scaffolding material cuplock material Q235,Q345 type
- Ref Price:
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- Loading Port:
- Tianjin
- Payment Terms:
- TT OR LC
- Min Order Qty:
- 1000 kg
- Supply Capability:
- 1000 kg/month
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1.Specification of Cup lock Scaffolding:
We are one professional scaffolding syestem manufacturer.
We could produce scaffolding as per your drawing or sample.
Cup-lock Scaffolding consists of adapter plug of cup-lock post, cross bar, diagonal brace, top bar, base and other fittings. The adapter plug of cup-lock is the core and consists of top cups, bottom cups, post, ledger connections and limit pins of top cups.While standards available in 9 regular sizes with cup joints welded at 0.5m intervals.The bottom cups are formed from high quality steel while the mobile top cups are malleable casting to provide the necessary hardiness on-site.
2.The picture of Cup lock Scaffolding:
3.Cup lock Scaffolding advantages:
1) Multifunction:equipments of construction with different size and load of construction could be assembled,such as one-side and double-sides scaffolding,props,etc.Applied to high-rise building,bridge,watertower,and so on.
2) 5 times fast of adapter plug assembly and disassembly than normal
3) Avioid using bolt in assembly and low down labor intensity.
4）Not easy to lose fastener, portable firm and easy to maintain and transport
4.FAQ
We have organized several common questions for our clients，may help you sincerely：
1）Can we provide different size of Frame system Scaffolding as customer need
The answer is Yes, customer can provide the Tec spec to us and Drawing for production.
- Q:Which hurts less, the piercing at the top of the ear, or the piercing from one side of the upper ear to the other?Thanks. =)
- Helix will be less painful. It's kind of obvious that it would be a helix is probably one of the easiest piercings you can get I got mine done when I was like 13 and I didn't even flinch getting it done. A scaffold is definitely more intense. After all there are 2 incisions for this piercings so it's gong to be twice as tough. It's sore haling too, the bar is awkward and when it moves it hurts. A helix is far easier :)
- Q:i just need to know the age limit with parental permission?
- I'm pretty sure it's 16-17 with parental permission. I suggest looking up some of the shops in your area and seeing what they say. There usually isn't a set rule for it, every shop is different. Like some shops may refuse seeing, say, a 14 year old, whereas another shop might do it with the parent's permission. Then of course, once you hit 18, you can do whatever you want, lol.
- Q:Scaffold removal should comply with those requirements......
- Preparation of scaffold safety demolition before demolition1 check the scaffold fastener connection, the wall, the support system is in line with safety requirements.2 according to the inspection results, supplement and improve the design of the demolition process, and after the implementation of the approval.
- Q:Cells from an animal's muscles are processed with chemicals and they grow. The cells are transferred to a metal scaffold and are stimulated physically. In a few months, you have a big block of meat which can be ground and cooked. What do you have to add? Does this innovation mean the price of meat will become a very minor expense?
- Sounds weird. When eaten I wonder how this experiment would affect the human body. It just might turn normal people into Liberals. If that's the case then I don't want anything to do with it.
- Q:Method for inspection of foot hand frame fittings
- Or "low pressure fluid delivery welded steel pipe" GBT 3092
- Q:A scaffold is constructed by placing two supports under a 13 ft, 9 in (a) board weighing 84 lbs. The supports are each 2 ft, 8 in (b) from their respective ends. Two painters stand on the board; one weighs 158 lbs and stands 4 ft, 11 in (c) from the left end of the board. Where must the 222 lbs painter stand so that each support carries the same weight? (express your distance in feet from the right end of the board (d).)please help!! thanks(:
- Total weight = 222 + 158 + 84 = 464 lb So, each support must carry 232 lbs Working in inches: Take moment about Right hand end Board is assumed to be uniform - CG is at the center (232 x 32) + (232 x 133) = (158 x 106) + ( 84 x 82.5 ) +(222 x d)7424 + 30856 = 16748 + 6930 + 222d 222d = 14602 d = 65.77 inches Distance of 222 lb painter should be 5ft 5.77inches from Right end
- Q:How does the second scaffold scene morally change Hester Prynne?
- It is less about Hester because she has accepted her punishment. It is more about Dimmesdale.
- Q:What is a bowl buckle scaffold?
- Compared with other types of scaffolding, bowl buckle type multifunctional scaffolding is a new scaffold with broad development prospects.
- Q:Construction scaffolding right angle fastener, rotary fastener, butt fastener weight? There are more than one meter steel pipe?Thank you！！！
- High efficiency of the installation and removal of only bare handed, greatly improve the efficiency of mobile scaffolding assembly and disassembly than the steel pipe frame 1/2 fast time, faster than bamboo scaffolding 2/3 time. Safe and reliable 1 overall performance is good: equipped with a foot board, parallel frame, buckle wall tube, horizontal and cross bar...
- Q:A 520 kg box sits 1.4 m from the left end. What is the tension in the right hand side wire? (g = 9.8 m/s2) ____________ Newtons
- Because the scaffold is not moving, we can assume that the net Torque acting on the scaffold equals zero. Net Torque = 0 torque = Force x distance (d) Use the left end of the scaffold as the center point. This will eliminate the Torque caused by the left wire (d = 0, so torque = 0) There are now three forces creating torque on the scaffold. There is the weight (m x g) of the scaffold, at 3.5m from the left end. m1 x g x 3.5m There is the weight of the crate, located 1.4m from the left end: m2 x g x 1.4m These two torques are countered by the torque caused by the Tension (T) of the right wire, located 7m from the left side. T x 7m The sum of these torques is zero. (T x 7m) - (m1 x g x 3.5m) - (m2 x g x 1.4m) = zero solve for T T = ((m1 x g x 3.5m) + (m2 x g x 1.4m)) / 7m T = ((115kg x 9.8m/s^2 x 3.5m) + (520kg x 9.8m/s^2 x 1.4m)) = 1.58 x 10^3 N Hope this helps.
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scaffolding material cuplock material Q235,Q345 type
- Ref Price:
-
- Loading Port:
- Tianjin
- Payment Terms:
- TT OR LC
- Min Order Qty:
- 1000 kg
- Supply Capability:
- 1000 kg/month
OKorder Service Pledge
OKorder Financial Service
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