Yellow Aluminum Foil

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FAQ

I have two glass tubes; one male, and one femaleMy problem is that the female end has an inner diameter that is very slightly too small, or that the male end has an outer diameter that is slightly too wideI have to work on these two components because I already spent the money on themso what to I use to sand 'em down? I need something with which to grind down the glass of either piece by just a half of a millimeter or so.Since they're tubes, it would be easier to reduce the diameter of the outside of the male end, but there is less glass to work withThe thicker female component would be preferable, but then there's the issue of managing to grind the inner surface of a tubeThe diameter in question is just a tad over a half an inch, and the length needed is about an inch and a half.

There is the braided stitchIt's thickerGoogle it, I'm on an iphonelol

1determine the value of h,r and hence calculate the ratio of h/r when the total surface area of each tin is minimum.here,h cm denotes the height and r cm the radius of the tin.2the t0p and bottom pieces of height h cm are cut from square-shape aluminium sheets.determine the value for r,h and hence calculate the ratio h/r so that the total area of the alumium sheets used for making the tin is minimum.(refer to the diagram the aluminium sheets used for making the tin is minimum.3investigate cases where the top and bottom surfaces are cut from;i)equilateral triangle.ii)regular hexagon.find the ratio of hj/r for each cases.further investigationinvestigate cases where the top and bottom faces of the tin are being cut from aluminium sheets consisting shapes of regular polygons.from the results of your investigation,what conclusion can you derive frrom the relationship of the ratio h/r and the number of sides of a regular polygon?

1Here is the first partWhat is the ratio of the height to the radius of a can that has minimum surface area for a given volume? r radius can h height can V volume S surface area V πr?h S 2πr? + 2πrh Solve for hV πr?h h V/(πr?) Substitute into SS 2πr? + 2πrh 2πr? + 2πr{V/(πr?)} 2πr? + 2V/r Take the derivative of S to find critical valuesS 2πr? + 2V/r dS/dr 4πr - 2V/r? 0 4πr 2V/r? 2πr V/r? r? V/(2π) r {V/(2π)}^? Take the second derivative of S to find the nature of the critical valuesdS/dr 4πr - 2V/r? d?S/dr? 4π + 4V/r? 0 since both terms are positive This implies a relative minimum, which is what we wantSolve for hh V/(πr?) 2V/(2πr?) (2/r?)(V/2π) (2/r?)(r?) 2r h 2r Ratio of h/r h/r 2r/r 2

I need to cook a 20-22lb bird on my gas BBQHow can I cook such a large bird without it becoming dry? Do I need to cover it with aluminum foil? What temp and for how long? Any receipts and advice for injecting flavors would be great tooI’d like to know the largest bird you’ve grilled, how it turned out and if you’d do it again.

Yes, you can, but you really need to use INdirect heatlight one side of grill, but put turkey on the otherStart it breast side down, then flip about half-way thru cookingYou REALLY need a meat thermometer to be sure it's doneA pan of water in there wouldn't hurt it staying moist, either.

Aluminium metal can reduce the hydrogen ions in a solution of hydrochloric acid to hydrogen gas, according to the equation:2Al(s) + 6H+(aq) -gt; 2Al3+(aq) + 3H2(g)a) Write half equations for the oxidation and reduction processes involved in this reaction.b) Use these half equations to explain why six hydrogen ions are reduced for every two aluminium atoms oxidised.I can do part a alright but I don't know how to answer part b and it seems so simple but I just don't get it! Any help will be appreciated and thanks in advance :)!

A) Aluminium is oxidized: Al - Al3+ + 3e- Hydrogen is reduced: 2H+ + 2e- - H2 Now, you have to balance to number of electrons, aluminium gives three, hydrogen takes two, so the least common factor is sixHence: 2Al - 2Al3+ + 6e- 6H+ + 6e- - 3H2 From the above two equations, you have see that for every two aluminium atoms, six hydrogen ions are reducedI really hope I helped

Here are the following questions: Please answer even if you only know 1:My name is very hard to pronounce, it is from the Greek meaning quot;hard to get atquot;I was discovered in France by Boisbaudran, my density is 8.56g/cm3My abundace in the earth's crust is 6.0x10-7Who am i?I make up about .93% of dry airMy heat capacity is 5.00cal/g`CI am colorless, odorless and tastelessFoods retain their normal flavorand color when I am used in packaging themI am also found in light bulbsWho am I.I am sometimes extracted from bonesI am a non-metal and i have an electronegativity of 2.1My atomic radius is 0.154My boiling point is 280`C and I was discovered in GermanyWho am I?I have been found hanging around MtPinatubo in the PhilippinesI am a light yellow non metal with a boiling point of 444`CI have a metling point of 1128`C and am used in matches, tires, and insecticidesWho am I?

Living on your own is very hard to do when you are just starting offMost likely you will move out and fail and have to go back to living with your parentsBut if your mind is really set on moving out then what you really need is to find a roommate who is dependable and who will split the rent with youGood luck!!

How to ues aluminum foil container?

Aluminum Foil Container uses: easy to use, easy to shape, health and safety, no smell, no leakage; have good thermal conductivity and uniform heating effect, can be used for oven, oven, steamer and heat sources such as heating directly on the original packaging . Aluminum foil container can withstand temperatures of 240 tall, used in fast food restaurants, take-away match shops, family kitchen, luxury hotels, as well as civil aviation enterprises and packaging food-related service industries.

Well, you know how when you take aluminum to some places, you can trade them in for a small amount of cash? (It's never a lot, but you can get a few bucks from a garbage bag full)Well, why is it that only aluminum is the only thing that brings in that small bit of cash?If we were to have cash trades for papers and plastics, wouldn't recycling rates go up?So, what is the reason why only aluminum is bought back, and not other recyclables, like glass or plastic?

I happen to work in the recycling businessThe answer is an incredibly simple oneSupply and demandThere is a huge demand for aluminum compared to supply, thus the higher priceAlso the processes for recycling paper and plastic and glass generally cost more than using virgin materials thus demand for recycled paper,plastic and glass is lower amongst companies that use those products for packaginggood old econmics 101 As to how to change this situation.well thats the 64 million dollar question as they say.

Anyone out there know any tricks?I have a edelbrock performer intake and the threaded hole for the temp sensor has a steel plug that's refusing to come out and will likely just strip the hex shapeI hear aluminum can corrode to the steel

As long as it's not international.