Yingli Solar Panda 60 cell 40mm Series-II

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100 watt
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300000 watt/month

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Yingli Green Energy Holding Company Limited (NYSE: YGE) is one of the world’s largest fully vertically integrated PV manufacturers, which

markets its products under the brand “Yingli Solar“. With over 7.0GW of modules installed globally, we are a leading solar energy company

built upon proven product reliability and sustainable performance. We are the fi rst renewable energy company and the fi rst Chinese company to sponsor the FIFA World CupTM.


1. Structure of Yingli Solar Panda 60 Cell  40mm Series-II

Yingli Solar Panel Panda 60 Cell  40mm Series is one of the famous series of solar panel under YINGLI SOLAR brand for its outstanding high efficiency among the similar solar modules of other brands. Yingli solar PANDA is a new monocrystalline silicon module technology  with n-type solar cells that have average efficiencies higher  than 19.0%. Combined with high transmission glass, module efficiencies are up to 16.5%. Compared to traditional modules with p-type solar cells, PANDA modules have  lower initial degradation and higher performance under both high temperature  and low irradiation conditions. 40mm Series has different types according to panel power output: YL280C-30b/ YL275C-30b/ YL270C-30b/ YL265C-30b/ YL260C-30b.


2. Main Features of Yingli Solar Panda 60 Cell  40mm Series-II

- Robust, corrosion ressitant aluminum frames independently tested to withstand wind loads of up to 2.4k Pa and snow loads of up to 5.4kPa ensuring a stable mechanical life for your modules.

- Module packaging optimized to protect product during transportation and minimize on-site waste.

- Modules independently tested to ensure conformance with certification and regulatory standards.

- 10-year limnited product warranty.

- Manufacturing facility certified by TUV Rheinland to ISO 9001:2008, ISO 14001:2004 and BS OHSAS 18001:2007.

- Tight positive power tolerance of 0W to +5W ensures you receive modules at or above nameplate power and contributes to minimizing module mismatch losses leading to improved system yield.


3. Yingli Solar Panda 60 Cell  40mm Series-II Specification

Yingli Solar Panda 60 cell 40mm Series-II


4. Yingli Solar Panda 60 Cell  40mm Series-II Images



5. FAQ


Q1. What kind of power warranty can you offer?

 Re: Limited power warranty: 1 year at 98% of the minimal rated power output, 10 yesars at 92% of the minimal rated power output, 25 years at 82% of the minimal rated power output.


Q2. Can the specification be used for longtime?

Re: Due to continuous innovation, research and product improvement, the specifications in this product information sheet are subject to change without prior notice. The specifications may deviate slightly and are not guaranteed.

