Carbon Black Precipitated Silica

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Tianjin
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TT OR LC
Min Order Qty:
-
Supply Capability:
10000MT m.t./month

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Product Description:

                                        Precipitated Silica

Product Description:

Precipitated Silica
1.Used in tires, tire body, with beam layer and sidewall rubber and rubber products,Shoes Etc.

2.Product Status:White powder

Suggest for Use:

(1) M160 Used in tires, tire body, with beam layer and sidewall rubber and rubber products.For strengthening filler in rubber, rubber formula provides high hardness, high breaking strength, high tear strength and high wear resistance, improve the rubber and steel cord bonding strength. Improve the durability of the rubber, to improve flexible and shock resistance, resistance to improve tractional snow tires on the road, improve the tire all-weather performance.

(2) M170 Used in tires, rubber products and sole material.For strengthening filler in rubber, rubber formula provides high hardness, high breaking strength, high tear strength and high wear resistance, and resistance to aging performance.

(3) M180 Used in shoe materials, rubber products. For strengthening filler in rubber, in color rubber products, instead of reinforcing carbon black, meet the needs of white or translucent product, it has strong bonding strength, tear resistance and heat-resistant anti-aging performance.

TDS of the Precipitated Silica  Standard: GB3778-2003

Product Varieties

M160

M170

M180

Nsa Surface Area(m2/kg)

160+15

170+15

180+15

Silica Content%

93

93

93

Color

Better than Standard samples

45um sieve residue

0.5

0.5

0.5

Heatloss(%)

5.5±1.0

5.5±1.5

5.7±1.0

LOI %

6.0

6.0

6.0

PH Value

6.7±0.3

6.2±0.5

6.7±0.3

DBP absorption Value (10-5m2/kg)

2.20±0.10

2.55±0.10

2.20±0.10

Conductivity us/cm

900

900

900

Cu mg/kg

30

Mn mg/kg

50

Fe mg/kg

1000

Safety:

As a matter of good industrial hygiene, gloves and safety glasses with side shields or better eye protection should be worn when handing Carbon Black ,For more information, refer to the MSDS.







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Q:Is the chemical reaction rate constant related to the amount of catalyst used?
The decomposition of hydrogen peroxide, manganese dioxide in addition to the catalyst, but also in which it can be considered a carrier (from the surface of manganese dioxide to emit small bubbles, you should be able to see), so the amount of more than certainly can speed up the reaction.
Q:why is palladium/platinum a good catalyst?
I'm guessing that the answer would be heterogeneous. Hydrogenation reactions use Pt and/or Pd metal as the catalyst. But these are always solids while the reaction is between H2 and either a gas or a liquid. Consequently the catalyst is in a different phase than the reactants, making them heterogeneous. I'd go with that one.
Q:Compare and contrast enzymes and catalysts?
enzymes are a type of catalyst
Q:The concept of catalyst in high school chemistry
Since the catalyst can only change the chemical reaction rate, the catalyst can not increase the mass of the product. The quality of the product depends only on the quality of the reactants.
Q:Does the nature and quality of the catalyst itself change before and after the chemical reaction?
No, but in some cases it may produce catalyst poisoning
Q:Explain how a catalyst may increase the rate of chemical reaction?
A catalyst lowers the activation energy of a reaction without affecting the reaction in any way.
Q:Catalyst and Intermediate.?
Cl is the catalyst. ClO the intermediate. The catalyst is the component which does not change in overall reaction. He forms some intermediate component(s) with the reactants. In the later reaction steps the intermediate(s) react forming the catalyst in its original state. (a) The overall order is the sum of the orders with respect to the components: n = 1 +1 = 2 (b) the unit of the rate of reaction is r [=] mol/ (Ls) (more general mol per unit time and volume) compare dimensions mol / (Ls) [=] k · mo/L · mol/L =k [=] L/(s mol) (more general unit volume per unit time and mole) (c) First reaction For elementary reaction steps the order of the reaction rate with respect to a reactant is equal to stoichiometric coefficient. Hence the rate of first reaction is: r₁ = k₁·[Cl]·[O₃] Overall rate is given by the rate determining step, while other reaction steps are in equilibrium: r = r₁ = k₁·[Cl]·[O₃] If second reaction is the rate determine step r₂ = k₂·[O]·[ClO] while reaction 1 is at equilibrium K₁ = ( [ClO]·[O₂] ) / ( [Cl]·[O₃] ) =[ClO] = K₁·( [Cl]·[O₃] ) / [O₂] the overall rate would be: r = r₂ = k₂·[O]·[ClO] = K₁·k₂·[O]·[Cl]·[O₃] / [O₂] = k·[O]·[Cl]·[O₃] / [O₂] That doesn't match the observed rate law
Q:Carbon monoxide and nitrogen dioxide in the catalyst conditions of the chemical equation
2NO2 + 4CO = catalyst = N2 + 4CO2
Q:What are the methods of catalyst characterization?
Physical means, is commonly used detection means, infrared, ultraviolet, electron microscopy, X-ray diffraction, nuclear magnetic, etc., of course, including a variety of conventional inability analysis.
Q:Which chemical reaction is added to the catalyst in order to slow down the reaction
CaC2 and water reaction to ethylene plus salt water (slow chemical reaction rate)

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