Thin Aluminum Sheet Alloy used for Foil Stock

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5 m.t.
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100000 m.t./month

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Item specifice:

Grade: 1000 Series,2000 Series,3000 Series,4000 Series,5000 Series,7000 Series,6000 Series Surface Treatment: Mill Finish Shape: Flat
Temper: O-H112 Application: Door & Window,Decorations

Product Description:

1.Structure of Thin Aluminum Sheet Alloy used for Foil Stock

Aluminum Sheets are strengthened and cut from raw materials with different alloys, such as AA5005, AA5052, etc. They are easy for processing in different shapes, good in intensity and can be quickly installed. Aluminium Sheets for Energy Saving Curtain Walls are good in energy saving, weather resistance, fire resistance, easy for maintenance and with many colors.

Aluminium Sheets for Energy Saving Curtain Walls are widely used in construction of metal walls, metal ceilings, car decoration, advertizing panels, etc.

2.Main Features of Thin Aluminum Sheet Alloy used for Foil Stock

•High intensity

•Easy to be processed and shaped

•Weather resistance

•Anti-pollution & environment protection

3. Thin Aluminum Sheet Alloy used for Foil Stock Images

Aluminium Sheets for Energy Saving Curtain Walls

Aluminium Sheets for Energy Saving Curtain Walls

Aluminium Sheets for Energy Saving Curtain Walls

4.Specification of Thin Aluminum Sheet Alloy used for Foil Stock

Alloy Number



H12, H14, H16, H18, H22, H24, H26, H32, HO, F


0.1mm – 500mm


10mm- 2200mm


GB/T3880-2006, ASTM, ISO, EU standard


AWhat about inspections to guarantee quality?

For each order for Aluminum Sheets with Mill Finished Surface AA5XXX, we will arrange strict inspection for raw materials, inspection during production and inspection for finished goods.

With requirement of customers, we also can arrange the third party inspection.

BWhat about delivery?

We will put order for Aluminum Sheets with Mill Finished Surface AA5XXX in production schedule after order gets confirmed against copy of TT or L/C. Normally it takes about one month for production. Exact shipment schedule is different based on different sizes and quantity.

CWhat is the MOQ?

5 tons for each size.

D. Where have you exported aluminium sheets?

We have exported aluminum sheets to many countries. Main markets include South East Asia, Middle East, North America, South America, etc.

