scaffolding steel pipe support props nuts
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Quick Details
| Type: | Scaffolding Part Type: | Thread: | |||
| surface treatment: | painted: | diameter: | |||
| thickness: | Packaging Detail: | Delivery Detail: |
Packaging & Delivery
| Packaging Detail: | Loose, in bundle, plastic film, or as your request. shippment in container |
| Delivery Detail: | 20-40days |
Specifications
scaffolding prop nut
1.Ductile iron,casted or machine tap thread
2.Pitch:10.0 or 6.35mm
3.Pin: Dia.10.12, 14 or 16mm
scaffolding prop nut
Very Good Casted Manufacturing Ability for All types of casted Nuts
1. Material: Ductile Iron
2. Nut Size: Dia 60 mm, Pin : dia.12,14 or 16 mm
3. Pitch: 6.0mm or 6.35mm
4. Nut weight: different weights
5. Surface: Electro galvanized
6. Thread: Casted thread or machine tap thread
7. Type: all types of Wing nuts, jack nuts,prop nut
8.Quality Control for Large amount production to Ensure Good Quality Products
9. Packing: Bags or pallets.
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- Q:I've wanted an industrial/scaffold piercing for ages! My mum is finally looking into letting me have it done. Any advice about it? How can I hide it for school? What's the healing time? :) thank you for any feed back.
- no its sixteen interior the united kingdom for any variety of ear piercing sixteen with out parent permssion and it will harm rather undesirable take a protracted time to heal and it will value approximately ?35-?40 and clean it with salt water.
- Q:Does anyone know the name of the song or perhaps have a link to the video if they have seen it on net for example on youtube.?
- try ain't goin down till the sun comes up
- Q:Standard for inspection of portal scaffolding
- 1.4 willow nails shall be made of ML2 steel specified in GB 715. All accord with the 1.5 electrode should be used in GB 5117 series E43 electrode. Comply with the 2 basic requirements: qualified 2.1 door frame and accessories in different combination conditions, shall be accorded with the inspection results are summarized in table NO:2008JW1658 inspection project and standard units of measurement test results 1# 2# single determine connectivity and interchangeability. When the 2.2 cross support, the connecting rod and other accessories are connected with the door frame, the utility model is in conformity with the retreat mechanism which is used to prevent the exit. When the connecting rod is used with the lock arm, the connecting rod is not limited by the limit. The 2.3 level frame, and the door frame scaffolding should prevent off the hooks, are in line with the fastening mechanism of the fall.
- Q:The role of the external scaffolding and the relevant provisions?
- Scaffolding outside the building in the construction of the building is an indispensable important tool for erection. Its role: first, can make the construction personnel in different parts of the operation of the high; two is to ensure the safety of construction personnel in the high altitude operation
- Q:How to calculate the fastener type steel pipe scaffold
- 1.1.2 provides for the temporary structure of the scaffolding structure, the structure of the importance coefficient of gamma 0 take 0.9. ?The scaffold structure design of 1.1.3 on reliability requirements, considering that there is no enough statistical data accumulated by the situation, determine the probability limit state design, should be consistent with our historical experience, if using a single coefficient method was designed, the single safety coefficient should be satisfied: the strength calculation of K1 = 1.5 the stability calculation; K2 = 2. To this end, in the calculation of the introduction of the material strength of the additional coefficient of gamma 'm' or resistance to the addition of partial coefficient gamma 'R, gamma' R= gamma 0 gamma 'm=0.9 gamma' m.
- Q:What are the chances of cracking the tile? What can I do to avoid cracking the tile?This will be 3 levels of scaffolding on 6 inch wheels.
- Put the wheels (locked) on 2 x 12 planks. This will distribute the weight.
- Q:Can you do the outer scaffolding?
- 6 15cm. When the oblique rod in a span of two step distance, it is appropriate in the intersection of the large cross bar to add a small bar, the oblique abdominal rod fixed on its protruding end. 7, scissors (1) of the scaffold bridging with columns, longitudinal and transverse horizontal rod synchronous erection, with long scissors along the elevated continuous layout
- Q:What are the dangers of scaffolding
- (5) the improper operation of the accident collision accident, etc.)Analysis of the main reasons two accidents:1) whole frame dumping, vertical collapse or local collapse frameStructural defects: the structure of the lack of the necessary structural members, not in accordance with the provisions of the number and requirements of the erection of the wall, etc.;In the process of using the arbitrary demolition essential bars and even wall pieces etc.;
- Q:Right! I've heard from so many different people about this. Some say that you should never twist an industrial because it can damage the delicate newly healing skin cells. Others say that you must twist it to prevent the jewelry from healing attached to the skin and to be able to clean it properly.There really doesn't seem to be a definitive answer!My piercer has said not to twist it, so I haven't been, and I'm happy that the piercing is clean enough, etc. However I'm interested in whether any of you out there have found that not twisting it can damage it more than doing so.Thanks
- mine told me to twist it....i twist it like every day haha. nothing bad has happened
- Q:A 520 kg box sits 1.4 m from the left end. What is the tension in the right hand side wire? (g = 9.8 m/s2) ____________ Newtons
- Because the scaffold is not moving, we can assume that the net Torque acting on the scaffold equals zero. Net Torque = 0 torque = Force x distance (d) Use the left end of the scaffold as the center point. This will eliminate the Torque caused by the left wire (d = 0, so torque = 0) There are now three forces creating torque on the scaffold. There is the weight (m x g) of the scaffold, at 3.5m from the left end. m1 x g x 3.5m There is the weight of the crate, located 1.4m from the left end: m2 x g x 1.4m These two torques are countered by the torque caused by the Tension (T) of the right wire, located 7m from the left side. T x 7m The sum of these torques is zero. (T x 7m) - (m1 x g x 3.5m) - (m2 x g x 1.4m) = zero solve for T T = ((m1 x g x 3.5m) + (m2 x g x 1.4m)) / 7m T = ((115kg x 9.8m/s^2 x 3.5m) + (520kg x 9.8m/s^2 x 1.4m)) = 1.58 x 10^3 N Hope this helps.
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scaffolding steel pipe support props nuts
- Ref Price:
-
- Loading Port:
- China Main Port
- Payment Terms:
- TT OR LC
- Min Order Qty:
- -
- Supply Capability:
- -
OKorder Service Pledge
Quality Product, Order Online Tracking, Timely Delivery
OKorder Financial Service
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