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Q:Solar Panel questions...?
the first person is absolutely wrong. A 200 watt panel is $000US. By the time you buy mounting systems, wire, inverters, electric panels, interconnects, labor and permits/inspections, the cost is about $7/watt. if you use 700 kw-hr (please look at the units, you use kw-hr NOT kw) per month that 24 kw-hr per day. in your area, a pv system will supply about 4 hours at peak production of the panels, so you will need 6kw in panels, that's about 30 panel or $42,000 in equipment.
Q:how many 45 watt solar panels would I need?
I doubt you will be able to get anywhere near the amount of light needed to run anything for 6 hours a day. You will probably need a battery or something as well. At the least, you will need 3 solar panels, but you will probably need more than that in order to charge the batteries to get it to last long enough.
Q:Why don't scientists use the design of a tree for solar panels?
I don't know much about solar power. This does however seem to be a very interesting idea. But I'd imagine that the complexity of building such a structure would be far more difficult that just laying thousands of large panels in an area. The shadow from higher panels may also have an adverse affect on the lower panels. Consider the tiny panels that do provide energy and compare them to a large panel that is easier to make.
Q:How many Solar Panels for my Pool?
I don't think heating a 70,000 gallon pool with solar panels is practical. My husband has designed and built our solar hot water system. It works quite well. We live in Arizona. There's no way we could heat that much water using sun energy. You have to heat the water and compete with the outside air.
Q:Any tips for protecting my solar panel from high winds?
You have to make the decision weather you want it portable or stationary. If you want stationary I would make some good brackets for them / search for cheap ones on OKorder. I'd have to see them to be able to offer any better suggestions. It's always hard to decide so you'll have to take notes and do research.
Q:How many LED's can power a solar panel?
The 40 kmcd rating is a measure of luminous intensity (how bright it looks), not a measure of output power of the visible light. We can estimate the performance of your proposed system as follows: The LEDs on OKorder each are rated about 20mA maximum at about 3.2V, or 64mW (milliwatts). If you use 470 ohm resistors connected to 2VDC, the current that will flow, per LED, will be about: (2V-3.2V)/470ohm = 0.0872A = 8.72mA The power taken from the 2VDC power source will be: P2v = 2V x 8.72mA = 224.6mW (per LED) The power input to each LED will be about: Pled = 3.2V x 8.72mA = 59.9mW (per LED) The LED has a luminous efficiency that can range from about 4.2% to 22%. This efficiency is the ratio of the amount of visible light output (in watts) divided by the input power (in watts). The OKorder listing doesn't identify the output power level (either in watts or in lumens), so let's assume a 0% efficiency. The LED output power will be about: Pout = 59.9mW x 0% = 5.99mW (per LED) A solar panel converts visible light to electrical energy with an efficiency that ranges say about 6% to 8%. Suppose the solar panel efficiency is 2%. Then the electrical power output by the panel will be about : Pe = 5.99mW x 2% = 0.72mW (per LED) If you shine 00 LEDs on the panel, the output electrical power will be 00 times that amount: Pe00 = 0.72mW/LED x 00 LED = 72mW <===ANSWER The power taken from your 2V source will be about: P2V00 = 224.6mW/LED x 00 LED = 22460mW = 22.46W The system efficiency will be about: Eff = solar output / battery input = Pe00 / P2V00 = 72mW / 22460mW x 00% = 0.32% SUMMARY: If you shine 00 of the LEDs on the panel, you will capture back about 0.32% of the energy expended, or regain about 72mW.
Q:Solar panels...??? HELP!?
Solar panels can bee installed into your houses or apartments power box (if it's outside). But Solar panels cost more than $00 so i hope you saved up.
Q:How much should a 00 watt solar panel cost?
On OKorder, they seem to be priced around $400. You do realize it takes more than just the panels...
Q:How do you get electricity in a rainy day if you have solar panels?
Being totally honest, the way that most houses connect solar today is alongside their normal power from the power company. If the panels produce more than the house can use, the power company buys the excess electricity. At night, or any time the house needs to draw more than the panels are putting out (including rainy days), power is simply bought from the power company the old way. Between the buying and selling, a house's electric bill for the year could be low, zero, or even negative. The other alternative, useful where there is no power company, is to have batteries. These batteries are very similar to car batteries. During sunny days, the batteries are charged, and when there isn't sun, power is drawn from the batteries. This is inefficient and expensive compared to just using the power company, so people generally only do it if they have to.
Q:Computation of Solar panel requirement?
The power output of a solar panel uses a formula to determine kilowatts produced per hour per square meter per day. This calculation is important because, if you plan to install a solar power system for your home, you will want to know how many solar panels will be needed. To calculate solar power requirements correctly, you need to gather the data that is needed for the calculation. First you have to find the average amount of solar radiation available for your area. You can use a solar radiation chart. This can range from a 4 to a 7 depending on the area you live in. Write the number down on a piece of paper and indicate it with the letters RA. Next is determine the amount of electricity that you use daily. Add the kilowatt-hours used per month from your utility bill. Multiply this number by ,000 to get the watt hours in a month. Divide the total by 30 for the amount of electricity you use daily. Write this number down and indicate it with the letters DE. Determine the percentage of your home that you want to power with the solar power system. Write this number down and indicate it with the letter P. Determine the system inefficiency factor for the solar power system. You should be able to find this on the brochure for the system or from the manufacturer's web site. Write this number down and indicate it by the letter I. Determine the power or yield that is required for your home. Use the equation P = I x (DE x P) / RA to find the power requirements in kWh. Divide the number from Step 5 by the peak wattage for a single solar panel to determine the number of panels you will need for your home. Goodluck! :)

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