Product Description:
Safety Guarranteed Salt Strage Silo,Assured 30 Years Lifespan
Main Structure of Salt Storage silo
Condition: New
Capacity: 5015000m3 for salt strage silo
Material: Steel
Dimension(L*W*H): As per size of salt strage silo
Weight: As per size of salt strage silo
Usage: Salt Strage Silo
Technology: China Leading,Germany
Silo Materials: Hot Galvanized Steel
Galvanized Coating: 275600g/m2
Bottom Type: Flat or Hopper Type
Gastightness: Perfect Gastightness
Auxillary System:Drying,Cleaning,Dedusting,Lifting and Conveying
Monitoring System: Temperature and Moisture Supervision SIMENS PLC
Silo Life: 2540 Years for Salt Strage Silo
Installation and Debugging: Engineers Sevice Overseas for Salt Strage Silo
Main Specification of Salt Storage Silo
Details  Materials  Quality Standard  Features 
Body Plate  By Hot Dip Galvanized Steel Plate, 275600g/m2 Galvanization  China National Standard with Quality Report  Corrugated Our Corrugated Steel Plate Production Line is IMPORTED 
Bolts and Screws  Hot Dip Galvanized, Taiwan Imported, Strengthened, Max Sealing  Quality Strength Report  Imported from Taiwan 
Enforcement Rib Stiffeners  Sidewall stiffeners are manufactured from min. 350 N/mm² tensile high strength steel with zinc coating of 275 g/m². This type of stiffeners easily transit the vertical loads during loading or unloading, environment loads of the silo.  China National Standard with Quality Report  Can be inside or outside rib Rigorous calculation to meet full silo strength safety 
Wind Ring  Hot Dip Galvanized For additional support for higher wind areas, the wind ring is attached directly to the stiffeners. The rings strengthen the silo providing reinforcement against damaging wind.  China National Standard with Quality Report  Rigorous calculation to meet the antiwind needs for sea port area or windy area 
Manhole  A standard manhole door is located in the second ring of the silo. Double size door with strong frame and block system  China National Standard with Quality Report  Easy for the ascendant to inspect and maintenance, ensure the safety of the silo. 
Stairs  SRON offers both ladders and stairs as outside climbing options. Stairs offer a shallow 8” step that decreases the incline angle for an easier, safer, and more comfortable climb.  China National Standard with Quality Report  Can be installed inside and outside of the silo, Easy for the ascendant to inspect and maintenance, ensure the safety of the silo. 
Inside Ladder  Ladder inside silo, simple vertical or cage type ladder are available for your choice  China National Standard with Quality Report 

Datas for Salt Storage Silo
Bottom shape  Hopper Type  Flat Bottom Type 
Capacity  ≤1500t  ≥1500t 
Design view  Heavy structural “wideflanged” columns Columns designed “X” bracing Pressure bearing is higher than the national standard, and safe enough.  Can be built by concrete or steel based on your requirement and actual demand. 
Silo Discharge  Hopper is with Rigorous Full Load Safety Calculation. SRON has 0 Silo Hopper Accidents and 0 Silo Accidents Can be made by concrete or steel  There will be one or more discharge holes on the bottom based on different materials and capacity. 
Sweeper  Normally no need sweeper for hopper bottom silo except for high viscidity materials  Clean up residual easier China Famous Brand or France Brand 
FAQ
Why should you choose us:
Any of Your Problem is the Top Urgency
WE SHALL BE RESPONSIBLE FOREVER FOR ANY SILO WE CONSTRUCT. AND FOREVER TECHNOLOGY SUPPORT FOR YOUR GRAIN SAFE STORAGE
Your Correspondence Must Issue Communication/Solution for Your Request within 24 Hours Due to International Time Difference, We Beg Your Pardon if Our Correspondence Fail to Respond Timely and Please Do Complain to Help Our Improvement.
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 Q:Where are American missile silos located?
