JDXF-35 TA,TH GY W1,W2,W3 Voltage Transformer

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Type description

Technical characteristic
1.It accords to the GB1207-1997<voltage transformer> ,IEC186 and IEC60044.
2.This product has the character of limited tightness.All the tightness compartment do not be put into ultraviolet radiation so that we solve the problem of chap of tightness rubber and aging,these product is more reliable and has longer life,we ensure that it can run 20 years without leakage.
3.The porcelain is equipped with irragateing flange.the surface of flange use hot zincification to enhance the wholly mechnism of product and has beautiful outlook.
4.This product is equiped with bellow and is tightnesds completely.
5.With higher accuracy to 0.2,we can reach the requirment of customer with seperatly measuring secondary winding and protection winding.
6.With epoxy secondary terminal board,the product is enhanced secondary insulation and tightness.
7.All the standard comparthent are plated Dakelo.We ensure that the product don't rust for 20 years.
8.The inner structure of this product has changed largly and we solve the problem of old 35KV PT with unreasoned inner structure for the unpassed dielectric loss,This product has low partial discharge and litter dielectric loss with advanced workcraft.
9.The excitaton density of this product is equal or less than 0.7T and has the ability of avoiding ferro-resonance.

Technical Data

Rated voltagePrimary winding35/
Measuring winding0.1/
Protection winding0.1/
Residual voltage winding0.1
secondary accuracy and reated outputMeasuring winding80VA 0.2 class
Protection winding150VA 0.5class 250VA 3P class
Residual voltage winding100VA 6P class
Rated limit output2000
Rated insulation level4.05/95/200
Creepage distance810,1050,1250
Flash distance410-500
Total weight/Oil weight40/190
Pack size580×600×1300

JDXF-35 Voltage Transformer Outline Drawing

Srructure drawing

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Q:Transformer copper row selection
A general use of cable out, select 120mm2 line can be; second to use two 100 × 10mm copper, copper is to tin treatment. Copper specifications table recommended to find the national standard, see the copper discharge capacity and installation methods, after all, the transformer must be produced to meet the national standard.
Q:How many transformers are used in a hundred households?
Depending on the specific use of electrical power. First select the rated voltage of the transformer. The voltage on the high voltage side is equal to the voltage of the connected grid. The voltage on the low voltage side is 10% or 5% higher than the voltage of the low voltage side (depending on the voltage level of the transformer and the magnitude of the impedance voltage). Calculate the size of the load carried by the transformer (requires the maximum statistical load, the conversion of the operating load kW value into apparent power kVA). If two transformers are used, the capacity of each transformer can be selected according to 70% of the maximum integrated load. The transformer should be considered for the total load and leave the appropriate margin. Other brand name parameters can be combined with the appropriate consideration of the transformer product. For example: select 35 / 10kV transformer. Assuming a maximum load of 3500kW, power factor of 0.8, choose two transformers, capacity S = 0.7 × 3500 / 0.8 = 3062kVA, 3150kVA transformer can choose, the voltage ratio of 35kV / 10.5kV. Select the model from the catalog.
Q:Transformer voltage range of 10.5 ± 2 * 2.5% kV and 10.5 ± 5% kV What is the difference
Two transformers of the same voltage range, but the tap is not the same, the previous one is 5-speed regulator, select the relatively small, more adaptable. The latter is the third gear regulator, sometimes with the actual time required to have the voltage difference, mainly to see that your load is stable and unstable. These two kinds of voltage regulator for the basic price of the transformer has no effect.
Q:Transformer oil filter method
So only on-line oil treatment. Oil filters require an external oil filter and oil tank. The new oil (has been qualified, insulation pressure are qualified oil into a clean oil tank inside, the external oil filter and oil drums and transformer tubing as a whole, the external circulation of online filter oil). Mainly: 1, online filter to continuous operation, to ensure that the weather is fine air humidity less case, under the conditions of the best conditions for 214 hours of continuous operation.
Q:A liter of transformer oil how much jin
The main role of transformer oil: (1) insulation: transformer oil has much higher than the air insulation strength. Insulation material immersed in oil, not only can improve the insulation strength, but also from the erosion of moisture. (2) heat dissipation: transformer oil specific heat, often used as coolant. Transformers run the heat generated close to the core and the winding of the oil heat up and down, through the oil up and down convection, heat dissipated through the radiator to ensure the normal operation of the transformer.
Q:Transformer 1KVA can load how much security, how to calculate the formula
You only give a parameter, that is, KVA, you have to give two dollars to count
Q:Proteus transformer how to adjust the parameters, the 220V into 14V output.
2, in the Proteus simulation diagram, double-click the transformer symbol, open the transformer parameter settings dialog box, which                 Primary Inductance 1H (set: can be fixed)                 Secondary Inductance 0.00406H (set by press)
Q:Where is the transformer used?
You ask more general, there are many kinds of transformers, 1 is the power transformer, it is 10,000 volts drop to 380,220 V commonly used low pressure for us to use. Small transformers are 220V voltage reduced to household appliances used when the operating voltage rectified as electrical power. High-frequency transformers are generally used as switching power supply pulse output transformer. High-frequency signal transformer only a few turns of the coil, the transmission of high-frequency signal. Simply say this kind of bar, a wide range of various types of transformers.
Q:How do you choose the public transformer capacity?
800X8 = 6400KW 6400KWX0.5 (use factor) = 3200KW + 50KW mall = 32500KW (full load operation) Choose three sets of 1000KVA transformer ,, 3000 (KVA) X0.9 (functional factors) = 2700KW · · · · · · · · · · · · · · · · · · · · · · · · · 315KVA transformer for 670 is too small ,,, 670X8 = 5360KW, 5360X0.5 = 2680KW 2680KW / 0.9 = 2977KVA Choose three sets of 1000 phase change
Q:Rated capacity of three-phase transformer S = √3 * U * I
Single phase transformer S = UI where U is the phase voltage and I is the phase current. When the composition of three-phase transformer, of course, is the three transformers add up, S = 3UI. Here U is phase voltage, I is the phase current. As the three-phase circuit to use the line current and line voltage calculation, angle and triangular connection is the same, when U is the line voltage, the phase voltage increases the root number 3 (1.732) times.

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