pharmacy foil for medicine

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Aluminium foil acts as a total barrier to light and oxygen (which cause fats to oxidise or become rancid), odours and flavours, moistness, and germs, it is used broadly in food and pharmaceutical packaging. The purpose of aluminium is to make long-life packs (aseptic processing|aseptic packaging) for drinks and dairy goods, which allows storing without refrigeration. Aluminium foil containers and trays are used to bake pies and to pack takeaway meals, ready snacks and long life pet foods.

Aluminium foil is widely sold into the consumer market, often in rolls of 500 mm (20 in) width and several metres in length.It is used for wrapping food in order to preserve it, for example, when storing leftover food in a refrigerator (where it serves the additional purpose of preventing odour exchange), when taking sandwiches on a journey, or when selling some kinds of take-away or fast food. Tex-Mex restaurants in the United States, for example, typically provide take-away burritos wrapped in aluminium foil.

Aluminium foils thicker than 25 μm (1 mil) are impermeable to oxygen and water. Foils thinner than this become slightly permeable due to minute pinholes caused by the production process.

Aluminium foil has a shiny side and a matte side. The shiny side is produced when the aluminium is rolled during the final pass. It is difficult to produce rollers with a gap fine enough to cope with the foil gauge, therefore, for the final pass, two sheets are rolled at the same time, doubling the thickness of the gauge at entry to the rollers. When the sheets are later separated, the inside surface is dull, and the outside surface is shiny. This difference in the finish has led to the perception that favouring a side has an effect when cooking. While many believe that the different properties keep heat out when wrapped with the shiny finish facing out, and keep heat in with the shiny finish facing inwards, the actual difference is imperceptible without instrumentation.The reflectivity of bright aluminium foil is 88% while dull embossed foil is about 80%.


