Q:A man of mass 74.4 kg stands on a scaffold supported by a vertical rope at each end. The scaffold has a mass of 21.9 kg and is 3.9 m long. Suppose the man stands to the right from the middle of the scaffold that is a distance one sixth of the length of the scaffold. What is the tension in the right rope? b) What is the tension in the left rope? thanks in advance.

this could be a 2d concern. The moments approximately any factor interior the gadget would desire to stability, in the different case the gadget (scaffold) would rotate. additionally, the vertical forces would desire to stability, or the gadget (scaffold) would translate. it form of feels to me that to the superb from the middle of the scaffold it somewhat is a distance one 6th of the dimensions of the scaffold is comparable to saying 2-thirds from the left-edge of the scaffold. The moments could be summed approximately any factor. i will evaluate the left facet of the scaffold, the place the 2d produced by the left rope is 0. comprehensive M = 0 = scaffold M + guy M + suited rope M 0 = 23.7kg*9.8m/s^2*(3.1m/2) + 60.1kg*9.8m/s^2*(2*3.1m/3) - F*3.1m wherein: the scaffold is considered a factor mass located at its center the strain F acts opposite to the load of the guy and the scaffolding, and subsequently has -ve sign remedy for F. To get the strain in the different rope, you are able to basically evaluate the vertical forces interior the gadget. on the different hand, you should sum the moments approximately another factor (say, the superb rope). wish this permits.

Q:PLEASE HELP!!!!!

maybe because her partner in crime was in the crowd and she didnt give- that takes some big balls

Q:There is a 6.0-kg pail of paint to one side.How close to the left end can he approach safely? How close to the right end can he approach safely? Can someone help me with this problem, I keep working and reworking it and coming to the same answer. I must be consistently making the same mistake. If someone can help me work through it I would really appreciate it. The answers I got were:Left: dmin, left = .54mRight: dmin, right = .77m

At the threshold of danger, the tension on the far rope reaches zero. (a) Distance from left edge = x; then summing moments about the left rope gives ΣM = 0 = 71.0kg * g * (1m - x) - 22.0kg * g * 2.0m - 6.0kg * g * 1m The g term cancels, and the rest solves to x = 0.296 m ? (b) Distance from right edge is X; summing about the right rope, and knowing the g terms will cancel, ΣM = 0 = 22.0kg * 2m + 6.0kg * 3m - 71.0kg * (1m - X) leads to X = 0.127 m ? Hope this helps!

Q:A 531 N window washer is standing on a scaffold supported by a vertical rope at each end.The sca?old weighs 332 N and is 3.5 m long.Assume the window washer stands 1.36 mfrom the left end.What is the tension in the rope on the right?Answer in units of NWhat is the tension in the rope on the left?Answer in units of N

(332 N)×(3.5 m)/2 + (531 N)×(1.36 m) = (3.5 m)×R R = 372.3 N < - - - - - - - - -tension in the right rope (531 N) + (332 N) = (372.3 N) + L L = 490.7 N < - - - - - - - - - tension in the left rope

Q:There is no shelter outside the scaffolding project has been accident accident case

I do not know what the problem you said is not clear, to send the following to you, for your reference: [Case 1] a single industrial plant project, eaves high 20m, construction area of ??5800m2

Q:Investment to do a steel pipe fastener leasing company, generally need to invest how much money? What conditions and procedures are required? Please help. Please help from the human, financial, facilities, steel, fastener configuration to help answer. Greatful

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Q:How to do a good job of typhoon during the mass transfer mobilization work

Such as: all kinds of dangerous housing, plant, shed, temporary buildings (such as walls, etc

Q:What would you like to ask?At what height do scaffolds have to be engineered?

At all heights...they are engineered as a system.

Q:Two window washers, Bob and Joe, are on a 3.00 m long, 380 N scaffold supported by two cables attached to its?

Oh, Ashley, you can't fit more than an intro in the what would you like to ask. More room in details.

Q:I live on a 2nd floor apartment with gorgeous, huge, arched windows. Until a week ago, we had a lovely view of a tree-lined street in NYC, but my building just installed a scaffolding which almost acts as a balcony for us. Our view is gone, and there is definitely a safety issue as anyone could climb off the scaffolding into our apartment through the windows. The windows are so old, and cannot fully lock unless wedged shut - and then we cannot open them for any kind of ventilation.There is work being done on the building and the super says the scaffolding will be up for at least a year.As a tenant, what rights do I have? I want to call my landlord and ask for a rent reduction as these windows were a huge spelling point at the time of rental. I am also worried that someone will enter my apartment during the day when I am not here. We have been here happily for 5 months, but this is really upsetting. Any advice on what I should do?

The scaffold is necesary, and already thre, and probably not coming down. I would think you have to LET the Land Lord give you a deal, and any decent LAnd Lord should respect wishes. You may have to move, but a deduction, possibly. Security, demand it ! Get the windows fixed, and if you are really unsure of the scaffold and window, get renters insurance, it's just twenty bux a month !. or buy a big DOG