Mill Finished Aluminium Coils for Wall Decoration AA3003

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Loading Port:
Shanghai
Payment Terms:
TT OR LC
Min Order Qty:
5 m.t.
Supply Capability:
5000 m.t./month

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Item specifice:

Grade: 1000 Series,3000 Series Surface Treatment: Mill Finish Shape: Flat
Temper: O-H112 Application: Decorations

Product Description:

1.Structure of Mill Finished Aluminium Coils for  Wall Decoration AA3003 

Mill Finished Aluminium Coils for  Wall Decoration AA3003 is one semi-finished aluminium material. This strip can be rolled down to aluminium coil,sheet,circle ect.  The alloy AA1050 is widly used in building, industry ect. Its weight is much lower than steel. So many customers choosed aluminium material instead of steel.


2. Main features of Mill Finished Aluminium Coils for  Wall Decoration AA3003 


a.Competitive price---We have our own mills and can produce mill finished aluminium coils, so we can control the production cost better.

b.Professional after-sale service---We have more than 15 years exportation experience and you need not worry about the exporation problems.

c.Fast delivery time---We can control the delivery time within 35 days.


3. Image of Mill Finished Aluminium Coils for  Wall Decoration AA3003

Mill Finished Aluminium Coils for  Wall Decoration AA3003

Mill Finished Aluminium Coils for  Wall Decoration AA3003

Mill Finished Aluminium Coils for  Wall Decoration AA3003



4. Product Specification ofMill Finished Aluminium Coils for  Wall Decoration AA3003 

AlloyTemperThicknessWidthCoil Weight
AA1100H180.2MM-3MM1000MM-1800MM2 TONS-5TONS


5.FAQ of Mill Finished Aluminium Coils for  Wall Decoration AA3003

What is the quality standard?

---Usually our standard is GB3880-2006

What is the largest width?

---It is 2300mm

What is the MOQ?

---Usually we can accept 80 tons.


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Q:What tools can I use to cut aluminum?
A rotary tool may do the trick. You would have to have a steady hand and also be able to hold the aluminum securely in place.
Q:Which kind of solution should I use while welding aluminum sheet and copper pipe by tin soldering?
1, you must use over 350W soldering iron, 2,prepare some borax and tin soldering paster, you can’t use rosin to weld it, 3, polish the pipe to clean with fine abrasive paper and borax, 4, put the pipe and sheet into borax, use the soldering trip to rub on the weldment with some borax. 5, after the pipe and sheet become hot, use the soldering iron with the paster and tin to rub the pipe and sheet in borax, then it can be welded. 6, they can be welded together after welding.
Q:aluminum ore is not formed in quebec (why not?)?
The okorder.com
Q:12ft aluminum boat weight limit?
12 Ft Aluminum Jon Boat
Q:Which explains aluminum's resistance to corrosion?
i would start by plugging in some of those key terms into wikipedia. it often has shockingly good engineering physics articles. there are really only 4 variables: exhaust tube, annealing furnace, age hardened aluminum alloy. play with those, and you might find terms that lead you to your answer
Q:Strongest Aluminum Stem?
i okorder.com
Q:Will sodium aluminum as an ingredient, cause problems for me?
It's actually Sodium Aluminum Phosphate. It's used as a preservative in a lot of food actually. It's not exactly good for you, but it's really no more harmful than any other preservative. So basically, it's unhealthy, but you're not gonna die from eating them. EDIT: Yes I realize that Aluminum has been linked to Alzheimer's disease, but this isn't Aluminum. Aluminum is an element. This is Sodium Aluminum Phosphate. A completely different substance. When an element bonds with another element (or two) often its properties completely change. I think you'd be surprised to learn that Sodium by itself, is not only horribly volatile (it will explode in water) and will kill you if you ingested it. Iodine is also poisonous in fairly moderate doses. But when the two are bonded together (sodium iodide) it becomes an essential nutrient to the body.
Q:How does the reflective film stick to the aluminum plate?
Put the plate clean, dry, reflective film a head from the aluminum back 2CM at the beginning attached to the aluminum plate, wrapping, pull to the front, back and side brush paper hanging tear reflective film side with the hanging brush to the aluminum paste, try to avoid bubbles.
Q:Can An Aluminum Water Bottle Go In The Fridge?
yea it would be safe because my brother does it all the time. Also you can just refill your plastic bottles with water and put in the fridge and the freezer because I do that all the time and i'm still using the same water bottles and they are in great shape and the fridge and freezer keep my water nice in cold.
Q:student combines 43.1 mL of a 0.279 M aluminum chloride solution with 14.6 mL of a 0.464 M aluminum sulfate (a?
You have to be able to determine the number of moles of Al+3 that each solution contributes to the final solution: 1. aluminum chloride: AlCl3 Multiply the volume (in L) by the molarity to determine the number of moles of each compound dissolved in solution. 0.0431 L x 0.279 M = 0.0120 mol AlCl3 in solution When the AlCl3 in placed in the water, it dissociates to form the following ions: AlCl3 -- Al+3 + 3Cl- So for every one mole of AlCl3 placed in the water, one mole of aluminum ions will dissociate. Therefore, since we have 0.0120 mole of AlCl3 in the solution, that means that the aluminum chloride will contribute 0.0120 Al+3 ions to the final solution. 2. Aluminum sulfate: Al2(SO4)3 Multiply the volume (in L) by the molarity to determine the number of moles of each compound dissolved in solution. 0.0146 L x 0.464 M = 0.00677 mol Al2(SO4)3 in solution When the Al2(SO4)3 in placed in the water, it dissociates to form the following ions: Al2(SO4)3 -- 2Al+3 + 3(SO4)-2 So for every one mole of Al2(SO4)3 placed in the water, two mole of aluminum ions will dissociate. Use the mole ratios of the dissociation reaction to determine the number of moles of Al+3 ions that the aluminum sulfate contributes to the solution. 0.00677 mol Al2(SO4)3 x (2 mol Al+3 ions / 1 mol Al2(SO4)3) = 0.01354 mol Al+3 ions Therefore, the total number of Al+3 ions in solution is the sum: 0.01354 + 0.0120 = 0.02554 mol Al+3 ions The last piece of information needed to determine the concentration of the final solution is the volume of the final solution. Since the two volumes were mixed, the volume of the final solution will be the sum of the two solutions. 0.0431 L + 0.0146 L = 0.0577 L Therefore, to calculate molarity: Molarity = moles of solute / liters of solution Molarity = 0.02554 mol / 0.0577 L = 0.443 M Al+3

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