JDCF-110,132,220,230 Voltage Transformer

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Shanghai
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1000sets set/month

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Brief Introduction
The"JDCF"series voltage transformers are inducitive type,single phase,oil filled,outdoor type.It accords to the GB 1207-1997<voltage transformer>,IEC 186 and IEC60044,This type of voltage transformer is of cascade full seal construction,The product consists of winding assembly,porcelain housing,transformer oil,base and stainless steel Bellow.

The primary winding of 110KV or 132KV voltage transformer is divided into two parts,wound separately around the upper and lower core,Wound around the lower core,three secondary windings are respectively measuring winding,protective winding and residual voltage winding.

The primary winding of 220KV or 230KV voltage transformer is divided into four parts,wound separately around two cores.Wound around the lower core,three secondary windings are respectively measuring winding.protective winding and residual voltage winding.

The active part is located to the base by suporting frame made of high quality insulation materials and is put into porcelain housing with degassed and de-watered transformer oil after vacuum treatment,All outlet wires of secondary winding and the terminal "N" of primary wnding are connected to the epoxy resin board which is in the waterproof and dust-proof terminal box of the base.There is a valve for oil-filling or oil-exhausting on the base.
Type description

Technical Data



JDCF-110,132 Voltage Transformer Outline Drawing

1.Oil-level indicator
2.Bellow
3.Primary terminal
4.Porcelain bushing
5.Insulation support frame
6.Winding body
7.Secondary terminal box
8.Base
9.Name plate
10.Valve
11.Earthing bolt

Type
JDCF-110W2
JDCF-110GYW2 JDCF-132W2
H1
1500±20
1700±20
H2
1800±25
2000±25


JDCF-220,230 Voltage Transformer Outline Drawing


1.Bellow
2.Observation window
3.Primary terminal
4.Primary terminal
5.Hook
6.Oil draining outlet
7.Name plate
8.Earthing bolt
9.Secondary terminal box
10.Base