Q:I can't figure out this question, could anybody help me figure out how to solve this? Thank you.A pot of hot water is boiling on your stoveThe pot is in the shape of a round cylinder made of aluminum which is 10 cm in radiusThe aluminum is 3 mm thickYou notice that after 20 minutes, 0.1 kg of water has boiled away.A) What is the temperature of the inner surface of the bottom of the pot?B) How much energy is required to boil away M kg of water?C) What is the difference in temperature between the inner and outer surfaces of the aluminum bottom of the pot?D) What is the change in entropy of the boiling water after boiling away 0.1 kg of water?
HmmAssuming this is at standard pressure (sea level on Earth), then if the pot is open, water boils at 100C so that must be the temperature of the inner surfaceTh others I don't know without looking it up, but you can calculate the power from the time taken to evaporate 100gThat and the heat conductivity of aluminum will give you the temperature difference across the bottom, and hence the temperature of the outer surface.
Q:In my Chem class, we have to make something out of metalIt can be with foil, nail, both, or whateverOur teacher likes creative things, but I also want it to be easyAny ideas?
You could try making an electro-voltaic cellThis is pretty much a batteryAll you need is some acids and bases and a rod of rolled sheet of aluminum foil and lead foilYou can attache a wire to each rod and dip them in containers containing the acids, two separate containersAttach a voltmeter to the wires to measure currentThe experiment can be altering the concentration of the acids or surface area of the rods.
Q:How do I make a solar oven?
Follow instructions on how to make leather, but use it on the clay!
Q:What's the difference between hot rolled aluminum foil and cold rolled aluminum foil?
The aluminum foil mill only consists of rough rolling, medium rolling, finishing rolling, without hot rolling and cold rolling.
Q:What is the electron configuration of Al 3+?
aluminum (Al) loses 3 of its valence electrons to become Al^3+ ; Al 1s^2 2s^2 2p^63s^2 3p^1 Al^3+ 1s^2 2s^2 2p^6
Q:I lost my favorite recipe card for the chicken alfredo does anyone have it? And no I do not want a copycat recipe, I have searched allover and cannot find a recipe that has similar baking instructionsIf anyone has this recipe please let me knowthanks
First of all, doing drugs is badThat aside, I dont think youre in any immediate danger of dying or getting some weird disease from smoking aluminum foilI do however, would like to recommend that you go down to a smoke shack or get an older sibling/friend to do that for you, and just pick up a pipeOr spend $1 and get small cigarette papers and roll a joint or take hits off of the pipeOr get someone to teach you the correct way to make a bong.
Q:I have a beef brisketMy husband had some at a shindig at one of the plumbing supply housesHe doesn't liked boiled corned beef and cabbage, but this he likedHe thinks it was baked he said it was tender, but he doesnt know what spices or how to cookDoes anyone have any simple recipes with ingredients you normally have in the houseI dont have any beerAny Ideas?.
INGREDIENTS 1 (3 pound) beef brisket, trimmed of fat 1 medium onion, thinly sliced salt and pepper to taste 1 (12 fluid ounce) can beer 1 (12 ounce) bottle tomato-based chili sauce 3/4 cup packed brown sugar DIRECTIONS Preheat the oven to 325 degrees F (165 degrees C)Season the brisket on all sides with salt and pepper, and place in a glass baking dishCover with a layer of sliced onionsIn a medium bowl, mix together the beer, chili sauce, and brown sugarPour over the roastCover the dish tightly with aluminum foilBake for 3 hours in the preheated ovenRemove the aluminum foil, and bake for an additional 30 minutesLet the brisket rest and cool slightly before slicing and returning to the dishReheat in the oven with the sauce spooned over the sliced meat.
Q:How does an electrical generator actually produce electrons? I understand the fact that there are two magnets, one facing north, the other facing south, which creates a magnetic field which will keep electrical current in place, I also understand that there is a conductive loop of wire, such as copper or aluminum that rotates on a shaft between the two magnetsWhat I don't understand is how electrons are actually being produced? Are they being somehow sucked in from surrounding atoms, such as the air, if so, how does this exactly work? Any help will be greatly appreciated.
Best to pour it out on a bowl and keep it inside the fridge.
Q:we have three cats, and three litter boxes throughout our housebut one of my cats (a fixed male, only a year old) for some strange reason likes to poop on the counter when we arent home!!!! its been happeneing way to many times, even when we are homei scoop their litter everyday so it cant be thatwe've tried spray bottles, we yell at him and lock him in the bathroom when it happensbut the very next day he does it againhes such a good, fun cat besides that, but now my parents want to get rid of himdoes any one have any techniques, or something, like any ideas on how to teach him to stop?? there has to be somethingbut thank you!
Just make sure you hold it carefully when you remove it from the oven It may or not sag a bit but as long as you are careful it should be fineYou might want to have a cutting board near to place the pan on if you have to carry it a distance.
Q:of the photon that ejected the electron(aluminum has a work function of 4.06eV)Where do I even start with this one? Can anyone help me jumpstart this problem please?
First let's find the kinetic energy (KE) of the electronIts velocity is low enough that we don't need to consider relativistic effects, so we can say its mass is close to its rest mass of 9.1 10-31 kilogramWe can find its KE by KE ?mv? and we know v is given as 8.70 105 meters per secSo KE ?(9.1 10-31)(8.70 105)? Do the arithmetic and get KE 3.44 10-19 jouleSince 1 J 6.28 1018 eV the KE of the electron (3.44 10-19 J)(6.28 1018 eV per J) 2.16 eV The photon's energy E must be at least the KE of the ejected electron plus the work function of aluminum, given as 4.06 eVSo E 2.16 + 4.06 6.22 eV E is related to the wavelength w by: E hc/w where h is Planck's constant, equal to 4.16 10-15 eV-secand c is the speed of light, 3.0 108 meters/sech and c are both constants, so hc is constant, 12.48 10-7 eV-metersSince E hc/w and we know E, we can say w hc/E (12.48 10-7)/6.22 The wavelength w 2.00 10-7 mor 200 nanometers (ultraviolet) Whew! I hope you understand this step by step procedure I used to find w.

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