with a trusted person, so they can access the account for you. Some banks even have other ways of dealing with such a situation. Talk to a representative at the bank where you deal, and they can give you specifics regarding their particular bank.
Q:Can bank pay a transaction eventhough you told them not to pay? And then give you a negative balance, and then charge you overdraft fee?
Call them argue it. Unfortunately banks have way too much power over our money now days!!!! ANDthere isn't much we can do about it.
Q:A power house on a river bank supplies power to a plant on the other side and 5 km. downstream. If the river is 3 km wide and the power line costs Php 4,000 per km. (Php is Philippine peso) on land and Php 5,000 per km. in water. Please show the detailed solution this problem is in differential calculus
A power house B C D plant we shall solve in general form then substitute values let AB w BC x BD wy cost ratio/km water:land k (5/4) angle BAC Θ dist. over water w?secΘ, dist. over land w(y - tanΘ) time C ∞ k?secΘ +(y - tanΘ) dC/dΘ k?secΘ?tanΘ - sec?Θ (ksinΘ - 1) / cos?Θ for minima, sinΘ 1/k which yields x w /√(k? - 1) 3/√((5/4)?-1) 2.25 km ----- you should now be easily able to compute the minimum cost
Q:A friend and me have an inside joke, and we r both superheroesi'm batwoman and shes spiderwoman. We know spiderman powers but neither of us can remember batmans.except for that totally awesome car. D
Batman doesn't have any powers. He's a human being who is driven by determination to wipe out crime and has trained his body and mind to be at the peak of human perfection. Batman really has nopowers to speak of, just a huge bank account to fund his gadgets, a vast intellect to help him sort his way out of any situation, as well as solve crimes, and an amazing physical regimen which helps him stay in shape and fight at the top of his game. Doesn't hurt that he looks good in black either.
Q:A power house, P, is on one bank of a straight river 200 m wide, and a factory, F, is on the opposite bank 400 m down stream from P. The cable has to be taken across the river under water at a cost of $6/m. On land the cost is $3/m. What path should be chosen so that the cost is minimized?
Call the point across the river from the power house P' Call the point of intersection of the cable with the opposite bank C, which defines right triangle PP'C Let x be the distance from P' to C The two legs of triangle PP'C are 200 and x So the hypotenuse (the distance the cable travels underwater) is sqrt(200^2 + x^2) The distance the cable travels along the shore is (400 - x) (the distance from C to F) cost under water: 6sqrt(200^2 + x^2) cost on land: 3(400 - x) 1200 - 3x Total cost 6sqrt(200^2 + x^2) + 1200 - 3x Find derivative of cost: 6(2x) / (2sqrt(200^2 + x^2)) - 3 6x/sqrt(200^2 + x^2) - 3 Where derivative 0 will be a min for the cost 6x / sqrt(200^2 + x^2) 3 2x sqrt(200^2 + x^2) 4x^2 200^2 + x^2 3x^2 200^2 x^2 200^2 / 3 x +/- sqrt(200^2 / 3) +/- 200 / sqrt(3) but discard the negative root (since this won't be the minimum cost), so the distance from P' to the cable hitting land should be 200 / sqrt(3) 200 / (3^(1/2))

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