Commercial Galvanized Iron Wire

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Product Description:

Commercial Galvanized Steel Wire

(1) Quality : Meet GB/T 343 standard and other requirements of relevant standards .

(2) Zinc Coating: Meet GB/T 15393 standard and other requirements of relevant standards .

(3) Raw Material : Wire rod ——1006 , 1008 , 1018 , Q195 , etc, and zinc with 99.995% purity.

(4) Tensile Strength Range

Size (mm)

Tensile Strength (mpa)

0.15-1.60

290-550

0.65-1.60

400-550

1.61-6.00

400-1200

(5) Application : Used in wire mesh , artware , metal hose , binding for agriculture and construction , etc.

(6) Packing

Size (mm)

Coil Size

Spool Packing

Big Coil Packing

ID (mm)

OD (mm)

0.15-0.26

6 inch

1-14kg/spool

0.27-0.60

8 inch

1-100kg/spool

0.61-1.60

12/14/16 inch

1-100kg/spool

250-400

400-770

1.61-6.00

14-500kg/spool

450

800

508

840


(7) Zinc Coating

Meet GB/T 15393 standard.

Size (mm)

Weight of Zinc-Coating ( g/m2 )

A

AB

B

C

D

E

F

A1

B2

0.25

30

20

18

>0.25-0.40

30

25

20

>0.40-0.50

30

20

>0.50-0.60

35

20

>0.60-0.80

120

110

40

20

>0.80-1.00

150

130

45

25

>1.00-1.20

180

150

50

25

>1.20-1.40

200

160

50

25

>1.40-1.60

220

180

50

35

30

>1.60-1.80

220

180

70

40

30

>1.80-2.20

230

200

80

50

40

>2.20-2.50

240

210

80

55

40

>2.50-3.00

250

230

90

70

45

>3.00-4.00

270

250

100

85

60

30

>4.00-5.20

290

270

110

95

70

40

>5.20-6.00

290

270

245

110

100

80

50


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Here okorder.com/
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Q:Tension in both wires?
The tension in both wires.? If you hang a pot-plant with mass of 8kg from two lengths of wire attached to a horizontal beam 100cm apart. The wire on the left has a length of 50cm and the wire on the right has a length of 75cm. What is the tension in both wires? In the triangle ABC, AB(c) = 100 cm, BC (a) = 50 cm and AC (b) = 75 cm 2s = a+b+c = 225 cm s = 112.5 s-a = 112.5 - 50 = 62.5 s-b = 112.5 - 75 = 37.5 s-c = 112.5 - 100 = 12.5 tan A/2 = √ {(s-b)*(s-c) / [s*(s-a)] = √ {37.5*12.5) / [112.5*62.5] A = 28.95º tan B/2 = √ {(s-c)*(s-a) / [s*(s-b)] = √ {12.5*62.5) / [112.5*37.5] B = 46.57º C = 180-28.95-46.57 =104.48º --------------------------------------... 46.57º is the angle between horizontal and 50 cm wire. 28.95 is he angle between horizontal and 100 cm P is the tension in the 50 cm wire and Q is the tension in the 75 cm wire Equating the horizontal components of the tensions P cos 46.57º = Q cos 28.95 º P = Q cos 28.95 º/ cos 46.57º P = 1.27 Q-------------------1 Equating the sum of the vertical components of the tensions to the weight of the pot P sin 46.57º + Q sin 28.95 = 8*9.8 N 0.73P + 0.48 Q = 78.4N 0.73(1.27 Q) + 0.48 Q = 78.4N Q = 55.72 N and P = 70.76 N ============================= Or use Lamis theorm Angle between P and Q = 104.48º Angle between P and the pot = 90 + 46.57º Angle between Q and the pot = 90 + 28.95 By Lamis theorm P/ cos 46.57º = 78.4/ sin 104.48º P = 55.67 N and Q = (78.4/ sin 104.48º ) cos28.95 = 70.85N ====================================
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tricky subject. check out from bing and yahoo. this can assist!
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