Full-coloured aluminum coil

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Product Description:

Aluminium is a relatively soft, durable, lightweight, ductileand malleablemetalwith appearance ranging from silvery to dull gray, depending on the surfaceroughness. It is nonmagnetic and does not easily ignite. A fresh film ofaluminium serves as a good reflector (approximately 92%) of visible lightand an excellent reflector (as much as 98%) of medium and far infraredradiation. The yield strength of pure aluminium is 7–11 MPa,while aluminium alloys have yield strengths ranging from200 MPa to 600 MPa. Aluminium has about one-third the densityand stiffness of steel. It is easily machined,cast, drawn and extruded.

Aluminium alloys (or aluminum alloys; see spellingdifferences) are alloysin which aluminium(Al) is the predominant metal. The typical alloying elements are copper, magnesium,manganese,silicon,tin and zinc. There are twoprincipal classifications, namely casting alloys and wrought alloys, both of which are furthersubdivided into the categories heat-treatableand non-heat-treatable. About 85% of aluminium is used for wrought products,for example rolled plate, foils and extrusions.Cast aluminium alloys yield cost-effective products due to the low meltingpoint, although they generally have lower tensile strengthsthan wrought alloys. The most important cast aluminium alloy system is Al–Si,where the high levels of silicon (4.0–13%) contribute to give good castingcharacteristics. Aluminium alloys are widely used in engineering structures andcomponents where light weight or corrosion resistance is required

Specification:

Alloy:  AA1050, 1060, 1100,AA3003, 3005, 3015, 5052, 5754, 5083,8011, etc

Temper: H14/16/18/22/24/32,HO etc.

Thickness: 0.2mm100mm

Width: 100mm2300mm (Can be slitted)

Inner Diameter:508MM

Coil Weight:500kg-3000kg(Max.)

Application:Foil stock, Circles, Roofing, Can stock, Marine plateAnti-slipery purpose in vehicles, packing and appliance.

Features:

1.     Excellent quality of products

2.     Quick delivery

3.     Best service to clients

4.     BV,SGS  avalible

5.     No buckle o waveness

6.     Tension leveling

7.     Certificate of Origin

8.     Form A,E


Packaging  Detail:

Carton ,Woodenpallet with plastic protection packing ,standard seaworthy packing or as yourrequest.


Production Capacity:

AnnualProduction capacity of 600,000 tons.

Products areexported to United States, Canada, U.A.E, Brazil, Mexico,Thailand, Vietnam,Nigeria  etc, over 100 countries andregions all over the world.


Production Line:

CNBM aluminumproduction base is comprised of 18 aluminumannealers, 10 coil and foilmills, 4 continuous production lines, 2hot rolling production line and 3prepainted lines.


FAQ:

1.     What is the form of payment?

Normally 30% TT, L/C

2.     Type of quotation?

FOB, CFR, CIF

3.     Port of loading?

Shanghai port

4.     Delivery time?

30 days after client’s deposit


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Q:Is it unsafe to use deodorant with aluminum?
Aluminum, okorder.com/
Q:Removing electrons from Aluminum?
One approach to this can use the density of aluminum to find the mass of the1 cm³ block. The density of aluminum is 2.70-g/cm³ so your cube has a mas of 2.70-g. The number of aluminum atoms in this block is: 2.7-g Al x (1 mol Al / 27.0-g Al) x (6.023 X 10²³ atoms Al / 1 mol Al) = 6.023 x 10²² atoms Al. Each Al, as you pointed out, contains 13 electrons so we have 6.023 x 10²² atoms Al x 13 electron/atom = 7.83 x 10²³ electrons. 1 x 10¹² pC = 1 C and 1 C = 6.24 x 10¹⁸ electrons=== 1.5 pC x (1C / 1 x 10¹² pC) x ( 6.24 x 10¹⁸ electrons / 1 C) = 9.36 x 10⁶ electrons a.) % removed = 9.36 x 10⁶ / 7.83 x 10²³ x 100% = 1.2 x 10⁻¹⁵ % b.) Each electron has a mass of 9.11 x 10⁻²⁸-g , so the total mass removed =9.11 x 10⁻²⁸-g/elec x 9.36 x 10⁶ electrons = 8.53 x 10⁻¹⁴-g. Thus the % decrease is (8.53 x 10⁻¹⁴-g/ 2.7-g) x 100% = 3.16 x 10⁻¹² %
Q:can you weld metal to aluminum?
aluminum to steel? short answer No and you will end up with a lot of mess and splatter try J-B weld it's a product though it can be done with a certain process that I'm not familiar with I have seen the finished application but i think the aluminum is a different metal make up I have accidentally tried to weld the two together many times not realizing what the metals were use a magnet to test if its aluminum magnets wont stick to aluminum
Q:Anti-Perspirant without Aluminum?
addidas makes one ( only one of there kinds is aluminum free, you have to look at the labels carefully) ... it smells clean, man or women can use it. There is a brand called JASON as well that is all natural... thoes are the only 2 worth a darn. Ive tried others but they suck. Addidas is probably stronger if that is your concern. I have both in my bathroom right now, my husband and i both use them.
Q:Can aluminum coil 3003H24 replace 3A21H14?
Yes.
Q:How can aluminum rolls prevent oxidation? One hundred
In general, aluminum itself. You said that the antioxidant warehouse is wet, there are other acidic substances damage the alumina compact protection film. Aluminum volume convenient paint, or wrapped in a plastic film, the best conditions inside the silicon desiccant
Q:What would life be like without aluminum?
Airplanes would be too heavy to get off the ground. Howard Hughes built an airplane out of wood called the Spruce Goose. It couldn't get more than 20 feet off the ground and only went about a half mile. Aluminum is the lightest weight metal in relation to it's tensile strength.
Q:Calculate the mass in grams of iodine (I2) that will react completely with 43.7 g of aluminum (Al) to form alu?
Aluminum Iodide is AlI3 - one aluminum atom bonded to three Iodine atoms. Look up the atomic weight of Aluminum. Look up the atomic weight of Iodine. Al / 43.7g =3 X Iodine / mass Mass of Iodine required = 43.7 X Atomic weight of Iodine X 3 / Atomic weight of Aluminum
Q:Aluminum coil Kaiping is out of arc plate, what's the matter?
Aluminum coil Kaiping need to use "stretch bending straightening machine" to do leveling, before they can be leveled
Q:Heat, vaporization, and melting points of aluminum.?
Calculate the quantity of energy required to heat 1.58 mol of aluminum from 33°C to its normal melting point in KJ- 1.58 mol x 26.98 g/mol x 0.902 J/g°C x (658 - 33)°C x 1 kJ/1000 J = 24.03 kJ Calculate the quantity of energy required to melt 1.02 mol of aluminum at 658°C In KJ- 1.02 mol x 26.98 g/mol x 3.95 kJ/g = 108.7 kJ Calculate the amount of energy required to vaporize 1.02 mol of aluminum at 2467°C In KJ- 1.02 mol x 26.98 g/mol x 10.52 kJ/g = 289.5 kJ

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