Diamond aluminium sheet

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Aluminium Checkered Sheet
Alloy: 1000 series,3000series,5000series,6000series.













0.8MM-10MM900MM-1600MMLighting,construction,printing,packing,decorative,electronics surface...

Technical Specifications

  1. Thickness: 0.8-10mm

  2. Width: 900-1600mm

  3. Length: 800-8000mm

  4. Material (alloy): 1100, 1050, 3003, 3103, 5052, 5754, 5083, 6061, 6082

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Q:Explain these statements about Aluminium.?
a) true b) false
Q:Is Aluminum really stronger than steel?
NO! You should ask yourself why Tank built with steel rather than using aluminum.
Q:how do i get read of condensation behind aluminum siding?
Aluminum siding can be vented with round pop-in perforated vent plugs, these are very easy to install. I would really like to know how do you know there is condensation behind your siding?
Q:Aluminum coil Kaiping is out of arc plate, what's the matter?
Aluminum coil Kaiping need to use "stretch bending straightening machine" to do leveling, before they can be leveled
Q:1mm how much is one square meter for aluminum rolls?
The price of aluminum sheet is calculated according to the price of aluminum ingot + processing fee (aluminum plate state), and the specific price is also different according to the size and size of aluminum sheet.
Q:What volume of oxygen measured at 25oC and 0.975 atm is required to completely oxidize 3.42 g of aluminum to a?
First write out the formula reaction: 4Al + 3O2 --- 2Al2O3 Next, find the number of moles of oxygen gas needed to oxidize 3.42 g of aluminium completely. From the cchemical equation above, 3 mol of oxygen is used to oxidize completely 4 mol of aluminium. Calculate the no. of moles of aluminium used: no. of moles of aluminium used = 3.42 g / molar mass of Al = 3.42 g / 26.98 g mol^-1 = 0.127 mol Use the mole ratio concept to find the no. of moles of oxygen required: no. of moles of oxygen required : no. of moles of aluminium used = 3 : 4 no. of moles of oxygen required / 0.127 = 3 / 4 no. of moles of oxygen required = (3 / 4)(0.127) = 0.095 mol Next, use the gas equation PV = nRT [P: Pressure of gas in Pa; V: Volume of gas in m^3; n: no. of moles; R, gas constant, 8.314 J mol^-1 K^-1; T, Temperature of gas in K] -Convert 0.975 atm to Pa: 0.975 atm = (0.975 x 101325) Pa = 98791.875 Pa -Convert 25 oC to K: 25 oC = (25 + 273) K = 298 K -Substitute into the equation PV = nRT and solve it: (98791.875)(V) = (0.095)(8.31)(298) (98791.875)(V) = 235.2561 V = 235.2561 / 98791.875 = 0.002381 m^3 = (0.002381 x 10^3) L = 2.381 L
Q:Chem Help: Ionization energies for aluminum?
aluminum forms an ion by loosing electrons. once an electron is lost, the nucleus attains net positive charge. as a result, the remaining electrons are strongly held by nuclea force of attraction, hence more energy is required to remove them.
Q:a sample of aluminum chloride has a mass of 37.2 g. how many aluminum ions are present?
Aluminum Chloride is simply AlCl3 So In each mole of AlCl3 there are 1 mol of Al 3 mol of Cl We know (from periodic table), 1 mol of Al weighs 26.98 g 1 mol of Cl weighs 35.47g so 1 mol of AlCl3 weighs 26.98g + 3x35.47g = 133.39 g sooo moles of AlCl3 = 37.2 g /133.39 g/mol = 0.279 mol in one mol of anything, there are 6.02 x 10 ^ 23 of that thing... so we have 0.279 mol x 6.02 x 10 ^ 23 molecules /mole = 1.68 x 10 ^ 23 And, we know one molecule of AlCl3 dissociates into one Al ion and 3 Cl ions sooo 1.68 x 10 ^ 23 AlCl3 ions dissociate into 1.68 x 10 ^ 23 Al ions so answer is 1.68 x 10 ^ 23 Al ions
Q:It is harmful for a budgie to take a bath in a aluminum pie tin?
Aluminum cookware/products that are in good condition aren't really a safety issue. That said, I'd be concerned about the birds chewing on the pie tin. Some of those tins can contain zinc which is very toxic to birds. I would suggest using something else just in case.
Q:What is the balanced equation for copper (I) oxide and Aluminum?
Copper(I) oxide is a solid and so is aluminum. Any reaction that might occur would have to be at an elevated temperature. This is a thermite reaction in which copper(I) is reduced to copper metal (molten) and aluminum is oxidized to aluminum oxide. 3Cu2O(s) + 2Al(s) -- 6Cu(s) + Al2O3(s) ========= Follow up ========== Do you mean in aqueous solution? There won't be any copper(I) chloride in aqueous solution. CuCl is very insoluble in water, but will undergo disproportionation to form Cu2+ ions and copper metal. Therefore, you would actually have a solution of copper(II) chloride. Copper(II) chloride will react with aluminum to form copper metal and aluminum ions. Ordinarily aluminum won't react with copper(II) ions. The reaction does proceed in the presence of chloride ion. This is because the chloride ion will react with the Al2O3 layer on the surface of aluminum metal to make [AlCl4]^- which exposes the aluminum metal below, and thus a reaction can occur. 3Cu2+ + 2Al(s) -- 2Al3+ + 3Cu(s)

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