Type
JDCF-220W2
JDCF-220GYW2 JDCF-230W2
H1
2510
2750
H2
2960
3200

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Q:Transformer ONAN?
Transformer ONAN cooling method for the internal oil natural convection cooling, that is commonly referred to as oil-immersed self-cooling. The cooling mode of the transformer is determined by the cooling medium and the circulation method. Since the oil-immersed transformer is also divided into the internal cooling mode of the tank and the external cooling mode of the tank, the cooling mode of the oil-immersed transformer is represented by four letters. The first letter: the cooling medium in contact with the winding. O -------- mineral oil or ignition of more than 300 ℃ of insulating liquid; K -------- Insulation liquid with ignition point greater than 300 ℃; L -------- ignition can not be measured insulation liquid; The second letter: the way the internal cooling medium is circulated. N -------- The oil flow flowing through the cooling equipment and the windings is a natural thermal convection cycle; F -------- The oil flow in the cooling equipment is forced to circulate and the oil flow flowing through the windings is the thermal convection cycle; D -------- The oil flow in the cooling equipment is forced to circulate, at least in the main winding oil flow is forced to guide the cycle; Third letter: external cooling medium. A -------- air; W -------- water; The fourth letter: the way the external cooling medium is circulated. N -------- natural convection; F -------- Forced circulation (fan, pump, etc.).
Q:Two Transformers Parallel Operation
The total capacity of the two transformers in parallel is not a simple addition of the capacity of the two transformers. Even if the rated capacity of the two transformers is exactly the same, the impedance of the two transformers can not be exactly the same due to the existence of design / manufacturing errors. Based on the principle of the parallel circuit, the transformer with a small impedance will share a larger current, A transformer has been overloaded and another transformer is not yet fully loaded. Can be based on the measured value of two transformer impedance (on the nameplate). Calculate the transformer with a small impedance to reach full load, the load of another transformer, the sum of the two is the total capacity of the two transformers in parallel. In fact, the transformer capacity selection is usually about 25% greater than the actual load, so the reality is usually not a full load, while the other has been a serious overload situation.
Q:Transformer size problem (kVA)?
buildings come in all sizes. Some use a lot of power, perhaps because of lots of machinery. Others use a much smaller amount. So you need to calculate or estimate the amount of power the building will be using. If you know the square foot total and use of the building (industrial, office, etc) there are probably tables that will give you a guess. One 240/120 panel for the entire building? That implies a very small building, as must buildings distribute 3 phase 208 volts, and have numerous subpanels. .
Q:Which movie do you think was movie of the summer? Transformers or Fantasic 4 (Rise of the siiver Surfer)?
Out of the two, I preferred Transformers as it wasn't quite so silly; the dance club scene in Fantastic 4 - where rubber guy shows off - was pretty stupid.
Q:Where can I find a replacement power transformer for my crate gt80 guitar amplifier?
First, what you need to know is the secondary voltages of the transformer you wish to replace. A part number is nice, but tells you very little, unless you have a book on hand, and usually, these numbers are only for that product line (in house) part numbers. I can tell you where to go to find a power x-fmr. but will need to know: How many watts will said amplifire send to the speakers, how many wires come off of the secondary, and how big is it? If you can get a schematic drawing of your amplifire with power transformer output voltages, I can tell you exactly where to get a transformer from. Feel free to e-me. Why did it fail? Are you sure that the power transformer is bad? There may be other issues, here. I rarely see a transformer go bad under normal use. If the fuse blows, replace it with a 1/2 amp larger than it calls for. If it calls for a 2 amp fuse, try a 2.5 amp fuse. If it still blows, try a 3. if it still blows, you may have a short in the power output section of your amp. I don't normally recommend that higher fuse ratings should be used, but that is what I would do if I was working on it. You may find other issues besides the power transformer. If you have voltage going into (the primary) and no voltage on the secondary at all, then you might have a transformer that has a thermal cutoff unit that is hooked up in series with the primary windings protecting the transformer from over heating. This has been known to happen, and can be easily repaired, if you have the right tools, a soldering iron, and a lot of patience. I can walk you through it.
Q:What is the critical load of the economic operation of the transformer?
In order to increase the amount of active loss caused by the active loss of the system in the power system, a conversion factor is introduced, that is, the reactive power economic equivalent. Reactive power economic equivalent, is that the power system to send 1kvar reactive power, the power system will increase the number of active power loss kw, the symbol kq, unit kw / kvar. This kq value and the power system capacity, structure and calculation of the specific location and other factors. For the factory substation, reactive power economic equivalent kq = 0.02 ~ 0.15; Kq = 0.05 ~ 0.08; for the three or more transformer factory, take kq = 0.1 ~ 0.15 ~ 0.04; for the two-stage transformer factory, take kq = The
Q:Power drawn by a transformer?
Hello Samantha, in case of ideal transformer the power at the out put would be the same as that in the input. To get the power we need voltage and current. Voltage at the out put is 8 V and current is 570 mA. Hence power consumed by the machine is 4.560 W. So the power drawn in case of ideal transformer will be the same as 4.560 W If the efficiency of the transformer is 86.5% (100-13.5) then the input power will be 5.27 W (approx) To get the number of turns in the secondary let us use Ns/Np Vs/Vp Hence Ns 600*8/120 40 turns.
Q:800KVA transformer itself is the loss of how much?
S9 type oil change 800kVA no load loss 1400 watts load loss 7500 watts S11 type oil change 800kVA no load loss 980 watts load loss 7500 watts
Q:Transformers Toys Class Difference?
Miss okorder
Q:what are the properties of electrical transformers ? their uses ? their applications ?
Through magnetic induction, a transformer transfers electrical energy from one circuit to another. I think it is used to step up/down the number of volts. It also allows alternating current to transmit electrical power over long distances.

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