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Q:Excuse me: what's the weight of the 1 square 2mm thick aluminum sheet?
Know that the density of aluminum is 2.7 g / cubic centimeter or 2700 kg / cubic meterThen 2mm thick aluminium plate with a weight of 1 square meters is:M= P *v=2700*1*0.002=5.4 (kg)=5.4*10^ (-3) tonsThe price of aluminium is 30000 yuan / ton nowTherefore, the title of the money required should be 30000* (5.4*10^ (-3)) =162 yuanEmpathy,The density of iron is 7.8 KG/M3The density of stainless steel is 7.52-7.75 KG/M3The same is true of galvanized sheets, as long as the density is known
Q:Aluminium car body!!!?
Chemistry is all about how atoms exchange electrons. Some kinds like electrons better than others, and this is the basis of electrochemistry and Redox reactions. It all starts with the acid: HAcid - H(+) + Acid(-) The important thing is the H(+) ion, which is positive because it is a Hydrogen atom which has lost an electron. This leaves it with a positive charge, since it is nothing but a positive proton at this point. Fe + 2H(+) - Fe(+2) + H2 The above is a typical reaction between an acid and most metals. The H(+) ions strip an electron from the metal to form a metal ion and Hydrogen gas. What has happened is the Hydrogen ions have oxidized the Iron. The Iron in turn has reducted the Hydrogen. In terms of electrochemistry, there are two half reactions going on simutaneously. First, the Iron atoms generate two negative electrons: Fe - Fe(+2) + 2e(-) = OXIDATION OF IRON Then the Hydrogen ions combine with the electrons to form Hydrogen gas: 2H(+) + 2e(-) - H2 = REDUCTION OF HYDROGEN Note that in both reactions, the charges are equal on either side of the reaction. The next part of this process happens when the Iron ions come into contact with the Aluminum metal: 3Fe(+2) + 2Al - 2Al(+3) + 3Fe Note the Iron ions are recting exactly the same way the Hydrogen ions did. In other words, they are oxidizing the Aluminum. The Aluminum is now reducing the Iron. The net result of this is that the acid rusts the Iron and then the Iron rusts the Aluminum. The end result is the production of tiny amounts of Hydrogen gas, The Iron being displaced from where it had initially been, and the solid Aluminum discintegrating into some form of Aluminum salt. Calculations involve something called an electrochemical series and the voltage is given using the Nerst equation. Both the electrochemical table and the equation can be found in any chemistry textbook.
Q:Which kind of glue can bond hard shell plastic and iron sheet or aluminum sheet?
You can use 502, Alteco and other instant glue to bond plastic and metal, chloroprene rubber adhesive or glass cement are also ok.
Q:High quality Aluminum or Mediocre Carbon frames?
A combo of both is nice. But if I had the choice, I would go stiffer frame (aluminum) with carbon stays. For a carbon frame, the carbon has to be decent quality, not like the carbon that is used for making Raleigh frames. Low quality!
Q:Which explains aluminum's resistance to corrosion?
i would start by plugging in some of those key terms into wikipedia. it often has shockingly good engineering physics articles. there are really only 4 variables: exhaust tube, annealing furnace, age hardened aluminum alloy. play with those, and you might find terms that lead you to your answer
Q:An aluminum clock pendulum?
this concerns change in length of aluminum due to fall in temp T(20 C) = 2pi√(L20/g = 1 sec L20 = g/4pi^2 ----------- (1) T(-5 C) = 2pi√(L5/g L5 = T(5)^2*g /4pi^2 ----------- (2) coefficient of linear expansion of aluminum = alpha alpha = delta L/L* delta T 23*10^-6 = (L5 - L20) /L20*(- 5 - 20) (L5 - L20) /L20 = - 25*23*10^-6 L5/L20 = 1 - 25*23*10^-6 = 0.999425 --- (3) L5 decrease in length T(5) will reduce (2) / (1) L5/L20 = [T(5)^2*g /4pi^2] * [4pi^2/g] = 0.999425 [T(5)^2] = 0.999425 T(5) = 0.9997 sec this is period when in (-5 C) room a) pendulum gains time in cold room word gains is used because it takes less in 1 oscillation. b) it gains time = 1 - 0.9997 = 0.0003 sec in 1 sec gain in every hour = 0.0003*3600 = 1.08 sec
Q:Which is more reactive Aluminium or Nitrogen?
Q:I have a sleek aluminium stand for my laptop. How come the stand doesn't get any warmer as the laptop warms up?
Yes aluminium is a good heat conductor, which is why it is used as a heatsink to dissipate heat from electronic components like the CPU in you laptop. The idea of the aluminium stand for your laptop is to raise it up from the desktop surface, allowing air to pass between the gap and extract the heat from the aluminium stand as your laptop heats up with use.
Q:How much is left of the element Aluminum?
Aluminium is one of the most abundant Element on earth, ranking 3rd in the crust, second only to oxygen and silicon. And it is eminently recyclable. However, many minerals containing aluminium are not economically exploitable.
Q:a sample of aluminum chloride (AlCI3) has a mass of 37.2 g.?
You have to remember Avogadro's number: 6.02 x 10^23 Read about it in your text book. It is the number of molecules of any atom that make up 1 mole. 1 mole of a molecule is equal to it's atomic weight in grams. So, the atomic weight of aluminum is 26.9. So, 26.9 grams of aluminum contains exactly 6.02 x 10^23 molecules of aluminum (or 1 mole). What's the molecular weight of aluminum chloride? Well, 26.9 + 3(35.5) = 133.4 the 35.5 is the molecular weight of chloride and there are 3 of them. So, 133.4 grams of aluminum chloride would be 6.02 x 10^23 molecules. We only have 37.2 g. 37.2 g/ 133.4 g per mole = 0.279 moles. 0.279 moles x (6.02 x 10^23 molecules/mole) = 1.68 x 10^23 molecules of aluminum chloride. So, since there is one aluminum per molecule, you have your answer. Just multiply by three to find out how many molecules of chloride are present. Finally, if 133.4g = 6.02 x 10^23 molecules, then 1 molecule = 133.4 / 6.02x10^23 = 22.16 x 10^-23 or 2.216 x 10^-22 Make sure that the periodic table you use for class has the same values (some tables are more simplified then others). Also, make sure that you use the correct number of scientific digits when calculating your answer.

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