Q:2009 and 2010 construction of secondary construction division of the exam questions and answers, Jiqiu ~!

(Construction project) single multiple choice questions (a total of 20 questions, each question 1 points

Q:Would like to ask you under the construction of the rainy season, what measures ah? Teach the next sprinkle

reasonable organization of construction arrangements, so that sunny day to pay attention to outdoor work, rain arrangements for indoor work

Q:What is the vertical transport of construction and the high increase in fees

In the contract of the project, the construction unit is paid a fee for the construction unit

Q:What is the exterior scaffolding erection specification? What do you need to pay attention to?

That it is what to do with it, for home improvement, then, in the end how much help? Need to pay attention to a few points:

Q:I am looking to buy storage tank building tools like bull pins, u-bars,keyplates,and scaffold someone HELP?

Check with Home Depot or Lowes. you can usually find what you need there.

Q:A man of mass 60.3 kg stands on a scaffold supported by a vertical rope at each end. The scaffold has a mass of 21.5 kg and is 2.3 m long. Suppose the man stands to the right from the middle of the scaffold that is a distance one sixth of the length of the scaffold. What is the tension in the right rope? Left Rope?Can someone please explain HOW you do this question!? Thanks!

this is a 2d concern. The moments approximately any component interior the gadget could desire to stability, in any different case the gadget (scaffold) might rotate. additionally, the vertical forces could desire to stability, or the gadget (scaffold) might translate. it style of feels to me that to the spectacular from the middle of the scaffold this is a distance one 6th of the dimensions of the scaffold is the comparable as announcing 2-thirds from the left-edge of the scaffold. The moments could be summed approximately any component. i will evaluate the left edge of the scaffold, the place the 2d produced by utilising the left rope is 0. finished M = 0 = scaffold M + guy M + spectacular rope M 0 = 23.7kg*9.8m/s^2*(3.1m/2) + 60.1kg*9.8m/s^2*(2*3.1m/3) - F*3.1m wherein: the scaffold is assumed to be a component mass placed at its middle the tension F acts opposite to the load of the guy and the scaffolding, and subsequently has -ve sign sparkling up for F. To get the tension in the different rope, you may basically evaluate the vertical forces interior the gadget. besides the fact that, you're able to desire to sum the moments approximately another component (say, the spectacular rope). desire this enables.

Q:- Construction safety and quality control report for the depth of construction quality and construction safety production, to ensure the safety and use of structural features to prevent the fall, collapse, mechanical injuries and other multiple accidents,

In the late 1950s, oil wells were specially developed for oil

Q:I have a concrete transport arm pump, would like to ask which building materials companies need to use, can be resident

That is, the upper and lower with a pump on the 90-degree bend, the two of them with the root 1 m straight tube connected to each other, and the other round steel to do two large diameter 18 meters, and then some straight round 2 large circle made of a hoop, and then the two straight with elbow straight fixed Below the elbow tow pump up the pump tube, the top elbow root 2 m straight tube It can be in the range of 4 meters to rotate the fabric, such as to move the car can be used in place

Q:what do you call a place of great significance? such as the scaffold in the Scarlet Letter?

Historical a place with alot of history attached to it Landmarks

Q:Also if its possible part B wants to know A ball thrown vertically upward is caught bythe thrower after 2 s.Find the initial velocity of the ball. Theacceleration of gravity is 9.8 m/s2Answer in units of m/sFind the maximum height it reaches.Answer in units of m

Use, Vf = Vo + g * t With Vo = 0 , Vf = g * t = 9.8 m/s^2 * 3.39 s = 33.222 m/s. part B, use the same equation, but take into consideration to watch for direction and adopt a convention. As before we have considered +ve for downward direction. Now Vf = 0 0 = Vo + g * t. Vo = - 9.8 m/s^2 * 2 s = -19.6 m/s . Negative means upward direction according to the adopted convention.