 You don't know for a reason... Your handle is an insult to Every Black American... just shows how really ignorant you are... Jealous because you can't get off your Fat A*s and build a Multi Million Dollar Corporation...?? Shows the only thing holding you back...is you !!!! He followed through on MLK's dream... all you do is ***** and complain...
 Q:Grain leaving conical silo?
 Calculus problem... i'm going to use V for Volume and v for velocity 1) figure out how much volume is flowing through the opening assuming the opening is round, d=.4m and h is constantly changing dV/dt = A*v = pi*.4^2/4*(2*g*h)^.43 (m^3/s) V(dot) = .126*(19.62*h)^.43 = .453*h^.43 (m^3/s) V(dot @ h=40) = 2.21 m^3/s V(dot @ h=14) = 1.41 m^3/s 2) Volume of a cone = pi*d^2*h/12 (www.grc.nasa.gov/WWW/K12/airplan... V(40m) = 104.7*40 = 4188 m^3 for at V(14m), take the ratio of diameters ==> 20/40 = d/14 therefore d(14m) = 7 m V(14m) = 179.6 m^3 Change of Volume = 4188180 = 4008 m^3 I'm stuck, hope I could give you a start.
 Q:what would it cost to demo and dispose of concrete foundations ?
 A small fortune for sure . 40 thousand would be a conservative guess . Why not knock the foundation into its own hole and bury it . Same with rest , dig a hole beside slab , cut it up and bury it .May cost 15  20 thousand . Good luck !~
 Q:Solid Geometry / Solid Mensuration?
 There's no diagram provided, but it seems the storage capacity of the silo is equal to the volume of the lower cylinder, plus the volume of the frustum. (Since the upper cylinder is part of the cupola, we won't count it as part of the silo's storage capacity.) Let C = the volume of the lower cylinder, and Let F = the volume of the frustum. Now, C = πr^2 h We're given that r = 12, and h = 21. So, C = π(12^2)(21) = 3,024π ft^3 The frustum is like a cone with its top part sliced off. The baseradius of the cone is 12 ft. The top part, sliced off, is a similar, smaller cone with baseradius 6 ft. If we let y = the height of the slicedoff cone, and consider the triangular crosssection of both cones, then, by similar triangles, (y + 6) / 12 = y / 6 => 2y = y + 6 => y = 6 So, the height of the larger cone is 6 + y = 12, and the height of the slicedoff cone is y = 6. (Recall again we're given that the baseradius of the larger cone is 12, and the base radius of the slicedoff cone is 6.) Then, the volume of the frustum is the volume of the larger cone, minus the volume of the slicedoff cone: F = (1/3)π(12^2)(12)  (1/3)π(6^2)(6) = 504π ft^3 Our total volume V is: V = C + F = 3,024π + 504π = 3,528π ft^3
 Q:anyone know cheat codes for command and conquer?
 Unlockables conflict Honors a thank you to benefit right here Skirmish Awards.Unlockable a thank you to unfastened up Air Wing Honor construct 20+ plane in a solo or multiplayer venture Apocalypse Honor construct each and all of the excellent weapons conflict Tank Honor construct 50+ Tanks in a solo or multiplayer venture Blitz Honor Defeat an enemy in under 10, 5, or 3 minutes. China marketing campaign Honor finished China's marketing campaign Mode persistence Honor finished all Skirmish maps GLA marketing campaign Honor finished GLA's marketing campaign Mode Streak Honor Win 3, 10, or 30 suits in a row. u . s . a . marketing campaign Honor finished u . s . a .'s marketing campaign Mode Contributed by potential of: Biospark3 participant score those are the scores which could be finished by potential of polishing off particular standards. Win: 3 factors Lose: 0 factors Disconnect: a million pointsUnlockable a thank you to unfastened up Brigadier prevalent 500 factors needed Captain 50 factors needed Colonel 2 hundred factors needed Commander in chief 2000 factors needed Corporal 5 factors needed prevalent one thousand factors needed Lieutenant 20 factors needed significant a hundred factors needed private 0 factors needed (gained after a million conflict) Sergeant 10 factors needed Contributed by potential of: Biospark3 secrets and methods honest Play Multiplayer Honor To get the multiplayer honor for honest Play, you've gained, lost, surrendered, or exited utilising frequent activity channels at a ninety% fee for a minimum of 10 finished video games. Contributed by potential of: XxThunderxX great Blitz Badge The ordinary blitz badge is for beating a skirmish under 10 minutes. whether, you may get the comparable badge with a 5 on it as a replace of a 10 in case you beat it in 5 minutes Contributed by potential of: fcs
 Q:A silo consists of a right circular cylinder of diameter 4 m. and altitude 6 m.?
