Hot Rolled Aluminium Coils for Ships Building AA5083

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Loading Port:
Shanghai
Payment Terms:
TT OR LC
Min Order Qty:
5 m.t.
Supply Capability:
50000 m.t./month

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Item specifice:

Grade: 5000 Series Surface Treatment: Mill Finish Shape: Flat
Temper: O-H112 Application: Transportation Tools

Product Description:

1.Structure of Hot Rolled Aluminium Coils for Ships Building AA5083


Hot Rolled Aluminium Coils for Ships Building AA5083 is one semi-finished aluminium material. This strip can be rolled down to aluminium coil,sheet,circle ect.  The alloy AA1050 is widly used in building, industry ect. Its weight is much lower than steel. So many customers choosed aluminium material instead of steel.


2. Main features of Hot Rolled Aluminium Coils for Ships Building AA5083

a.Competitive price---We have our own mills and can produce mill finished aluminium coils, so we can control the production cost better.

b.Professional after-sale service---We have more than 15 years exportation experience and you need not worry about the exporation problems.

c.Fast delivery time---We can control the delivery time within 35 days.


3. Image


Hot Rolled Aluminium Coils for Ships Building AA5083

Hot Rolled Aluminium Coils for Ships Building AA5083

Hot Rolled Aluminium Coils for Ships Building AA5083



4. Product Specification of Hot Rolled Aluminium Coils for Ships Building AA5083



AlloyTemperThicknessWidthWeight
AA5083H140.2MM-3MM1000MM-1800MM2 TONS


5.FAQ:


What is the quality standard?

---Usually our standard is GB3880-2006

What is the largest width?

---It is 2300mm

What is the MOQ?

---Usually we can accept 80 tons.


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Q:help with aluminium and titanium questions?
1. When exposed to air, pure aluminium rapidly forms a passive oxide layer, alumina, which further inhibits aluminium reactions with other elements. 2. Aluminium can be made stronger by alloying with other elements. One of the most known aluminum alloy is duraluminium, where the principal alloying component is copper. 3. Exactly as aluminium, titanium corrosion resistance is due to its high reactivity with oxygen. When pure titanium is exposed to air it forms a passive titanium dioxide layer on the surfaces exposed which further prohibits other reactions with corrosion agents. 4. The use of titanium in jet engines components is favored by its strength to weight ration, which is unmatched by any other metal. As for the nuclear reactors, its use is preferred because of its superior corrosion resistance associated with fracture toughness and overall durability. 5. Both titanium and aluminium are refined from their respective mined ores - bauxite, for aluminium, ilmenite and rutile for titanium. Basically, these are oxides of the metals. Pure metal has to be reduced from these ores and processes involve use of temperatures up to and sometime exceeding 1000 degrees Celsius, which obviously requires a great consumption of energy, including electricity. Moreover, pure aluminium is obtained in the final processing phase through electrolysis, meaning an electrical current is needed in order to drive the required chemical reactions, thus adding to the electrical consumption. 6. Recycling aluminium from aluminium simply requires the remelting of the metal, eliminating the electrolytic phase that is high electric energy consuming.
Q:cinergy field seats: metal? aluminum?
If Cinergy isn't the concentration of the drawing, it particularly is probable in simple terms th at they have not as much as date the drawing of the skyline. If there's an indicator on the packaging layout, then removing the stadium might require them to resubmit the trademark utility, and that they probable do no longer evaluate it relatively easily worth the difficulty.
Q:How much is the price of the 6061 aluminum plate?
You ask the question is not detailed enough, because 6061 aluminum thick and thin prices are different, domestic and imported prices are different, domestic quality of different prices are also different.
Q:If aluminum, with an atomic weight of 27...?
aluminum oxide is Al2O3 , or 2 part Al to 3 part O. 27 grams Al2 *2 / 54 grams Al available = 16 grams of O * 3 / X grams of O solve for X: X = 48 grams of oxygen needed next guy is right....the formula for aluminum oxide is Al2O3..sorry...I readjusted the formula above to show the change
Q:Why can't I melt aluminum?
if a candle is 1000 degrees u can melt aluminum with it, it wont happen straight away, you have to give the metal a long time to heat up as it conducts heat it will take ages, you will prob let go or get bored before the metal has chance to heat up
Q:Any difference between aluminum and carbon arrows?
Aluminium weight more than carbon arrow, so it will drop more.
Q:Which explains aluminum's resistance to corrosion?
the fourth one is correct the fourth statement tells us that aluminium is more reactive(it has higher electrode potential) so it cannot be displaced by 02/H20 which has lower electrode potential (which means it is less reactive)so less reactive cannot displace more reactive hope so it will help
Q:Fiber laser cutting machine and carbon dioxide laser cutting machine, which thin aluminum plate effect is better?
If it is a thin aluminum plate, it is better to use the fiber laser cutter. Fiber laser cutting machine is mainly to cut thin metal, CO2 cutting machine is mainly cutting non-metallic or very thick metal. You can see the families:
Q:How do you calculate the price and weight of aluminum sheet?
The material of aluminum plate is divided into many grades100110021003 and so on, each price is not the sameAccording to the smoothness after processing, smoothness and so on, there are larger come and goI remember last year's 2.5 thick 1001 aluminum plate cost price is about 230 square meters
Q:Expansion--Aluminum and Steel?
Assume linear thermal expansion with constant expansion coefficient. The change of length is given by: ΔL = L₀·α·ΔT (L₀ initial length, α linear thermal expansion coefficient) The overall length of an object as function of temperature is: L= L₀ + ΔL = (1 + α·ΔT) · L₀ Consider the measurement at 21.2°C as reference: The aluminum column changes its length to L= (1 + α_aluminum · ΔT) · L₀ = (1 + 23×10-6 ^C°-1 · (35.4°C - 21.2°C) ) · 17.7m = 17.705m That would be the length measured with a steel tape at reference temperature of 21.2°C. Unfortunately the steel tape expands too. Because the scale increases with the expansion it measures too short. On the expanded tape you read the length L₀ while the actual length is L. Hence the measured length is: L₀ = L / (1 + α_steel · ΔT) = 17.705m / (1 + 11×10-6 ^C°-1 · (35.4°C - 21.2°C) ) = 17.003m

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