Direct Casting Aluminium Strip in Coils for Second Casting

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Loading Port:
Shanghai
Payment Terms:
TT OR LC
Min Order Qty:
80 m.t.
Supply Capability:
60000 m.t./month

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Item specifice:

Grade: 5000 Series Surface Treatment: Mill Finish Shape: Flat
Temper: O-H112 Application: Transportation Tools

Product Description:

1.Structure of Direct Casting Aluminium Strip in Coils for Second Casting


Direct Casting Aluminium Strip in Coils for Second Casting is one semi-finished aluminium material. This strip can be rolled down to aluminium coil,sheet,circle ect.  The alloy AA1050 is widly used in building, industry ect. Its weight is much lower than steel. So many customers choosed aluminium material instead of steel.


2. Main features of Direct Casting Aluminium Strip in Coils for Second Casting


a.Competitive price---We have our own mills and can produce mill finished aluminium coils, so we can control the production cost better.

b.Professional after-sale service---We have more than 15 years exportation experience and you need not worry about the exporation problems.

c.Fast delivery time---We can control the delivery time within 35 days.


3. Image of Direct Casting Aluminium Strip in Coils for Second Casting


Direct Casting Aluminium Strip in Coils for Second Casting

Direct Casting Aluminium Strip in Coils for Second Casting

Direct Casting Aluminium Strip in Coils for Second Casting



4. Product Specification of Direct Casting Aluminium Strip in Coils for Second Casting


ALLOYTEMPERTHICKNESSWIDTHFINAL THICKNESS
AA1050F3-8MM1200MM-2100MM0.2MM-3MM


5.FAQ:


What is the quality standard?

---Usually our standard is GB3880-2006

What is the largest width?

---It is 2300mm

What is the MOQ?

---Usually we can accept 80 tons.







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Q:Is aluminum a hard metal for a ring?
Aluminum is a quite soft metal, but so is gold. It is true that aluminum is light in weight but magnesium is even lighter and is common enough that a ring could be made of it. Metals can be made harder by adding small amounts of other metals or even by the way it is heat treated. .
Q:How to clean the engine oil and kerosene on the surface of aluminum sheet?
you can buy a bottle of petroleum ether in chemical raw material shop, it will be clean after rubbing, or you can buy solvent oil.
Q:connect copper to aluminum?
You need both anti-oxide paste, (follow directions), and spring type connectors to take care of the thermal creep.- A good electrical supply hose will have them. Give them the details and they'll advise you. (Last I heard, modern wirenuts are ' UL listed' for the application. Lack of the surface treatment is probaly the cause of your bad connection.) Aluminum wiring isn't bad by itself. It's the terminations that cause the problems. Bad advice Shabir - Screw connectors have no 'spring' to take up the thermal cycles of the aluminum and are exactly the WRONG thing to use for the problem in question.
Q:Could two pieces of aluminum sheets be welded together?
youcan use aluminium soldering,what do you want to weld?
Q:is copper wire really better than aluminum?
yes copper wire is better than almunium since coppe is very best conductor that that of almunium
Q:A copper-aluminum alloy has an aluminum concentration of (5.19x10^2) kg/m3.?
Densities: Aluminum: 2,710 kg/m^3 Copper: 8,940 kg/m^3 Basis: 1 m^3 of copper-aluminum alloy mass of aluminum in 1 m^3 alloy = 519 kg vol. of aluminum in the 1 m^3 alloy = 519 kg/(2710 kg/m^3) = 0.1915 m^3 vol. of copper in 1 m^3 alloy = 1 m^3 - 0.1915 m^3 = 0.8085 m^3 mass of copper in 1 m^3 alloy = (0.8085 m^3)*(8,940 kg/m^3) = 7,227.87 kg mass of the m^3 alloy = 7,227.87 kg + 519 kg = 7,746.87 kg %weight of aluminum = (519 kg/7,746.87 kg)*100% = 6.70% The alloy has 6.70% by weight of aluminum in it.
Q:Is plastic or aluminum more harmful?
I have read that some plastics have estrogen in them. Causing an excess in either sex can cause serious problem, men especially. Autopsy's of people who had Alzheimer's show aluminum in their brains. Life is definitely a challenge.
Q:The price of an atom of aluminum?
This can be done, as crazy as it sounds. Aluminum has a molar mass of 26.98g and the stated sample (the roll) is $2.96 for 0.995g You would divide 0.955 by 26.98. This gives you 0.0369, which is the amount of moles of aluminum in the roll. Then you need to use Avogadro's number. This is 6.02*10^23, and is the amount of particles in a mole. Avogadro's number multiplied by 0.0369 gives you 2.22138*10^22. This is the amount of aluminum atoms in the roll. Now, you divide the price ($2.96) by the amount of aluminum atoms (2.22138*10^22) to get the price per atom. Price per atom of aluminum in the stated sample: $1.332505*10^-22 (This is equivalent to .$0.0000000000000000000001332505) I hope this helps.
Q:Can you paint aluminum foil using acrylic paints?
i use aluminum foil to mix colors on and when it dries it DOES stick, however, it will scratch off really easy. just try experimenting. what do u need the foil for? maybe you can try the aluminum foil leaves? the flakes that you put ontop on the art instead of under it. that way you can glue it on and dont have to worry about it scratching off. foil looks beautiful on paintings :) how it turns out great
Q:What masses of iron(III) oxide and aluminum must be used to produce 10.0 g iron?
I'm going to show my calculations anyways Fe2O3(s) + 2 Al(s) -- 2 Fe (l) + Al2O3 (s) From the equation : 1 mole of iron (III) oxide 2 moles of aluminium -- 2 moles of iron 1 mole of aluminium oxide Given that iron = 10.0 g = 10.0 g / 55.8 g per mole = 0.179 mol of iron (corr to 3 sig fig) Because the mole ratio of iron to iron (III) oxide is 2 : 1 Therefore moles of iron (III) oxide produced = 0.179 / 2 = 0.0895 mol Convert it back to grams 0.0895 x (55.8 x 2 + 16.0 x 3) = 14.3 grams (corr to 3 sig fig)' a) 14.3 grams of iron (III) oxide must be used ----- Given that iron = ...... (previously calculated) ...... = 0.179 mol of iron (corr to 3 sig fig) Because the mole ratio of iron to aluminium is 1 : 1 Therefore moles of aluminium produced = 0.179 mol Convert it back to grams 0.179 x 27.0 = 4.83 grams (corr to 3 sig fig) b) 4.83 grams of aluminium must be used ----- Given that iron = 0.179 mol Because the mole ratio of iron to aluminium oxide is 2 : 1 Therefore moles of Al2O3 produced = 0.179 / 2 = 0.0895 mol Convert it back to grams 0.0895 x (27.0 x 2 + 16.0 x 3) = 9.13 grams (corr to 3 sig fig) c) 9.13 grams of aluminium oxide is the maximum mass that could be produced P.S. The relative molecular masses used are from my textbook

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