Cyanuric Acid 98.5% Granular High Quality

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Product Description:

                                                                     Cyanuric Acid

Structure of Cyanuric Aicd Descriptions:

Trade Name: Isocyanuric Acid

Other name: Cyanuric Acid; 1,3,5-Triazine-2,4,6-triol

Uses: Bleaches and sanitisers.

Formula: C3H3N3O3

Molecular Weight: 129.07

CAS NO.: 108-80-7

Main Feautrues of Cyanuric Acid

White powder, granular or colored tablet form, non-toxic and odorless

Cyanuric Acid Image:

Cyanuric Acid 98.5% Granular  High Quality

Cyanuric Acid Specification:

PH value4.0-4.54.26
Insoluble matter in DMF0.3%0.25%
AppearanceWhite crystalline powerWhite crystalline power
Mesh number95% pass 80 mesh95% pass 80 mesh
White degree8990.5
Conclusion:The product complies with the standard above.


in 25kg, 1000kg bag for powder

in 25kg plastic bag or 50kg PE drums for granular

Cyanuric Acid 98.5% Granular  High Quality

Cyanuric Acid 98.5% Granular  High Quality

Cyanuric Acid 98.5% Granular  High Quality


kept in a light-proof,well-colsed,dry and cool place.

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Q:can you guys help me by listing all the catalysts?
copper nickel zinc common catalysts are solid acids such as the silicas, alumina, and zeolites it depends on the reaction
Q:Co and No form a chemical equation for Co2 and No2 under the action of a catalyst
Write the catalyst on the horizontal line, where NO is the oxidant and CO is the reducing agent
Q:What reactions need catalysts?
Reactions that have high Activation Energy need catalysts to speed up reactions. These reactions aren't spontaneous since the reactants do not have enough energy to overcome the activation energy barrier. Catalysts are compounds that speed up reactions by providing an alternative pathway for the reaction. It is a common misconception that catalysts lower the activation energy. It doesn't actually lower the activation energy, instead it provides an alternative pathway with lower activation energy. For example, breakdown of hydrogen peroxide happens in nature but, relatively slowly. When you add a little bit of manganese dioxide, the breakdown happens a lot faster. Another example is, breakdown of glucose in the body. It is facilitated by an enzyme called amylase (or carbohydrase). An industrial example is the use of vanadium pentoxide (V2O5) in the Contact process, where SO2 is converted to SO3 in the presence of V2O5. Hope that helps!
Q:What is the difference between an enzyme catalyst in a living body and a catalyst in chemistry?
(Such as: high temperature, high pressure, strong acid, alkali, etc.), but the enzyme catalyzed reaction (enzymatic reaction) is generally at room temperature, atmospheric pressure (normal reaction), the reaction temperature of the chemical reaction, , Neutral pH, etc. under mild reaction conditions.
Q:Catalyst and Intermediate.?
Cl is the catalyst. ClO the intermediate. The catalyst is the component which does not change in overall reaction. He forms some intermediate component(s) with the reactants. In the later reaction steps the intermediate(s) react forming the catalyst in its original state. (a) The overall order is the sum of the orders with respect to the components: n = 1 +1 = 2 (b) the unit of the rate of reaction is r [=] mol/ (Ls) (more general mol per unit time and volume) compare dimensions mol / (Ls) [=] k · mo/L · mol/L =k [=] L/(s mol) (more general unit volume per unit time and mole) (c) First reaction For elementary reaction steps the order of the reaction rate with respect to a reactant is equal to stoichiometric coefficient. Hence the rate of first reaction is: r₁ = k₁·[Cl]·[O₃] Overall rate is given by the rate determining step, while other reaction steps are in equilibrium: r = r₁ = k₁·[Cl]·[O₃] If second reaction is the rate determine step r₂ = k₂·[O]·[ClO] while reaction 1 is at equilibrium K₁ = ( [ClO]·[O₂] ) / ( [Cl]·[O₃] ) =[ClO] = K₁·( [Cl]·[O₃] ) / [O₂] the overall rate would be: r = r₂ = k₂·[O]·[ClO] = K₁·k₂·[O]·[Cl]·[O₃] / [O₂] = k·[O]·[Cl]·[O₃] / [O₂] That doesn't match the observed rate law
Q:What happens to this catalyst ?
If it is only a catalyst, then by definition it will still be there at the end.
Q:Nitrogen and hydrogen in the role of high temperature and pressure catalyst to generate ammonia chemical equation
N2 + 3H2 = catalyst, high temperature and high pressure = 2NH3
Q:Can a catalyst be present in the rate equation?
Yes, a catalyst can be included in a rate law. That's because, most reactions occur in a series of step and the rate is based on the rate determining step, which is the slowest step. A catalyst may be a reactant in the rate determining step, and a product in a subsequent step. Therefore, the catalyst is not included in the overall reaction. But a catalyst need not always be in the rate law. The rate law is usually based on the rate determining step. ========== Follow up =========== In the free response questions on the AP chemistry exam there has been at least one case where a rate law included a catalyst( 2002D). Brown and LeMay always include at least one in their examples, and I always cover this situation when I teach rate laws and mechanisms in AP chemistry. Here is one comment: Other examples of species not in the balanced reaction occurring in the rate law would include catalysis, where a catalyst does not normally appear in the balanced reaction but does appear in the rate law. Consider this generalized reaction which is catalyzed by M A + B --C A + M --Q ... slow Q + B --C ... fast M is the catalyst, and Q is the intermediate. The slow, or rate determining step, depends only on the concentrations of A and M, the catalyst. So even though the overall reaction does not include, M, the rate law does. Rate = k[A][M]
Q:The catalyst can change the chemical reaction process, why is it wrong?
No, only for the length of time
Q:What is the maximum impact of the chemical reaction rate?
But the temperature is greater than the concentration of concentration and pressure on the solid and pure liquid is not affected

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