Q:A real inductor can be modeled as an ideal inductor in series with an internal resistance as illustrated in the figure above.A time-varying current I is passed through a real inductor. At a time when I +4 A and dI/dt +14 A/s, the voltage drop across the inductor is observed to be Va - Vb +185 V. At another time when I +4 A and dI/dt -14 A/s, the observed voltage drop is V'a- V'b +43 V.

Ldi/dt +4i Vab, L(14) + R(4) 185 L(-14) + R(4) 43 System of linear eqns, add together; 8R 228, R 28.5 ohm

Q:whats the diffrence between a inductor with a medal and a normal inductor?

There isn't really a difference, just an enhancement in design by including the ferromagnetic core for an inductor. An empty inductor is just a coil of wire. A ferromangetic material core inductor is a coil of wire filled with a ferromagnetic material like iron as a method to get more inductance with less wire. And there is an annoying non-ideal phenomena called magnetic hysteresis in a ferromagnetic core incuctor. This only occurs when the current is high enough to saturate the ferromagnetic material's ability to enhance magnetism.

Q:A series RLC circuit is connected across a 10kHz source. The 1.2 H inductor and 1000 ohm resistor are fixed and the capacitor is variable. At what capacitance will the current in the resistor be a maximum?

At resonance the inductor and capacitor will be a short. C1/w^2 L where w2 pi f.

Q:if the frequency is 60 Hz.

Ohm's law tells you that V I*R, which translates to V I*Z in an AC network, where Z is impedance. We want to know the current I, which we can express as I V/Z. We know the voltage is 110V AC, so to find the current we should find the impedance and calculate it that way. Inductors have an impedance of Z L*w, where w is the frequency in radians per second. 60 Hz means you have 60 complete oscillations (cycles) per second, which is equal to 2*pi*60Hz 376.9 radians per second. Since the L of our inductor is 0.9H, our impedance must be Z 0.9H*376.9rad/s 339.23ohms of impedance. Now that we know the impedance, we calculate the current. I 110VAC/339.23ohms 324.27mA AC.

Q:if electric field is zero then how current passes through an inductor?

the inductor is a coil of metal The E field inside is zero because it acts like a faraday shield. Within the metal if its a pure inductor there is no resistance. (copper losses zero) so a finite current is driven by a zero E field. (OK thats hard to comprehend, but only because a PURE lossless inductor is imposible)

Q:5.00 H. Find the current through the resistor, inductor, and the total current in the circuit.

Actually you should specify the resistance of the 5 H inductor, but in this case X(L)R so the impedance can be estimated as the inductive reactance, where 5 H @ 60hz by X(L)2piFL6.28*60*5 1884 ohms. Resistor current equals 117/1000 .117 A. Inductor current 117/1884 .062A

Q:Hello, i need some help solving. please show all steps. thanks so much for your assistance.A 3.5-mH inductor and a 4.5-mH inductor are connected in series and a time varying current is established in them. When the total emf of the combination is 16V, the emf of the larger inductor is: A) 7.0 V B) 9.0 V C) 2.3 VD) 28 VE) 36 V

A. When they are in series, this is just a voltage divider question. The answer is B because 16 I*[Z1+Z2] I*[jw7/2+jw9/2] I 16/jw8 2/jw mA where w omega 2pi times frequency and j sqrt[-1] The voltage across the larger inductor is then I*jw[9/2] [2/jw]*jw[9/2] 9V B. The answer is B because: The voltage across an inductor is L*di/dt Both inductors have the same voltage since they are in parallel 16V L 4.5e-3 16 4.5e-3* di/dt di/dt 16*10^3/4.5 3.6x10^3 A/s

Q:(a) If an inductor carrying a 1.60 A current stores an energy of 0.250 mJ, what is its inductance?(b) How much energy does the same inductor store if it carries a 2.9 A current?

W0.5Li^2 whence 2W/i^2 L L 2 *.25 / 1.6^2.

Q:A student wants to figure out if an unlabeled item is a capacitor or inductor. He applies a voltage with diferent frequencies and find that as the frequency goes up, the current through the item goes down. Is this a capcitor or an inductor? Why? Thanks for the help! Please explain in detail.

inductor. Inductive reactance is proportional to frequency, so it goes up as frequency goes up. Since Current is inversely proportional to reactance, as frequency goes up, current goes down. A cap would be the opposite. .

Q:A .5-H inductor is connected into a 110 V-rms 60-Hz voltage source, with an ammeter in series. What is the rms value of the current through the inductor?I can not figure this last problem out. Please help, thanks!

I v/Z Z Xl in this case as r0 Xl 2 Pi f L 2 * 3.14 * 60 * 5 I 110 / (2 * 3.14 * 60 * 5) 0.058 A