Format : 156 mm × 156 mm ± 0.5 mm
Thickness: 210 μm ±40 μm
Front (-) : 1.5mm bus bars (silver),blue anti-reflection coating (silicon nitride)
Back (+) : 2.5mm wide soldering pads (silver) back surface field (aluminium)
1. High efficiency and High power.
2. Long-term electrical stability.
3. Lowest price and Fastest delivery.
4. Good quality and best service.
5. Bulk supply
6. Trusted Warranty
7. Big Sale
8. More than 25 years on the lifetime.
Electrical Characteristic of Mono Solar Cells
Open Circuit Voltage-Voc(V)
Maximum Power Voltage-Vmp(V)
Short Circuit Current-Isc(A)
Maximum Power Current-Imp(A)
Maximum System Voltage
Maximum Series Fuse Rating
Temperature Coefficients of Pmax
Temperature Coefficients of Voc
Temperature Coefficients of Isc
Nominal Operating Cell Temperature
Standard Testing Condition(STC)
Qualification Test Parameters
We have organized several common questions for our clients，may help you sincerely：
1. What’s price per watt?
A: It’s depends on the quantity, delivery date and payment terms of the order. We can talk further about the detail price issue. Our products is high quality with lower price level.
2. Can you tell me the parameter of your solar cells?
We have different series of cells with different power output, both from c-si to a-si. Please take our specification sheet for your reference.
3. How do you pack your products?
We have rich experience on how to pack the panels to make sure the safety on shipment when it arrives at the destination.
- Q:solar panel roofing?
- The solar panels are very expensive to provide much power. If u go that way do not skimp on the support as a high wind will blow them away. In Ecuador I put in a remote site for communications. It was working good when a Strong wind blew $0.000 worth of solar panels all over the jungle.
- Q:can i make a solar panel out of aluminum foil?
- You can't make a solar panel to generate any reasonable amount of electricity from that. You need a semiconductor to start with, in order to have something that can generate free charge carriers(electrons and holes) from photons. Then you need a junction which can separate the charges. In principle you could make a Shottky Diode solar cell from copper if you could find a doped semiconductor to bond a sheet of it to the copper. To form a decent electric field there should be a significant difference in work functions between the copper and the semiconductor, this will generally require the semiconductor to be doped. On top of this you would need a transparent conductor (most used are things like ITO or other 'TCOs' - Transparent Conducting Oxides) to be the top electrode to inject replacement charges into the semiconductor to replace the effect of recombination current. In summary, it's difficult to DIY. You generally need complicated machinery to get decent crystal growth and/or doping.
- Q:Computation of Solar panel requirement?
- The power output of a solar panel uses a formula to determine kilowatts produced per hour per square meter per day. This calculation is important because, if you plan to install a solar power system for your home, you will want to know how many solar panels will be needed. To calculate solar power requirements correctly, you need to gather the data that is needed for the calculation. First you have to find the average amount of solar radiation available for your area. You can use a solar radiation chart. This can range from a 4 to a 7 depending on the area you live in. Write the number down on a piece of paper and indicate it with the letters RA. Next is determine the amount of electricity that you use daily. Add the kilowatt-hours used per month from your utility bill. Multiply this number by ,000 to get the watt hours in a month. Divide the total by 30 for the amount of electricity you use daily. Write this number down and indicate it with the letters DE. Determine the percentage of your home that you want to power with the solar power system. Write this number down and indicate it with the letter P. Determine the system inefficiency factor for the solar power system. You should be able to find this on the brochure for the system or from the manufacturer's web site. Write this number down and indicate it by the letter I. Determine the power or yield that is required for your home. Use the equation P = I x (DE x P) / RA to find the power requirements in kWh. Divide the number from Step 5 by the peak wattage for a single solar panel to determine the number of panels you will need for your home. Goodluck! :)
- Q:How many solar panels do you need on your house to power your heater in winter?
- I okorder.com/... To run your pump 24 hr you need 028 m^2 = 0.254 acres. In July the solar insolation is 5.92 kW-hr/day/m^2 and you need 0.042 acres to run the pump for 24 hours. Further south in the US, the numbers are more favorable.
- Q:What factors effect the amount of electricity produced from solar panels?
- irradiance in watts/meter^2 (000-800w/m^2 depending on air quality) COS of angle to the suns rays efficiency of the panels (usually about 5%) age of the panels(one dead cell can drop an entire panel from the array) how dirty are the panels (dust, bird poop, leaves, shading) efficiency of the inverter (usually about 90%) All of these factors affect the amount of electricity produced. One other consideration is that in areas of extreme hot and cold the band gap of the silicon is changed.
- Q:Where is the best place to get an education/experience and job in the installation of solar panels? ?
- The best suggestion I can give is to call solar installation companies in your area, and ask for their recommendation as to what to do. They may recommend a technical college with an appropriate program. With unemployment rising, new jobs in solar will likely be scarce for a while. You might also inquire at roofing companies. If you apply at a solar company, and can demonstrate that you already have roofing experience, that will be a plus.
- Q:Question about using solar panels......?
- I don't think it is enough solar power. Your motor requires .5A x 9V = 3.5 watts. The solar cells are .450A x 4V x 2ea. = 3.6 watts, .2A x .5V = .3 watts, .A x 9V = .9 watts total solar = 4.8 watts. The problem with connecting the cells in series to get the right voltage, like the two 4V cells in series with the .5 volt cell (total 9.5 volts) is that the .5 volt cell limits the maximum current to only 0.2A. If you paralleled that with the 9V cell, you would get 9 volts at 0.2 + 0. = 0.3A, too low to operate the motor at its design current and voltage. The best you could do is put the two 4V cells in series, and in parallel with the 9V cell (a blocking diode might be a good idea, but probably not required for such a small array). That way you get 8 volts at 0.55 amps.
- Q:Solar panel connected to battery ??
- . Make sure you got the right type of battery that allow to charge from the solar panel. 2. Make sure you use a device which I forgot the name but it will make sure the charge go one way in case the light go out so will not drain the battery while it is hook up. 3. Make sure you got the right charge from the solar panel to charge the battery. Reason is easyier to swim down the river or is it easy to swim up river.
- Q:Designing 3d Solar Panels?
- I okorder.com/
- Q:Efficiency of solar panels?
- Efficiency of photovoltaic panels usually describes the ratio between the energy of the sunlight falling onto the panels and the electric energy you get out. This number is, for commercially available panels today, usually in the range of 2...9 %. What you are asking is something else. The power from the panel depends on the light falling on it. A panel rated for kw peak will deliver that kw under a clear sky, with the sun orthogonally above the panel. For a fixed mounted panel, that is true (at most) for two days every year at noon. At any other time, the output is less. Therefore (at least for the area I live in), some people build databases (and Excel tools) in which the various variables are considered: - inclination of the panel - orientation of the panel - average sunshine duration during a year Plugging in these numbers, I get theoretically for my roof an electricity output of just over 000 kWh/year per installed kWpeak of collector power. If you set up a tracking panel (following the sun), the energy output of the panel will be higher, but so will be the cost for the mounting and the area needed to set up the system.
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