GI Binding Wire

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Product Description:

1.Material: high quality low carbon steel Q195

2. The wire diameter: from BWG35 - BWG6 (0.2mm - 5.0mm)

3. The general weight : 25kg/50kg/coil (or in according to your requirement 0.5kg- 200kg/roll)

4. The packing: plastic inside and hessian/woven outside (or in according to your requirement)

5.Tensile strength: 350---550N/mm2

6. Zinc coating: 10 - 30g/m2

7.Technical information: Processing with low carbon steel wire, throught drawing and galvanizing.

8.Characteristic&Applications: High zinc coating with super corrosion resistance, firmed and well-proportioned zinc Coating, slippery surface, used in construction, express way fencing, binding of flowers and wire mesh weaving.

                   electro galvanized iron wire

Wire Gauge

SWG(mm)

BWG(mm)

Wire Gauge

SWG(mm)

BWG(mm)

6

4.877

5.156

20

0.914

0.889

7

4.47

4.572

21

0.813

0.813

8

4.064

4.191

22

0.711

0.711

9

3.658

3.759

23

0.61

0.635

10

3.251

3.404

24

0.559

0.559

11

2.946

3.048

25

0.508

0.508

12

2.642

2.796

26

0.475

0.475

13

2.337

2.413

27

0.417

0.406

14

2.032

2.108

28

0.376

0.356

15

1.829

1.829

29

0.345

0.33

16

1.626

1.651

30

0.315

0.305

17

1.422

1.473

31

0.295

0.254

18

1.219

1.245

32

0.274

0.229

19

1.016

1.067

33

0.254

0.203

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Q:down to the wire?
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Q:Where can i find a 88 300zx stereo wiring diagram that lists all colors and what they go to?
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Q:Wire tension physics question?
Problem 1: If the tension in the two wires are equal, the angle they make with the horizontal must also be equal. Always remember that a horizontal line is a straight angle; hence, it has a measurement of 180°. Let's look for the angle the wires make with the horizontal. 130 + x + x = 180 130 + 2x = 180 2x = 180 - 130 2x = 50 (Divide both sides by 2) x = 25° Each wire makes a 25° angle with the horizontal. We can now find the tension. The mass must be divided by 2. Using trigonometry, let's find the tension force. The divided weight of the lamp shall be the opposite side, and the tension force shall be the hypotenuse. sin 25° = (200 / 2) / Ftens Ftens = 100 / sin 25° Ftens = 236.62 N (Answer) The tension is 236.62 N in each wire. Problem 2: We use the same approach. 100 + x + x = 180 100 + 2x = 180 2x = 180 - 100 2x = 80 (Divide both sides by 2) x = 40° Each wire makes a 40° angle with the horizontal. Calculate the tension force. sin 40° = (200 / 2) / Ftens Ftens = 100 / sin 40° Ftens = 155.57 N (Answer) The tension is 155.57 N in each wire. Hope this helps!
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ampere depends on the number of turns..........
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Hi does anyone knows where the stereo looms connect back to .i.e. fused?
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just reconnect like-colored wires back together
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HI Drive by wire In a drive by wire set up there no solid connection between the steering wheel and the front wheels. the steering is all done be electronics. on a regular car there is a shaft that goes from the steering wheel to the steering gear box, then tho the steering arms to the wheels. ON by wire the steering wheel moves switches and valves the turn the wheel by a pre set amount. Drive by brake this is done by using two brake pedals one for the left side and one for the right side.. when you step on the left brake it slows or stops the left side so the car well turn in that direction. that's how airplanes steer when on the ground they have a left and right brake hope this helps Tim

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