Single-Stage Double-Suction Split Volute Fire Pumps XBD-ALOW Series

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Product Description:

XBD-ALOW Series Single-Stage Double-Suction Split Volute Fire Pumps is used for liquid transportation for water works, air-conditioning circulation, building, irrigation, drainage pump station, electric power station, industrial water supply system, firefighting system, shipbuilding and so on.

Structural Features:
Outlet diameter of pump DN:80~1000mm
Capacity Q:≤11600m3/h
Head H:≤200m
Working temperature T:≤105℃
Solid particles:≤80mg/L
Permitted working pressure:≤25bar
Permitted testing pressure:≤37.5bar

Feature:

1、 Compact structure nice appearance, good stability and easy installation.
2、 Stable running and the optimally designed double-suction impeller makes the axial force reduced to the minimum and has a blade-style of very excellent hydraulic performance, both internal surface of the pump casing and the impeller’s surface, being precisely cast, are extremely smooth and have a notable performance of vapor-corrosion resisting and high efficiency.
3、 The pump case is double volute structured, which greatly reduces radial force, lightens bearing’s load and prolongs bearing’s service life.
4、 Bearing use SKF or NSK bearing to guarantee a stable running, low noise and long duration.
5、 Shaft seal use BURGMANN mechanical or stuffing seal to ensure an 8000h non-leak running.
6、 After material replacement, it can be used to transmit 150℃ and corrosive mediums.

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Q:How do I replace the water pump in a 1992 ford escort?
1992 Ford Escort
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if it is low you still have a problem
Q:Water supply query or water pump or motor problem?
You say that your pump used to operate properly before, so if the pump is in good condition, the lift mustn't be too great so we can rule that out. It appears to me that the gurgling sound would be made by sucking air, and for this to happen, it would be a problem on the inlet side of the pump. If the person who repaired the pump knows what he is doing, it shouldn't be the pump, so we can rule that out. That leaves the pipe and any fittings between the pump and the foot valve that should be on the end of the pipe. Try running the pump, and pouring water over all joints and fittings, one at a time, if the pump is working properly, a slurping sound will be heard at the leak. The pump will have a priming point, a screw in plug, somewhere on top of it. With the pump stopped, remove the plug, and pour water into the hole. You should be able to fill the pump right up, and the water remain at that level, without draining away. If it wont retain the water, the valve on the bottom of the pipe is either worn out or has something like a stone or gravel preventing it from operating properly. As you have disconnected this pump for repairs, it would have needed priming anyway, which is the filling up with water. It's too much to ask a dry pump to lift water any height, so maybe you don't have a problem at all. Good luck
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You can refer to the DCL and DCS microcomputer access control system, you can achieve the purpose of remote control. Specific installation methods can be found in local instrument engineering inquiries.
Q:who can recommend me some good water pumpS?
Water pump. ( Pond ) Sump pump. ( Flood prevention ) Auto water pump. ( Radiator ) What is the specific purpose of the pump.
Q:Water is pumped out of a holding tank.. Calculus question?
Let V(t) be the volume of water (in Liters) in the tank after t minutes. We are given that V(0) = 1000, and we wish to find V(60). We are also given the rate of change of the volume: V'(t) = -[6 - 6e^(-0.09t)]. Note that a negative sign needs to be placed because the rate represents water leaving the tank, i.e., being pumped out of the tank. By the Fundamental Theorem of Calculus, Integral (0 to 60) V'(t) dt = V(60) - V(0), so that V(60) = V(0) + Integral (0 to 60) V'(t) dt V(60) = V(0) + Integral (0 to 60) -[6 - 6e^(-0.09t)] dt V(60) = V(0) + Integral (0 to 60) [-6 + 6e^(-0.09t)] dt V(60) = V(0) + [-6t + (6/-0.09)e^(-0.09t)] (Evaluated at t = 60 - Evaluated at t = 0] V(60) = V(0) + [-6(60) + (6/-0.09)e^(-0.09(60))] - [-6(0) + (6/-0.09)e^(-0.09(0))] V(60) = 1000 + [-360 - (200/3)e^(-5.4)] - [0 - (200/3)] V(60) = 1000 - 360 + 200/3[1 - e^(-5.4)] V(60) = 640 + 200/3[1 - e^(-5.4)] V(60) = approx. 706.4 Therefore, approximately 706.4 L of water occupy the holding tank 1 hour after the pump is started.
Q:What kind of water pump does the 5.5KW motor have?
Model has: QS-250-40-21, lift 21m, flow 40 square, motor power is 4KW, water pump diameter is 232cmQJ-200-40-26, lift 26m, flow 40 square, motor power is 5.5KW, water pump diameter is 189cmYou can choose the right pump according to your well path.
Q:How much would it cost approximately to replace a water pump and a serpentine belt for a ford taurus 99?
2001 Ford Taurus Water Pump
Q:2001 jeep Cherokee water pump?
you can go to your local chevy dealership service center and not only they can get any part you need they can give you a diagram of your engine. i hope this is helpful to you and good luck.
Q:Water Pump replacment?
Price okorder.com, Water-pumps and serpentine belts are very easy to change in all rear wheel drive cars

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