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thick wires have less resistance
Q:Power wire, speaker wire and ground wire please answerrrrrrr?
the 17 ft of power wire is going to be fine. Just make sure you install an inline fuse by the battery. The 17ft of ground wire is a little bit too much, but you can cut that down. Make sure you ground the amp as close as possible so the voltage drop is minimal. The 8 guage speaker wire is way too high a gauge for speaker wire. You would be fine with 12, 14, or 16 gauge. The length needed depends on what speakers you plan to wire up. If its just subs then I would say thats more than enough. If you're powering components, you will need much more, probable close to 100. Overall it should be a good setup though.
Q:when wiring car speakers.. does the thickness of the wires matter?
This Site Might Help You. RE: when wiring car speakers.. does the thickness of the wires matter? do speakers function better with thick or thin wires?
Q:Need help wiring Ikea chandelier ASAP?
You do have a problem there, the colors in the ceiling are not standard. So black goes to black(hot), then green/yellow goes to the bare copper (ground). Now the tricky part is, you'll need a test meter to figure out if the yellow in the ceiling is the neutral which should go to the white. I would test between the yellow and the black in the ceiling (with the switch on) to see if there is 120V there. If there is problem solved, if not check between the red and yellow. I am guessing that either the red or the black will be the hot and the yellow will be the neutral. The one you do not use, I would cap off either by putting a wire nut on it or electrical tape.
Q:Some questions about EL wire?
Electroluminescent okorder.com) have wire that lasts far longer. You can expect the shelf life of these wires to be about 4-6 years. At that time, the wire just doesn't stop working, it slowly breaks down the phosphor particles, and the wire will get dimmer over time. The expected working life of EL Wire is about 4-6,000 hours which beats your average glow stick by about 5,992 hours...
Q:how do i hang/wire a chandelier?
There is a difference between the wires. One of the wires should have a ridge along its entire length. This is the neutral (white) wire. The neutral connects to the shells of the sockets and the hot wires to the center. once you peel the two wire apart you will see that one has little ridges that should be the neutral. the other way is to use a ohm or continuity meter.The center part of a light socket is the hot. neutral goes to white the other to black. good luck and i hope that this is a help to you
Q:Calculating thickness of wire?
The resistivity of copper is ρ_Cu = 1.72 x 10^(-8) ohm - meters, whereas that of aluminum is ρ_Al = 2.82 x 10^(-8) ohm-meters . Assuming that the wire runs are the same length L, the resistance in the aluminum wire will be R_Al = ρ_Al * L/A_Al, where A_Al is the cross-sectional area of the aluminum wire. The resistance in the copper wire will be R_Cu = ρ_Cu * L/A_Cu. If we want the same resistance in both wires, we require R_Cu = R_Al: ρ_Cu * L / A_Cu = ρ_Al * L / A_Al A_Al / A_Cu = ρ_Al / ρ_Cu. Since the resistivity ρ_Al of aluminum is higher, the aluminum wire must have a larger cross sectional area to yield the same resistance. To make this precise, suppose the wires are cylindrical. Then the cross sectional area is π(R_Al)² for the aluminum wire and π(ρ_Cu)² for the copper wire: π(R_Al)²/π(ρ_Cu)² = ρ_Al / ρ_Cu R_Al/R_Cu = √(ρ_Al / ρ_Cu) = √(2.82/1.72) = 1.28 The aluminum wire must be 28% thicker than the copper wire in order to provide the same resistance.
Q:wires, coils, AC generators?
Assuming the generator output voltage (RMS) remains constant the current will be less through the coil. By wrapping the wire into a coil it's resistance doesn't change but it's self inductance increases. AC in a wire produces an alternating (changing) magnetic field that is concentrated into a smaller space as a coil - so increasing it's strength and ability to link with the wire that produced it. When this changing magnetic field links (passes through) it's 'own' coils a self-induced 'back' EMF(voltage) is generated in the wire that opposes the 'forward' current from the generator (Lenz's law). If the geverator provides a pd = Vg and the back EMF = Vb, then the current in the coil is effectively being driven by a reduced pd = (Vg - Vb) .
Q:What is the fundamental frequency of the second wire?
Since the tension and size are different the two wire will have different wave speeds Since v= sqrt(T/mu) mu can be represented by density * area Since the second wire has twice the diameter it will have 4 times the mu and since Tension in wire 2 is twice that in wire 1 v2 = sqrt(2T/4mu) sqrt(.5)*v1 = 0.707*v1 Since f1 (wire 1) = v/2L1 then f2(wire 2) = v2/2L2 so replacing v2 and L2 yields 0.707v1/(2*2*L1) = 0.707/2(v1/2L) = 0.707/2 *f1 = 0.707/2*880Hz = 311Hz
Q:What causes signal Loss and Distortion in Copper Wire?
the resistance of the wire itself can be responsible for signal loss. electromagnetic fields may cause distortion. Another possibility is if the signal is not terminated properly you may experience a reflection of the signal traveling in opposition of the desired signal. Heat can cause loss or distortion. corrosion on the copper wire may also cause loss or distortion of the signal.