Aluminium Coils for Continuous Cold Rolling

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5 m.t.
Supply Capability:
5000 m.t./month

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Item specifice:

Grade: 1000 Series Surface Treatment: Mill Finish Shape: Flat
Temper: O-H112 Application: Kitchen Use

Product Description:

1.Structure of Aluminium Coils for Continuous Cold Rolling

Aluminium Coils for Continuous Cold Rolling can be rolled down to aluminium coil,sheet,circle ect.  The alloy AA1050 is widly used in building, industry ect. Its weight is much lower than steel. So many customers choosed aluminium material instead of steel.

2. Main features of Aluminium Coils for Continuous Cold Rolling

a.Competitive price---We have our own mills and can produce mill finished aluminium coils, so we can control the production cost better.

b.Professional after-sale service---We have more than 15 years exportation experience and you need not worry about the exporation problems.

c.Fast delivery time---We can control the delivery time within 35 days.

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Aluminium Coils for Continuous Cold Rolling

Aluminium Coils for Continuous Cold Rolling

Aluminium Coils for Continuous Cold Rolling

4. Product Specification

AA1050H140.2-3MM1000-1800MM2 tons


What is the quality standard?

---Usually our standard is GB3880-2006

What is the largest width?

---It is 2300mm

What is the MOQ?

---Usually we can accept 80 tons.

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Q:can the oxide film on the surface of aluminum sheet prevent the erosion of acid liquid? Why?
yes, acid can react with aluminum oxide , generating salt and water, but its anti-corrosion will be stronger if oxide film on the surface is enough dense.
Q:aluminum elements question?
Aluminum is from group 3 and there for has 3 electrons in its outer shell and desires 5 to fill it. it is going to react with any aspects from group 5 that desire aluminum's 3 electrons.
Q:Analysis of a Magnesium-Aluminum Alloy?
This Site Might Help You. RE: Analysis of a Magnesium-Aluminum Alloy? A 0.250-g sample of a magnesium-aluminum alloy dissolves completely in an excess of HCl (aq). When the liberated H2 is collected over water at 29 C and 752 torr, the volume is found to be 311 mL. The vapor pressure of water at 29 C is 30.0 torr. What is the mass percentage of aluminum in this...
Q:Calculate Number of Aluminium ions ?
The formula for aluminium oxide is Al2O3 Its molecular weight is 2*27+3*16= 54+48 =102 Now, 102g of Al2O3 contains 2*6.023*10^23 number of Al ions so 1g contains (2*6.023*10^23)/102 number of Al ions so 0.051g Al2O3 contain (2*6.023*10^23)/102 *0.051 number of Al ions which is equal to 6.023*10^23*10^-3 = 6.023*10^20 number of Al ions(Answer)
Q:A solid aluminum ingot weighs 71.0 N in air.?
first find the volume of your aluminium. youll need this when analyzing the bouant force F(b). the sg of aluminum is 2.7 and the density of water is 1000 kg/m^3 so the density of aluminum is 2.7x1000=2700kg/m^3. the mass is 71N/g = 7.237512742 kg. so volume of our piece of aluminum = mass/density = 0.0026805603 m^3 now analyze the forces being applied to the system. There are three, the force of gravity F(g), the buoyant force F(b) and the tension T. Tension and buoyant force push up, gravity pulls down. the system will be at rest since the rope is holding it at rest. so T + F(b) - F(g) = 0 T + (Volume aluminum X density water X g) - (MAss of aluminum x g) = 0 T + (0.0026805603x1000x9.81) - (71 N (given in problem)) = 0 Solving for T, T = 44.70370346 N = 45 N using sig figs.
Q:Percentage Aluminum in alloy using stoichiometric relationship?
You don't need to worry about the magnesium at all, because it doesn't enter into the reaction. You have a balanced equation for aluminium and hydrogen, and the data given are sufficient: From the equation, you know that 2 moles of aluminium produce 3 moles of H2. 0.1068 g of H2 were produced, so divide this by molecular mass of H2 (2.016) to determine the moles of H2 produced. You know that 3 moles of H2 would have been produced from 2 moles of Al. Therefore, multiply the moles of H2 by 2/3, to determine the moles of Al that were present. Now multiply this number by the atomic mass of Al, to determine the grams of Al. Now divide this number if grams by 1.118 and multiply by 100 to determine % Al present in the alloy.
Q:How many molecules are in 1 square foot of aluminum foil?
Since aluminum foil is an amalgamation of various metals you would first need to know the full chemical breakdown in order to determine how many molecules there are in a square foot of aluminum foil. That said, if your foil was 100% aluminum, you could determine the number of AL atoms by first determining the mass of the foil and dividing by the molecular weight of AL. Multiply that by 6.022 x 10^23 to determine the number of atoms.
Q:What oil does the aluminum plate stretch with?
There are professional tensile oil, you can ask to pull the rice cooker liner manufacturers know, if not a lot of production, you can use peanut oil first try, the effect barely enough!
Q:How to distinguish aluminum sheet from magnesium sheet?
put two sheets into excess NaOH. The one that reacts with NaOH, generating sediment, is magnesium sheet,(sediment, but Al(OH)3 is amphoteric:Mg(OH)2) another one without sediment is aluminum sheet(in fact, there is sediment Al(OH)3, but it will react with alkali,)
Q:aluminum ore is not formed in quebec (why not?)?

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