 The volume of a cylinder is given by the formula: V(cylinder) = pi r² h r = 4, h = 6 Hint: 96 pi :D The volume of a cone is given by the formula: V(cone) = 1/3 pi r² h r = 4, h = 3 Hint: 1/3 * 48 pi = ? I can plug in the numbers, but you can solve it just as easily. Hint: A multiple of pi that has three digits. Two are 1 and one is 2. :)
 Q:Does the UK have nukes?
 You do not have enough points to know about this.
 Q:find minimum?
 Let V = volume of silo V = volume of hemisphere + volume of cylinder Volume of hemisphere = (2/3)(pi)r^3 Volume of cylinder = (pi)r^2h where r = radius of cylinder = radius of hemisphere h = height of the cylinder Since V = 100, 100 = (2/3)(pi)r^3 + pi(r^2)h and solving for h h = (100/(pi*r^2))  (2r/3) S = Surface area of silo = surface area of hemisphere + surface area of cylinder Surface area of hemisphere = 2(pi)r^2 Surface area of cylinder = pi(r^2) + 2(pi)rh Therefore, S = 2(pi)r^2 + pi(r^2) + 2(pi)rh since h = (100/(pi*r^2))  (2r/3) and substituting it in the above equation, S = 2(pi)r^2 + pi(r^2) + 2(pi)r[100/(pi*r^2))  (2r/3)] Simplifying the above, S = 2(pi)r^2 + [(pi)r^2 + 200/r  2(pi)r^2/3] S = 2(pi)r^2 + [(1/3)(pi)r^2 + 200/r] Since cost of hemisphere is twice that of the cylinder, then C = cost = 2*2(pi)r^2 + 1*[(1/3)(pi)r^2 + 200/r] C = 4(pi)r^2 + (1/3(pi)r^2 + 200/r C = (13/3)(pi)r^2 + 200/r Differentiating C with respec to r, (dC/dr) = (26/3)(pi)r  200/r^2 and setting (dC/dr) = 0 and solving for r, (26/3)(pi)r  200/r^2 = 0 Simplifying the above, 26(pi)r^3 = 600 Solving for r, r = 1.94 meters Now, that r is known, h can be determined by using the above derived formula of h = (100/(pi*r^2))  (2r/3) Substituting r = 1.94. h = 7.16 meters Dimensions of the silo are: r = 1.94 m h = 7.16 m CHECK: First check: V = (2/3)(pi)(1.94)^3 + pi(1.94)^2(7.16) V = 15.3 + 84.7 = 100 m (this checks with the original condition of the problem that the volume of the silo is fixed at 100 m^3). Second check: Take the second derivative of the original function, i.e., (d^2C/d^2r) = 400/r^3 and since the second derivative is positive (greater than zero), then it confirms that the calculated dimensions for r and h will indeed yield the minimum cost.
 Q:Many good Americans died fighting Hitler and racism. Why would their children vote for Trump now?
 Somewhat of a stretch there, simpleton, but I understand your fear. Trump is soooo scary.
 Q:how do you put a starter silo id on a 85 ford ranger?
 Very easy, its right by your batt. Clean all the connections on it first, it may just be coroded.
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